Problem 82
Question
Suppose that \(E(x)\) is a function such that \(E^{\prime}(x)=E(x)\). Use the Chain Rule to show that the derivative of the composite function \(E(g(x))\) is \(\frac{d}{d x} E(g(x))=E(g(x)) \cdot g^{\prime}(x) .\)
Step-by-Step Solution
Verified Answer
The derivative of \(E(g(x))\) is \(E(g(x)) \cdot g'(x)\).
1Step 1: Understand the Given Function
We know that the function \(E(x)\) has the property that its derivative is equal to the function itself, i.e., \(E^{\prime}(x) = E(x)\). This implies \(E(x)\) is an exponential function.
2Step 2: Apply the Chain Rule
The Chain Rule states that if you have a composite function \(E(g(x))\), the derivative with respect to \(x\) is given by \(\frac{d}{dx}[E(g(x))] = E^{\prime}(g(x)) \cdot g^{\prime}(x)\).
3Step 3: Substitute the Known Derivative
Since \(E^{\prime}(x) = E(x)\), we substitute \(E^{\prime}(g(x))\) with \(E(g(x))\). Thus, the derivative becomes \(E(g(x)) \cdot g^{\prime}(x)\).
4Step 4: Conclusion of Steps
We have found that using the Chain Rule and the given property of \(E(x)\), the derivative of \(E(g(x))\) is \(E(g(x)) \cdot g^{\prime}(x)\). This confirms the relationship we needed to show.
Key Concepts
Chain RuleComposite FunctionsExponential Functions
Chain Rule
The Chain Rule is a fundamental theorem in calculus used to compute the derivative of a composite function. In simpler terms, it's a rule that allows us to differentiate functions that are "nested" inside one another. To understand this, think of a composite function as one function inside another, like a Russian nesting doll.
Imagine you have a function described as \(f(g(x))\). The Chain Rule tells us how to differentiate this composite function with respect to \(x\). The formula is:
In our original exercise, \(E(g(x))\) is a composite function, with \(E\) as the outer function and \(g(x)\) as the inner function. Applying the Chain Rule efficiently breaks down the differentiation process.
Imagine you have a function described as \(f(g(x))\). The Chain Rule tells us how to differentiate this composite function with respect to \(x\). The formula is:
- First, differentiate the outer function \(f\) with respect to its inner function (let's call it \(u\)), giving \(f'(u)\).
- Then, multiply by the derivative of the inner function \(g(x)\) with respect to \(x\), giving \(g'(x)\).
In our original exercise, \(E(g(x))\) is a composite function, with \(E\) as the outer function and \(g(x)\) as the inner function. Applying the Chain Rule efficiently breaks down the differentiation process.
Composite Functions
Composite functions are functions constructed by combining two or more functions. In notation, if you have two functions \(f(x)\) and \(g(x)\), their composition is denoted as \(f(g(x))\). This means you first apply \(g\) to \(x\), and then apply \(f\) to the result from \(g(x)\).
This process can be visualized as processing an input through multiple stages. For example:
This layered approach is fundamental in advanced calculus, as it enables the building of complex equations from simpler ones. Understanding composite functions is crucial as they naturally lead us to utilize the Chain Rule for differentiation.
This process can be visualized as processing an input through multiple stages. For example:
- First, you input \(x\) into \(g\).
- Second, the output of \(g(x)\) becomes the input for \(f\).
This layered approach is fundamental in advanced calculus, as it enables the building of complex equations from simpler ones. Understanding composite functions is crucial as they naturally lead us to utilize the Chain Rule for differentiation.
Exponential Functions
Exponential functions are a special class of functions where a constant base is raised to a variable exponent, typically described in the form \(b^{x}\). A common exponential function seen in calculus is the natural exponential function, represented as \(e^{x}\), where \(e\) is approximately 2.71828.
In the context of differentiation, exponential functions have a unique quality: the derivative of \(e^{x}\) is itself, \(e^{x}\). Therefore, if we have an exponential function \(E(x)\) such that \(E'(x) = E(x)\), it clearly aligns with the properties of the natural exponential.
Our initial problem states that \(E'(x) = E(x)\), indicating that \(E(x)\) is an exponential function—it has the same form as \(e^{x}\).
In the context of differentiation, exponential functions have a unique quality: the derivative of \(e^{x}\) is itself, \(e^{x}\). Therefore, if we have an exponential function \(E(x)\) such that \(E'(x) = E(x)\), it clearly aligns with the properties of the natural exponential.
Our initial problem states that \(E'(x) = E(x)\), indicating that \(E(x)\) is an exponential function—it has the same form as \(e^{x}\).
- When \(E(x)\) is used within a composite function as in \(E(g(x))\), this self-deriving property becomes powerful.
- It simplifies the calculation by maintaining the same form, even after differentiation, as long as the Chain Rule is properly applied.
Other exercises in this chapter
Problem 81
BUSINESS: Interest Compounded Continuously If you deposit $$\$ 1$$ into a bank account paying \(10 \%\) interest compounded continuously (see Section 4.1), a ye
View solution Problem 81
Let \(f\) and \(g\) be differentiable functions of \(x\). Assume that denominators are not zero. True or False: \(\frac{d}{d x}(x \cdot f)=f+x \cdot f^{\prime}\
View solution Problem 82
Let \(f\) and \(g\) be differentiable functions of \(x\). Assume that denominators are not zero. True or False: \(\frac{d}{d x}\left(\frac{f}{x}\right)=\frac{x
View solution Problem 83
Find the limit by making a TABLE of values correct to two decimal places, thereby finding the value of the deposit in dollars and cents. GENERAL: Superconductiv
View solution