Problem 82
Question
Use the identity $$\sin 2 x=2 \sin x \cos x$$ \(n\) times to show that $$\sin \left(2^{n} x\right)=2^{n} \sin x \cos x \cos 2 x \cos 4 x \cdots \cos 2^{n-1} x$$
Step-by-Step Solution
Verified Answer
The identity expands to \(\sin(2^n x) = 2^n \sin x \prod_{j=0}^{n-1} \cos(2^j x)\) by repeated application.
1Step 1: Understanding the Identity
We start with the given identity \(\sin 2x = 2\sin x \cos x\). This identity expresses \(\sin 2x\) in terms of \(\sin x\) and \(\cos x\). It can be seen as a basic building block that we will use repeatedly.
2Step 2: Applying the Identity Once
First, apply the identity to find an expression for \(\sin(4x)\). Using the identity, we have \(\sin(4x) = 2\sin(2x)\cos(2x)\). Substitute the expression for \(\sin(2x) = 2\sin x \cos x\) into this equation: \(\sin(4x) = 2(2\sin x \cos x)\cos(2x) = 4\sin x \cos x \cos(2x)\).
3Step 3: Applying the Identity for General n
Assume by induction that \(\sin(2^k x) = 2^k \sin x \prod_{j=0}^{k-1} \cos(2^j x)\). Now apply the identity to \(\sin(2^{k+1} x) = 2\sin(2^k x)\cos(2^k x)\). Using the induction hypothesis, substitute \(\sin(2^k x)\) with \(2^k \sin x \prod_{j=0}^{k-1} \cos(2^j x)\) to get \(\sin(2^{k+1} x) = 2(2^k \sin x \prod_{j=0}^{k-1} \cos(2^j x))\cos(2^k x)\). This simplifies to \(2^{k+1} \sin x \prod_{j=0}^{k} \cos(2^j x)\).
4Step 4: Conclusion for General n
By mathematical induction, we can conclude that the pattern holds for all natural numbers \(n\): \(\sin(2^n x) = 2^n \sin x \prod_{j=0}^{n-1} \cos(2^j x)\). Thus, every time \(\sin\) doubles its angle, we add a \(\cos\) term to the product, and the power of 2 increases by one.
Key Concepts
Sine FunctionCosine FunctionInduction ProofDouble Angle Identity
Sine Function
The sine function is one of the fundamental trigonometric functions and is crucial in understanding various mathematical concepts. It relates to the ratio of the length of the opposite side over the hypotenuse in a right triangle. The sine function is typically denoted as \( \sin(\theta) \), where \( \theta \) is the angle. In a unit circle, the sine value represents the y-coordinate of the point where the terminal side of the angle intersects the circle.
Key properties of the sine function include:
Key properties of the sine function include:
- Its range from -1 to 1.
- It is an odd function, meaning \( \sin(-x) = -\sin(x) \).
- It is periodic with a period of \( 2\pi \).
Cosine Function
The cosine function is another primary function in trigonometry, typically paired with the sine function to form the essentials of circular functions. It is noted as \( \cos(\theta) \), and it describes the ratio of the adjacent side over the hypotenuse in a right triangle. For a unit circle, the cosine of an angle represents the x-coordinate of the intersection point with the terminal side of the angle.
Important features of the cosine function include:
Important features of the cosine function include:
- A range from -1 to 1.
- Being an even function, expressed as \( \cos(-x) = \cos(x) \).
- Periodic with a period of \( 2\pi \).
Induction Proof
Induction is a mathematical proof technique used to prove statements for all natural numbers. An induction proof normally involves two main steps: a base case and an inductive step. The base case verifies the statement for an initial value, typically for \( n = 0 \) or \( n = 1 \). The inductive step assumes the statement is true for \( n = k \) and then proves it for \( n = k+1 \).
This process is akin to dominoes falling; once you push the first one (base case), and show one knocks over the next (inductive step), all dominoes fall indefinitely. With the exercise provided, induction is skillfully employed to unfold the identity \( \sin(2^n x) = 2^n \sin x \prod_{j=0}^{n-1} \cos(2^j x) \) for every natural number \( n \). This elegant process is quite powerful in unveiling and proving intricate patterns in mathematics.
This process is akin to dominoes falling; once you push the first one (base case), and show one knocks over the next (inductive step), all dominoes fall indefinitely. With the exercise provided, induction is skillfully employed to unfold the identity \( \sin(2^n x) = 2^n \sin x \prod_{j=0}^{n-1} \cos(2^j x) \) for every natural number \( n \). This elegant process is quite powerful in unveiling and proving intricate patterns in mathematics.
Double Angle Identity
The double angle identity is a pivotal trigonometric identity that expresses trigonometric functions of double angles in terms of single angles. The specific double angle identity used in the exercise is \( \sin(2x) = 2 \sin(x) \cos(x) \). This formula demonstrates how doubling an angle reconfigures the sine function's angle representation using both sine and cosine expressions of the original angle.
Some important double angle identities also include:
Some important double angle identities also include:
- \( \cos(2x) = \cos^2(x) - \sin^2(x) \),
- \( \cos(2x) = 1 - 2\sin^2(x) \),
- \( \cos(2x) = 2\cos^2(x) - 1 \).
Other exercises in this chapter
Problem 81
Prove the identity $$\frac{\sin x+\sin 2 x+\sin 3 x+\sin 4 x+\sin 5 x}{\cos x+\cos 2 x+\cos 3 x+\cos 4 x+\cos 5 x}=\tan 3 x$$
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Verify the identity. $$ \frac{\cot x+1}{\cot x-1}=\frac{1+\tan x}{1-\tan x} $$
View solution Problem 83
Verify the identity. $$ \frac{\sin ^{3} x+\cos ^{3} x}{\sin x+\cos x}=1-\sin x \cos x $$
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In Philadelphia the number of hours of daylight on day \(t\) (where \(t\) is the number of days after January 1 ) is modeled by the function $$L(t)=12+2.83 \sin
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