Problem 82
Question
When \(\mathrm{MnO}_{2}\) is fused with KOH, a coloured compound is formed. The product and its colour is (a) \(\mathrm{K}_{2} \mathrm{MnO}_{4}\), purple green (b) \(\mathrm{KMnO}_{4}\), purple (c) \(\mathrm{Mn}_{2} \mathrm{O}_{3}\), brown (d) \(\mathrm{Mn}_{i} \mathrm{O}_{4}\), black
Step-by-Step Solution
Verified Answer
The product is \( \mathrm{K}_{2} \mathrm{MnO}_{4} \), green.
1Step 1: Identify the Reaction
When \( \mathrm{MnO}_{2} \) is fused with \( \mathrm{KOH} \) in the presence of oxygen, it undergoes an oxidation process. The manganate ion \( \mathrm{MnO}_{4}^{2-} \) is usually produced in this process.
2Step 2: Determine the Compound Formed
The oxidation of \( \mathrm{MnO}_{2} \) in basic medium by \( \mathrm{KOH} \) results in the formation of potassium manganate, which has the chemical formula \( \mathrm{K}_{2} \mathrm{MnO}_{4} \).
3Step 3: Identify the Colour of the Compound
Potassium manganate \( \mathrm{K}_{2} \mathrm{MnO}_{4} \) is well-known for its green color. This distinguishes it from potassium permanganate \( \mathrm{KMnO}_{4} \), which is purple.
4Step 4: Choose the Correct Option
Based on the information above, \( \mathrm{K}_{2} \mathrm{MnO}_{4} \) is green, which matches the description given in option (a).
Key Concepts
Oxidation ProcessPotassium ManganateChemical Reactions
Oxidation Process
The oxidation process is a fundamental chemical reaction that involves the loss of electrons from a substance. Typically, it means one or more elements within the compound are being transformed to a higher oxidation state by gaining oxygen or losing hydrogen. In the case of manganese dioxide (\(\mathrm{MnO}_{2}\)), when it is fused with potassium hydroxide (\(\mathrm{KOH}\)) and heated in an oxygen-rich environment, an oxidation process occurs.
\(\mathrm{MnO}_{2}\) is oxidized, meaning it loses electrons to form a higher state compound like potassium manganate \(\mathrm{K}_{2} \mathrm{MnO}_{4}\).
This reaction illustrates the essence of oxidation in chemical reactions:
\(\mathrm{MnO}_{2}\) is oxidized, meaning it loses electrons to form a higher state compound like potassium manganate \(\mathrm{K}_{2} \mathrm{MnO}_{4}\).
This reaction illustrates the essence of oxidation in chemical reactions:
- Loss of electrons (oxidation) as opposed to gaining electrons (reduction).
- Transformation of manganese from \(\text{Mn}^{4+}\) in \(\mathrm{MnO}_{2}\) to \(\text{Mn}^{6+}\) in \(\mathrm{K}_{2} \mathrm{MnO}_{4}\).
- Involvement of oxygen as a principal reactant facilitating oxidation.
Potassium Manganate
Potassium manganate is an important compound formed during some inorganic chemical reactions. It bears the chemical formula \( \mathrm{K}_{2} \mathrm{MnO}_{4} \). This compound is significant not only for its structural properties but also for its characteristic green color, setting it apart from its chemical cousin, potassium permanganate, which is purple.
In chemistry, the distinction in color between these two compounds is essential:
In chemistry, the distinction in color between these two compounds is essential:
- Potassium manganate appears green due to the manganese in the oxidation state +6 in the structure \(\mathrm{MnO}_{4}^{2-}\).
- In contrast, potassium permanganate \(\mathrm{KMnO}_{4}\) is purple because manganese has an oxidation state of +7 forming \(\mathrm{MnO}_{4}^{-}\).
Chemical Reactions
Chemical reactions are processes where substances interact, leading to the formation of new products. These transformations involve breaking and forming chemical bonds, often accompanied by energy changes.
In the case of the reaction between manganese dioxide (\(\mathrm{MnO}_{2}\)) and potassium hydroxide (\(\mathrm{KOH}\)), a specific type of chemical reaction occurs known as a solid-state fusion reaction. Here:
In the case of the reaction between manganese dioxide (\(\mathrm{MnO}_{2}\)) and potassium hydroxide (\(\mathrm{KOH}\)), a specific type of chemical reaction occurs known as a solid-state fusion reaction. Here:
- Reactants, \(\mathrm{MnO}_{2}\) and \(\mathrm{KOH}\), are fused together with thermal energy, typically involving oxygen.
- The process leads to the conversion of \(\mathrm{MnO}_{2}\) into potassium manganate \(\mathrm{K}_{2} \mathrm{MnO}_{4}\).
Other exercises in this chapter
Problem 80
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When \(\mathrm{MnO}_{2}\) is fused with KOH, a coloured compound is formed. The product and its colour is (a) \(\mathrm{K}_{2} \mathrm{MnO}_{4}\), purple green
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