Problem 83
Question
A shopper in a mall is on an escalator that is moving downward at an angle of \(41.8^{\circ}\) below the horizontal at a constant speed of \(0.75 \mathrm{~m} / \mathrm{s}\). At the same time a little boy drops a toy parachute from a floor above the escalator and it descends at a steady vertical speed of \(0.50 \mathrm{~m} / \mathrm{s}\). Determine the speed of the parachute toy as observed from the moving escalator.
Step-by-Step Solution
Verified Answer
The parachute appears stationary relative to the shopper on the escalator.
1Step 1: Understanding the problem
We need to find the speed of the toy parachute as observed by the shopper on the escalator. The key here is to find the relative speed of the parachute with respect to the moving escalator.
2Step 2: Identify given parameters
The shopper and the escalator move at a constant speed of 0.75 m/s downward at an angle of 41.8° below the horizontal. The parachute descends with a steady vertical speed of 0.50 m/s.
3Step 3: Calculate escalator's vertical speed component
The vertical speed component of the escalator's motion is found using the formula: \[v_{e,y} = v_e \sin(\theta)\]where \(v_e = 0.75 \text{ m/s}\) and \(\theta = 41.8^{\circ}\) so \[v_{e,y} = 0.75 \sin(41.8^{\circ})\approx 0.50 \text{ m/s}\]
4Step 4: Determine relative speed of parachute as seen by shopper
Since both the parachute and the vertical component of the escalator's speed are the same (0.50 m/s), the parachute's speed relative to the escalator is essentially zero in the vertical direction.
Key Concepts
Escalator PhysicsVelocity ComponentsRelative Speed Calculation
Escalator Physics
When considering escalators in physics, it's important to understand how they move. An escalator is essentially a moving staircase, and it typically moves at a constant speed at a specific angle relative to the horizontal axis. This means that the escalator has both vertical and horizontal components of motion.
- The angle of movement gives the escalator a distinct path, often measured in degrees from the horizontal.
- The constant speed of the escalator is a crucial factor since it determines how swiftly a person or object traveling with it moves both vertically and horizontally.
Velocity Components
To comprehend motion on an escalator, we break down velocities into their components. Any motion at an angle can be decomposed into horizontal and vertical components using trigonometry. Here’s how this works:
- The horizontal component: It describes how fast something moves parallel to the ground. It's determined using the cosine of the angle.
- The vertical component: It represents how fast the object moves up or down, calculated using the sine of the angle.
- The vertical component of its velocity is calculated as: \(v_{e,y} = v_e \sin(41.8^\circ)\).
- Given that \(v_e = 0.75 \text{ m/s}\), substituting the values gives a vertical component of approximately 0.50 m/s.
Relative Speed Calculation
Relative motion is observing how fast an object moves compared to another moving object. In this scenario, we find the relative speed of the parachute as seen by the shopper.
- Since the escalator's vertical speed component and the parachute's descending speed are both 0.50 m/s, they effectively cancel each other out in the vertical direction.
- This means that, to the shopper, the parachute would appear to have no speed vertically, as if it's stationary in regards to the vertical motion.
Other exercises in this chapter
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