Problem 83
Question
Insert either \(<,>,\) or \(=\) in the shaded area to make a true statement. $$\frac{30}{40}-\frac{3}{4} \square \frac{14}{15} \cdot \frac{15}{14}$$
Step-by-Step Solution
Verified Answer
The inequality symbol that makes the statement true is \(<\). Hence, the solution for \(\frac{30}{40} - \frac{3}{4} \square \frac{14}{15} \cdot \frac{15}{14}\) is \(\frac{30}{40} - \frac{3}{4} < \frac{14}{15} \cdot \frac{15}{14}\).
1Step 1: Calculate the given fractions
First, we simplify the fractions on both sides of the shaded square. We have \(\frac{30}{40} - \frac{3}{4}\) on one side, and \(\frac{14}{15} \cdot \frac{15}{14}\) on the other side. The fraction \(\frac{30}{40}\) simplifies to \(\frac{3}{4}\), so the left side becomes \(\frac{3}{4} - \frac{3}{4}\). The fraction \(\frac{14}{15} \cdot \frac{15}{14}\) simplifies to 1.
2Step 2: Subtract fractions
Next, we perform subtraction on the left side. It gives us \(\frac{3}{4} - \frac{3}{4} = 0\).
3Step 3: Compare the fractions
Now we compare 0 and 1 using an inequality or equality sign. Since 0 is less than 1, we insert \(<\) in the shaded area to enforce a true statement.
4Step 4: Re-check the result
Finally, we ensure our solution is correct. This can be done by replacing the shaded square in the original statement with the derived sign and check that the overall statement is true. For this case, the final check ensures that indeed 0 is less than 1.
Other exercises in this chapter
Problem 82
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In Exercises \(81-88,\) simplify each algebraic expression by removing parentheses and brackets. $$3[6-(y+1)]$$
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Simplify each algebraic expression. $$-5 x+x$$
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