Problem 83
Question
In Exercises \(77-84,\) evaluate each expression without using a calculator. $$32^{-4 / 5}$$
Step-by-Step Solution
Verified Answer
The value of \(32^{-4 / 5}\) is \(1/16\).
1Step 1: Rewrite the Expression With Negative Exponent
The first step is to rewrite the expression using the rule \(a^{-m} = 1/a^m\). So, \(32^{-4 / 5}\) can be written as \(1/32^{4 / 5}\).
2Step 2: Simplify the Expression with Fractional Exponent
Next, observe that the expression in the denominator is in the form \(a^{m/n}\), which can be written as the \(n\)th root of \(a^m\). Therefore, \(32^{4 / 5}\) can be written as the 5th root of \(32^4\). Now, 32 can be written as 2 to the power of 5, so the expression becomes the 5th root of \((2^5)^4\) which simplifies to the 5th root of \(2^{20}\). The 5th root of \(2^{20}\) is \(2^{20/5}\) = \(2^4\) = 16
3Step 3: Write the Final Answer
Given that the original expression was the reciprocal of \(32^{4 / 5}\), take the reciprocal of 16. So, \(32^{-4 / 5}\) = \(1/16\).
Key Concepts
Negative ExponentsFractional ExponentsRoots and PowersSimplifying Expressions
Negative Exponents
Negative exponents might seem intimidating at first, but once you understand the basic concept, they become much simpler to handle. When you see an expression like \(a^{-m}\), it tells you to take the reciprocal of \(a^m\). Essentially, any non-zero number raised to a negative exponent is equal to one divided by that number raised to the corresponding positive exponent. For example:
- \(a^{-3} = \frac{1}{a^3}\)
- \(5^{-2} = \frac{1}{5^2} = \frac{1}{25}\)
Fractional Exponents
Fractional exponents are another way to express roots and powers combined. They are written in the form \(a^{m/n}\), where:
- \(m\) is the power to which the base \(a\) is raised
- \(n\) is the root we are taking
Roots and Powers
Understanding how roots and powers work together is key to simplifying expressions effectively. When we deal with roots, we are essentially asking what number, when raised to a certain power, gives us the original number. Meanwhile, powers indicate how many times we multiply the base by itself. For example, the 5th root of a number \(a\), denoted as \(\sqrt[5]{a}\), asks for a number which multiplied by itself 5 times results in \(a\).
In our example of \(32^{4/5}\), seeing the base 32 as \(2^5\) makes it easier to handle the root and power:
In our example of \(32^{4/5}\), seeing the base 32 as \(2^5\) makes it easier to handle the root and power:
- The power 4 remains with the base after simplifying the root.
- It results in \(2^4\) since \(\sqrt[5]{2^{20}} = 2^4\).
Simplifying Expressions
Simplifying expressions is about rewriting them in a form that is easier to understand or calculate. The process involves using a combination of algebraic rules, such as dealing with exponents, roots, and simplifying fractions. In our example:
- We first use the negative exponent rule to find the reciprocal of \(32^{4/5}\).
- Then, change the fractional exponent into a root and power expression to make calculations easier.
- Finally, simplify the expression to its lowest terms.
- Convert the negative exponent to \(\frac{1}{32^{4/5}}\).
- Simplify \(32^{4/5}\) to \(2^4\).
- The final simplified expression is \(\frac{1}{16}\).
Other exercises in this chapter
Problem 82
Writing about mathematics will help you learn mathematics For all writing exercises in this book, use complete sentences to respond to the question. Some writin
View solution Problem 83
Find each product. $$\left(3 x y^{2}-4 y\right)\left(3 x y^{2}+4 y\right)$$
View solution Problem 83
How much are your monthly payments on a loan? If \(P\) is the principal, or amount borrowed, \(i\) is the monthly interest rate, and \(n\) is the number of mont
View solution Problem 83
In Exercises \(57-84\), factor completely, or state that the polynomial is prime. $$2 x^{3}-8 a^{2} x+24 x^{2}+72 x$$
View solution