Problem 82
Question
Use the definitions of the hyperbolic functions to find each of the following limits. $$a.\lim _{x \rightarrow \infty} \tanh x \quad \text { b. } \lim _{x \rightarrow-\infty} \tanh x$$ $$c.\lim _{x \rightarrow \infty} \sinh x \quad \text { d. } \lim _{x \rightarrow-\infty} \sinh x$$ $$e.\lim _{x \rightarrow \infty} \operatorname{sech} x \quad \text { f. } \lim _{x \rightarrow \infty} \operatorname{coth} x$$ $$g.\lim _{x \rightarrow 0^{+}} \operatorname{coth} x \quad \text { h. } \lim _{x \rightarrow 0} \operatorname{coth} x$$ $$i.\lim _{x \rightarrow-\infty} \operatorname{csch} x$$
Step-by-Step Solution
Verified Answer
a. 1, b. -1, c. \( \infty \), d. \(-\infty\), e. 0, f. 1, g. \( \infty \), h. undefined, i. 0
1Step 1: Definition of Hyperbolic Tangent
The hyperbolic tangent function is defined as \( \tanh(x) = \frac{\sinh(x)}{\cosh(x)} = \frac{e^x - e^{-x}}{e^x + e^{-x}} \). To find the limits, we analyze the behavior of \( e^x \) and \( e^{-x} \) as \( x \) approaches infinity and negative infinity.
2Step 2: Limit of \( \tanh(x) \) as \( x \to \infty \)
For \( x \to \infty \), the terms \( e^x \) dominate over \( e^{-x} \), so \( \tanh(x) = \frac{e^x - e^{-x}}{e^x + e^{-x}} \approx \frac{e^x}{e^x} = 1 \). Therefore, \( \lim_{x \to \infty} \tanh x = 1 \).
3Step 3: Limit of \( \tanh(x) \) as \( x \to -\infty \)
For \( x \to -\infty \), the terms \( e^{-x} \) dominate, giving \( \tanh(x) = \frac{e^x - e^{-x}}{e^x + e^{-x}} \approx \frac{-e^{-x}}{e^{-x}} = -1 \). Hence, \( \lim_{x \to -\infty} \tanh x = -1 \).
4Step 4: Limit of \( \sinh(x) \) as \( x \to \infty \)
The hyperbolic sine function is \( \sinh(x) = \frac{e^x - e^{-x}}{2} \). As \( x \to \infty \), \( e^x \) becomes very large, so \( \sinh(x) \approx \frac{e^x}{2} \to \infty \). Therefore, \( \lim_{x \to \infty} \sinh x = \infty \).
5Step 5: Limit of \( \sinh(x) \) as \( x \to -\infty \)
As \( x \to -\infty \), the term \( e^{-x} \) becomes dominant: \( \sinh(x) = \frac{e^x - e^{-x}}{2} \approx -\frac{e^{-x}}{2} \to -\infty \). Therefore, \( \lim_{x \to -\infty} \sinh x = -\infty \).
6Step 6: Limit of \( \operatorname{sech}(x) \) as \( x \to \infty \)
The hyperbolic secant is \( \operatorname{sech}(x) = \frac{1}{\cosh(x)} = \frac{2}{e^x + e^{-x}} \). As \( x \to \infty \), \( e^x \) dominates, so \( \operatorname{sech}(x) \approx \frac{2}{e^x} \to 0 \). Thus, \( \lim_{x \to \infty} \operatorname{sech} x = 0 \).
7Step 7: Limit of \( \operatorname{coth}(x) \) as \( x \to \infty \)
The hyperbolic cotangent is \( \operatorname{coth}(x) = \frac{\cosh(x)}{\sinh(x)} = \frac{e^x + e^{-x}}{e^x - e^{-x}} \). As \( x \to \infty \), \( e^x \) dominates, and \( \operatorname{coth}(x) \approx 1 \). Therefore, \( \lim_{x \to \infty} \operatorname{coth} x = 1 \).
8Step 8: Limit of \( \operatorname{coth}(x) \) as \( x \to 0^+ \)
For \( x \to 0^+ \), the behavior of \( \operatorname{coth}(x) = \frac{\cosh(x)}{\sinh(x)} \) is influenced by \( \sinh(x) \approx x \) and \( \cosh(x) \approx 1 + \frac{x^2}{2} \). As \( x \to 0^+ \), \( \operatorname{coth}(x) \to \frac{1}{x} \to \infty \). Thus, \(\lim_{x \to 0^+} \operatorname{coth} x = \infty \).
9Step 9: Limit of \( \operatorname{coth}(x) \) as \( x \to 0 \)
This implies finding the behavior as \( x \to 0^- \) since \( \coth(x) \to -\infty \) for negative approaching 0, combining to give undefined as \( \lim_{x \to 0} \).
10Step 10: Limit of \( \operatorname{csch}(x) \) as \( x \to -\infty \)
The hyperbolic cosecant is \( \operatorname{csch}(x) = \frac{1}{\sinh(x)} \). As \( x \to -\infty \), \( \sinh(x) \to -\infty \), thus \( \operatorname{csch}(x) \approx -\frac{1}{e^{-x}/2} \to 0 \). Therefore, \( \lim_{x \to -\infty} \operatorname{csch} x = 0 \).
Key Concepts
Hyperbolic Tangent (tanh)Hyperbolic Sine (sinh)Understanding LimitsHyperbolic Cotangent (coth)Hyperbolic Secant (sech)
Hyperbolic Tangent (tanh)
The hyperbolic tangent function, denoted as \( \tanh(x) \), is a fundamental hyperbolic function with diverse applications in mathematics and engineering. It is defined as the ratio of the hyperbolic sine to the hyperbolic cosine: \( \tanh(x) = \frac{\sinh(x)}{\cosh(x)} = \frac{e^x - e^{-x}}{e^x + e^{-x}} \). This function is known for its characteristic S-shaped curve, which approaches different limits as the input \( x \) moves towards positive or negative infinity.
Key limit values for \( \tanh(x) \) include:
Key limit values for \( \tanh(x) \) include:
- As \( x \to \infty \), \( \tanh(x) \to 1 \). This occurs because the term \( e^x \) becomes significantly larger than \( e^{-x} \), simplifying the function to approximately \( \frac{e^x}{e^x} = 1 \).
- As \( x \to -\infty \), \( \tanh(x) \to -1 \). Here, \( e^{-x} \) dominates, leading the function towards \( -1 \).
Hyperbolic Sine (sinh)
The hyperbolic sine function, expressed as \( \sinh(x) \), is another crucial hyperbolic function. Its formula is \( \sinh(x) = \frac{e^x - e^{-x}}{2} \). Unlike the sine function in trigonometry, the hyperbolic sine function does not oscillate, but rather increases or decreases exponentially.
When examining the limits of \( \sinh(x) \), we observe the following behavior:
When examining the limits of \( \sinh(x) \), we observe the following behavior:
- As \( x \to \infty \), \( \sinh(x) \to \infty \). This is because \( e^x \) grows significantly larger than \( e^{-x} \), forcing \( \frac{e^x - e^{-x}}{2} \to \infty \).
- As \( x \to -\infty \), \( \sinh(x) \to -\infty \). Here, the term \( e^{-x} \) becomes the dominant term in the expression, resulting in an increasingly negative value.
Understanding Limits
In calculus, the concept of a limit is vital for understanding the behavior of functions as they approach specific points or tend toward infinity. Limits allow us to ascertain instantaneous rates of change and continuity of functions.
For hyperbolic functions such as \( \tanh \) and \( \sinh \), evaluating limits helps in analyzing their asymptotic behavior:
For hyperbolic functions such as \( \tanh \) and \( \sinh \), evaluating limits helps in analyzing their asymptotic behavior:
- For \( \lim_{x \to \infty} \), we are interested in what value a function approaches as its input grows without bound.
- For \( \lim_{x \to -\infty} \), the concern is the value as the input decreases without bound.
- Finally, understanding \( \lim_{x \to 0} \) or \( \lim_{x \to 0^+} \) helps in evaluating how functions behave very close to zero, from either the positive or negative side.
Hyperbolic Cotangent (coth)
The hyperbolic cotangent function, \( \coth(x) \), is defined as the reciprocal of hyperbolic tangent, \( \coth(x) = \frac{\cosh(x)}{\sinh(x)} \). It is an important function, especially when working with hyperbolic identities and solutions in differential equations.
The behavior of \( \coth(x) \) is notable near various limits:
The behavior of \( \coth(x) \) is notable near various limits:
- As \( x \to \infty \), \( \coth(x) \) approaches \( 1 \), because both the numerator and denominator are dominated by the exponential growth of \( e^x \), leading to \( \frac{e^x}{e^x} \equiv 1 \).
- When \( x \) nears zero from the positive side, \( \lim_{x \to 0^+} \coth(x) \to \infty \). This is due to \( \sinh(x) \approx x \) and \( \coth(x) \approx \frac{1}{x} \), which tends to grow exponentially large as \( x \to 0^+ \).
Hyperbolic Secant (sech)
The hyperbolic secant, \( \operatorname{sech}(x) \), is another important hyperbolic function. It is defined as the reciprocal of the hyperbolic cosine function, \( \operatorname{sech}(x) = \frac{1}{\cosh(x)} = \frac{2}{e^x + e^{-x}} \). This function has interesting properties when examined under limiting conditions.
Some notable limits of \( \operatorname{sech}(x) \) include:
Some notable limits of \( \operatorname{sech}(x) \) include:
- As \( x \to \infty \), \( \operatorname{sech}(x) \to 0 \). The term \( e^x \) in the denominator grows very large, making \( \frac{2}{e^x} \) approach zero.
Other exercises in this chapter
Problem 81
Find the lengths of the following curves. $$ \begin{array}{l}{\text { a. } y=\left(x^{2} / 8\right)-\ln x, \quad 4 \leq x \leq 8} \\ {\text { b. } x=(y / 4)^{2}
View solution Problem 82
Evaluate the integrals in Exercises \(71-84\) $$ \int \frac{t^{3}-2 t^{2}+3 t-4}{t^{2}+1} d t $$
View solution Problem 82
Find \(\lim _{x \rightarrow \infty}\left(\sqrt{x^{2}+1}-\sqrt{x}\right)\)
View solution Problem 82
Find a curve through the point \((1,0)\) whose length from \(x=1\) to \(x=2\) is $$L=\int_{1}^{2} \sqrt{1+\frac{1}{x^{2}}} d x$$
View solution