Problem 83
Question
Determine the domain and range of the quadratic function. \(k(x)=3 x^{2}-6 x-9\)
Step-by-Step Solution
Verified Answer
The domain is all real numbers and the range is
\( [-12, \infty) \).
1Step 1: Identify the Type of Function
The function given is a quadratic function, which generally has the form \( f(x) = ax^2 + bx + c \). Here, \( a = 3 \), \( b = -6 \), and \( c = -9 \). This tells us we are working with a parabola.
2Step 2: Determine the Domain
The domain of a quadratic function is all real numbers, \( \mathbb{R} \), because you can plug any real number into the equation and obtain a real output.
3Step 3: Determine the Vertex of the Parabola
To find the range, first calculate the vertex of the parabola because the vertex form of a quadratic will guide us to the minimum or maximum value. The x-coordinate of the vertex can be calculated using \( x = -\frac{b}{2a} \). Here \( x = -\frac{-6}{2\times3} = 1 \).
4Step 4: Calculate the y-coordinate of the Vertex
Substitute \( x = 1 \) back into the function to find the y-coordinate of the vertex. \( k(1) = 3(1)^2 - 6(1) - 9 = 3 - 6 - 9 = -12 \). The vertex of the parabola is \( (1, -12) \).
5Step 5: Analyze the Parabola's Orientation
Since the coefficient \( a = 3 \) is positive, the parabola opens upwards. This means the vertex represents the minimum point of the function.
6Step 6: Determine the Range
With the parabola opening upwards and the vertex being the minimum point, the range of the function is all real numbers greater than or equal to -12. Thus, the range is \( [-12, \infty) \).
Key Concepts
Quadratic FunctionVertex of a ParabolaFunction DomainFunction Range
Quadratic Function
A quadratic function is a type of polynomial that has the form:
The leading coefficient \( a \), determines whether the parabola opens upward or downward:
In the given function, \( k(x) = 3x^{2} - 6x - 9 \), we identify a quadratic function with the coefficients: \( a = 3 \), \( b = -6 \), and \( c = -9 \).
This indicates that our parabola will open upwards, given that \( a \) is positive.
- \( f(x) = ax^2 + bx + c \)
The leading coefficient \( a \), determines whether the parabola opens upward or downward:
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), the parabola opens downwards.
In the given function, \( k(x) = 3x^{2} - 6x - 9 \), we identify a quadratic function with the coefficients: \( a = 3 \), \( b = -6 \), and \( c = -9 \).
This indicates that our parabola will open upwards, given that \( a \) is positive.
Vertex of a Parabola
The vertex of a parabola is a key point that represents the maximum or minimum of the function. This point helps determine the parabola’s range.
The vertex is found using a formula for the x-coordinate:
The parabola opens upwards, so this vertex represents the lowest point in the function's range.
The vertex is found using a formula for the x-coordinate:
- \( x = -\frac{b}{2a} \)
- \( x = -\frac{-6}{2 \times 3} = 1 \)
- \( k(1) = 3(1)^2 - 6(1) - 9 = -12 \)
The parabola opens upwards, so this vertex represents the lowest point in the function's range.
Function Domain
The domain of a function is the set of all possible input values (x-values) that the function can accept. For quadratic functions,
In other words, the domain of our quadratic function is:
- the domain is typically all real numbers
In other words, the domain of our quadratic function is:
- \( (-\infty, \infty) \)
Function Range
The range of a function describes the set of possible output values (y-values). For a quadratic function like \( k(x) = 3x^{2} - 6x - 9 \), the range depends on the direction in which the parabola opens and its vertex point.
Since the parabola opens upwards and has a vertex of \( (1, -12) \), it indicates that the function's minimum output value is \( -12 \) and increases thereafter.
Thus, the range for this quadratic function is:
This means the function's outputs can cover an entire half-plane of y-values above \( -12 \).
Since the parabola opens upwards and has a vertex of \( (1, -12) \), it indicates that the function's minimum output value is \( -12 \) and increases thereafter.
Thus, the range for this quadratic function is:
- \( [-12, \infty) \)
This means the function's outputs can cover an entire half-plane of y-values above \( -12 \).
Other exercises in this chapter
Problem 81
Determine the domain and range of the quadratic function. \(f(x)=x^{2}+6 x+4\)
View solution Problem 82
Determine the domain and range of the quadratic function. \(f(x)=2 x^{2}-4 x+2\)
View solution Problem 84
Solve the equations over the complex numbers. \(x^{2}=-25\)
View solution Problem 85
Solve the equations over the complex numbers. \(x^{2}=-8\)
View solution