Problem 83
Question
Define a \(p\) -series and state the requirements for its convergence.
Step-by-Step Solution
Verified Answer
A \(p\)-series is defined as the series \(\sum_{n=1}^{\infty} \frac{1}{n^p}\), for \(n\) a natural number and \(p\) a real number. The series is convergent if \(p > 1\), and divergent if \(p \leq 1\).
1Step 1: Define a \(p\)-series
A \(p\)-series can be defined as the series of the form \(\sum_{n=1}^{\infty} \frac{1}{n^p}\), where \(n\) is a natural number and \(p\) is a real number. This series derives its name from the power \(p\) of \(n\) in the denominator.
2Step 2: State the requirements for its convergence
The \(p\)-series \(\sum_{n=1}^{\infty} \frac{1}{n^p}\) is convergent if \(p > 1\) and divergent if \(p \leq 1\). This is a conclusion derived from the p-series test (part of the integral test for convergence), a fundamental concept in the study of calculus and analysis.
Other exercises in this chapter
Problem 83
(a) You delete a finite number of terms from a divergent series. Will the new series still diverge? Explain your reasoning. (b) You add a finite number of terms
View solution Problem 83
Give an example of a sequence satisfying the condition or explain why no such sequence exists. (Examples are not unique.) A sequence that converges to \(\frac{3
View solution Problem 83
Determine the convergence or divergence of the series using any appropriate test from this chapter. Identify the test used. $$ \sum_{n=1}^{\infty} \frac{\cos n}
View solution Problem 84
Consider the formula \(\frac{1}{x-1}=1+x+x^{2}+x^{3}+\cdots\) Given \(x=-1\) and \(x=2\), can you conclude that either of the following statements is true? Expl
View solution