Problem 82
Question
Of the following nuclides, the highest nuclear binding energy per nucleon is found in (a) \(_{1}^{3} \mathrm{H} ;\) (b) \(_{8}^{16} \mathrm{O} ;\) (c) \(_{26}^{56} \mathrm{Fe}\); (d) \(_{92}^{235} \mathrm{U}\).
Step-by-Step Solution
Verified Answer
The nuclide with the highest nuclear binding energy per nucleon is \(_{26}^{56} \mathrm{Fe}\).
1Step 1: Understanding the information
The task gives us four nuclides: Tritium \(_{1}^{3} \mathrm{H}\), Oxygen \(_{8}^{16} \mathrm{O}\), Iron \(_{26}^{56} \mathrm{Fe}\), and Uranium \(_{92}^{235} \mathrm{U}\). We need to determine which one of these has the highest nuclear binding energy per nucleon.
2Step 2: Refer to the binding energy curve
The binding energy curve charts binding energy per nucleon against atomic number. First, it increases, reaching a maximum at Iron-56 (\(_{26}^{56} \mathrm{Fe}\)), then it decreases for elements with higher atomic numbers.
3Step 3: Apply knowledge of the binding energy curve to given nuclides
According to the curve, the binding energy per nucleon is highest for Iron-56 (\(_{26}^{56} \mathrm{Fe}\)), lower for elements lighter than iron like Tritium (\(_{1}^{3} \mathrm{H}\)) and Oxygen (\(_{8}^{16} \mathrm{O}\)), and even lower for heavier elements like Uranium (\(_{92}^{235} \mathrm{U}\)).
Key Concepts
NuclidesIron-56Binding Energy Curve
Nuclides
When discussing nuclear physics, the term "nuclides" comes up frequently. A nuclide refers to a specific type of atomic nucleus, defined by its number of protons (atomic number) and neutrons. This means that each nuclide is characterized by a unique combination of these two subatomic particles. Understanding nuclides is crucial because they form the foundation of nuclear chemistry and physics. They help in identifying the stability and energy characteristics of atoms.
Nuclides are often represented using the notation \(_{Z}^{A}X\), where:
Nuclides are often represented using the notation \(_{Z}^{A}X\), where:
- \(Z\) is the atomic number (number of protons)
- \(A\) is the mass number (total number of protons and neutrons)
- \(X\) is the chemical symbol of the element
Iron-56
Iron-56 is a special nuclide often referenced in the study of nuclear physics and chemistry. It is denoted as \(_{26}^{56} \, \mathrm{Fe}\), where it consists of 26 protons and 30 neutrons. This particular nuclide is significant because it has one of the highest binding energies per nucleon. Binding energy per nucleon is an indicator of the stability of a nucleus - the higher it is, the more stable the nucleus.
In fact, Iron-56 is considered to be the most stable nuclide in existence, at least in terms of nuclear binding energy. This results from the optimal ratio and distribution of protons and neutrons within its nucleus. Due to its stability, it is prevalent in the universe and commonly discussed in the context of stellar nuclear processes, where many elements form and degrade based on their stability relative to Iron-56.
In fact, Iron-56 is considered to be the most stable nuclide in existence, at least in terms of nuclear binding energy. This results from the optimal ratio and distribution of protons and neutrons within its nucleus. Due to its stability, it is prevalent in the universe and commonly discussed in the context of stellar nuclear processes, where many elements form and degrade based on their stability relative to Iron-56.
Binding Energy Curve
The concept of the "Binding Energy Curve" is essential for understanding the stability of different nuclides. This curve represents the binding energy per nucleon plotted against the atomic number of different elements. Initially, as the atomic number increases, so does the binding energy per nucleon. This trend reaches its peak at Iron-56, which holds the maximum value.
- This indicates that Iron-56 is the most stable, with a strong nuclear force holding together its protons and neutrons.
- After Iron-56, the binding energy per nucleon begins to decrease as elements become heavier.
Other exercises in this chapter
Problem 80
Of the following nuclides, the one most likely to be radioactive is \((a)^{31} P ;(b)^{66} Z n ;(c)^{35} C l ;(d)^{108} A g\).
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One of the following elements has eight naturally occurring stable isotopes. We should expect that one to be (a) \(\mathrm{Ra} ;\) (b) \(\mathrm{Au} ;\) (c) \(\
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The most radioactive of the isotopes of an element is the one with the largest value of its (a) half-life, \(t_{1 / 2}\) (b) neutron number, \(N ;\) (c) mass nu
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Given a radioactive nuclide with \(t_{1 / 2}=1.00 \mathrm{h}\) and a current disintegration rate of 1000 atoms \(s^{-1}\), three hours from now the disintegrati
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