Problem 83
Question
Evaluate each expression. \(_{6} \mathrm{C}_{5}\)
Step-by-Step Solution
Verified Answer
The result of the given combination problem, _6C5, is 6.
1Step 1: Find Values
In our given expression _6C5, n represents the total number of items which is 6 and r represents the number of items to select, which is 5.
2Step 2: Factorial Calculation
Before we substitute the values into the combination formula, let's calculate the factorials: 6! = 6 * 5 * 4 * 3 * 2 * 1 = 720, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 1! which is simply 1.
3Step 3: Substitute Values into Formula
Place the calculated factorials into the combination formula: _6C5 = \(\frac{6!}{((6-5)!)(5!)}\). After substitution, we get: _6C5 = \(\frac{720}{1 * 120}\).
4Step 4: Calculate the Result
Performing the calculation, we finally get: _6C5 = 6.
Key Concepts
FactorialsPermutation and CombinationMathematical Expressions
Factorials
Factorials are fundamental in the study of permutations and combinations. They are used to express the product of a sequence of descending natural numbers. The factorial of a number is denoted by the symbol '!', so for a positive integer n, the factorial is defined as \[ n! = n \times (n-1) \times (n-2) \times \, ... \, \times 2 \times 1 \]Factorials dramatically increase as the number grows because you multiply the number by every positive integer below it.
- For example, the factorial of 3 (written as 3!) is: \[ 3! = 3 \times 2 \times 1 = 6 \]
- Similarly, 5! is 120 because: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]
Permutation and Combination
Permutation and combination are two different ways to count arrangements of a set of items. Permutations focus on the arrangement of items where the order matters, while combinations focus on the selection of items where order does not matter.
- Permutation: When you need to find out how many ways you can arrange a set of items, use permutations. For instance, arranging 3 books on a shelf considers permutations. \[ nPr = \frac{n!}{(n-r)!} \]
- Combination: When the order of selection doesn’t matter, use combinations. The formula for combinations is: \[ nCr = \frac{n!}{r!(n-r)!} \]
Mathematical Expressions
Mathematical expressions are statements combined using numbers, variables, operation symbols, and groups of those symbols representing a specific value.Expressions are essential tools in conveying mathematical ideas and are central to mathematical analysis.Mathematical expressions are often solved using a series of steps:
- Identify known quantities (e.g., numbers or defined variables)
- Apply arithmetic operations as per mathematical rules (e.g., order of operations/BODMAS)
- Use well-known formulas (e.g., combination formula, factorial formula)
Other exercises in this chapter
Problem 83
Rationalize the denominator of each expression. Assume that all variables are positive. \(\frac{\sqrt{36 x^{3}}}{\sqrt{12 x}}\)
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Find each indicated root if it is a real number. $$ \sqrt[5]{243} $$
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Find each composition of functions. Simplify your answer. Let \(f(x)=2 x-3 .\) Find \(\frac{f(1+h)-f(1)}{h}, h \neq 0\)
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Simplify each radical expression. Use absolute value symbols as needed. $$ \sqrt{0.0064 x^{40}} $$
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