Problem 83
Question
Insert either \(<,>,\) or \(=\) in the shaded area to make a true statement. $$\frac{30}{40}-\frac{3}{4} \quad \square\quad\frac{14}{15} \cdot \frac{15}{14}$$
Step-by-Step Solution
Verified Answer
The correct symbol to insert is \( < \)
1Step 1: Simplify the First Expression
The given expression is subtracting two fractions, \(30/40\) - \(3/4\). We can simplify both fractions. \(30/40\) simplifies to \(3/4\), therefore the whole expression simplifies to \(3/4 - 3/4\), which equals 0.
2Step 2: Simplify the Second Expression
The other expression is multiplying two fractions, \(14/15\) * \(15/14\). Numbers in the numerator of the first fraction match the numbers in the denominator of the second fraction. They cancel each other out when multiplication is performed giving a result of 1.
3Step 3: Insert the Correct Comparison Symbol
Now, comparing the values, we have 0 and 1. 0 is less than 1, therefore the correct symbol to insert is \(<\)
Key Concepts
Simplifying FractionsFraction SubtractionFraction Multiplication
Simplifying Fractions
Simplifying fractions is like tidying up your room. You want to make things as neat as possible. When we simplify a fraction, we make it as simple as it can get without changing its value.
For example, look at the fraction \( \frac{30}{40} \). Both the numerator and the denominator have a common factor, which is 10. So, when we divide both the top and bottom by 10, we simplify \( \frac{30}{40} \) to \( \frac{3}{4} \).
This process is crucial because it makes comparing and working with fractions easier. Remember, always look for the greatest common factor between the numerator and the denominator to simplify efficiently.
For example, look at the fraction \( \frac{30}{40} \). Both the numerator and the denominator have a common factor, which is 10. So, when we divide both the top and bottom by 10, we simplify \( \frac{30}{40} \) to \( \frac{3}{4} \).
This process is crucial because it makes comparing and working with fractions easier. Remember, always look for the greatest common factor between the numerator and the denominator to simplify efficiently.
- Find the greatest common factor (GCF)
- Divide both the numerator and the denominator by the GCF
- Rewrite the fraction in simplest form
Fraction Subtraction
Subtracting fractions can be trickier than adding them. Especially when the denominators are different. Fortunately, when the denominators are the same, like with \( \frac{3}{4} - \frac{3}{4} \), the process becomes simple.
First, always ensure the fractions have the same denominator. If not, you'll need to find a common denominator before you can subtract. Once they are the same, you subtract the numerators only and keep the denominator the same.
In our exercise, the fractions \( \frac{3}{4} - \frac{3}{4} \) already have the same denominator. So you simply subtract the top numbers to get:\[\frac{3-3}{4} = \frac{0}{4} = 0\]
First, always ensure the fractions have the same denominator. If not, you'll need to find a common denominator before you can subtract. Once they are the same, you subtract the numerators only and keep the denominator the same.
In our exercise, the fractions \( \frac{3}{4} - \frac{3}{4} \) already have the same denominator. So you simply subtract the top numbers to get:\[\frac{3-3}{4} = \frac{0}{4} = 0\]
- Ensure denominators are the same
- Subtract the numerators
- Simplify the result if needed
Fraction Multiplication
Multiplying fractions is a bit like playing a matching game. You simply multiply the numbers across the top, and the numbers across the bottom. However, you can also simplify as you multiply, which can save you some work later.
Consider multiplying \( \frac{14}{15} \cdot \frac{15}{14} \). Notice that 14 appears once in the numerator and once in the denominator, as does 15. We can "cancel" these like terms beforehand. This makes the multiplication quite straightforward:
After canceling, you are left with \( \frac{1}{1} \), which equals 1.
Here’s a step-by-step approach to remember:
Consider multiplying \( \frac{14}{15} \cdot \frac{15}{14} \). Notice that 14 appears once in the numerator and once in the denominator, as does 15. We can "cancel" these like terms beforehand. This makes the multiplication quite straightforward:
After canceling, you are left with \( \frac{1}{1} \), which equals 1.
Here’s a step-by-step approach to remember:
- Multiply the numerators together
- Multiply the denominators together
- Cancel terms that appear in both the numerator and the denominator before multiplying
- Simplify the result
Other exercises in this chapter
Problem 83
In Exercises \(77-96,\) simplify each algebraic expression. $$-5 x+x$$
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State an associative property and give an example.
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Simplify each algebraic expression. \(-5 x-10 y-3 x+13 y\)
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Perform the indicated operation. Where possible, reduce the answer to its lowest terms. $$\frac{11}{18}-\frac{2}{9}$$
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