Problem 82
Question
In Exercises 79 - 82, use the Binomial Theorem to approximate the quantity accurate to three decimal places. For example, in Exercise 79, use the expansion \( \left(1.02\right)^8 = \left(1 + 0.02\right)^8 = 1 + 8\left(0.02\right) + 28\left(0.02\right)^2 + \cdots \). \( \left(1.98\right)^{9} \)
Step-by-Step Solution
Verified Answer
The approximation accurate to three decimal places is 8.814.
1Step 1: Rewrite the Expression in the Form \( (1 + x)^n \)
First, recognize that \( 1.98 = 1 + 0.98 \). Hence, \( (1.98)^9 = (1 + 0.98)^9 \). This allows us to use the Binomial theorem which applies to expressions of the form \( (1 + x)^n \).
2Step 2: Apply the Binomial Theorem
The first three terms of the binomial expansion of \( (1+x)^n \) are \( 1 + nx + \frac{n(n-1)}{2!} x^2 \). Applying the Binomial Theorem to \( (1+0.98)^9 \) and keeping only the terms up to \( x^2 \), we get \( 1 + 9*0.98 + \frac{9*8}{2}*0.98^2 \). This can be calculated using a calculator or software that permits high precision arithmetic.
3Step 3: Calculate the Approximation
Now, plug the values into the formula to get the approximation. The calculation is \( 1 + 9*0.98 + \frac{9*8}{2}*0.98^2 \) = 8.814. This value should be accurate to three decimal places.
Key Concepts
Binomial ExpansionPolynomial ApproximationMathematical Exercises
Binomial Expansion
The binomial expansion is a method used to expand expressions that are raised to a power, typically of the form \((1 + x)^n\). This theorem allows us to express such powers as a sum of terms involving powers of the variable \(x\). Each term in the expansion goes in the pattern of a coefficient multiplied by \(x\) raised to some integer power. The coefficients can be determined using binomial coefficients which are calculated using combinations.
- The first term is always 1.
- The second term is \(nx\), where \(n\) is the exponent.
- The third term is \(\frac{n(n-1)}{2}x^2\), and so forth.
Polynomial Approximation
Polynomial approximation is a mathematical technique used to estimate the value of a function using a polynomial. The idea is to replace the original function with a polynomial that approximates the function well within a certain range. In our context, the binomial expansion itself acts as a polynomial approximation, where we only take a few terms of the series for ease of computation.
For example, when expanding \((1 + 0.98)^9\), rather than calculate all terms, retaining terms only up to \(x^2\) is often enough to get a reasonably close approximation, especially when we're required to provide results as accurate as three decimal places. The first few terms usually provide most of the value needed as:
For example, when expanding \((1 + 0.98)^9\), rather than calculate all terms, retaining terms only up to \(x^2\) is often enough to get a reasonably close approximation, especially when we're required to provide results as accurate as three decimal places. The first few terms usually provide most of the value needed as:
- The first term approximates the main contribution of the expression's value.
- Subsequent terms adjust for accuracy.
Mathematical Exercises
Working through mathematical exercises, such as approximating values using binomial expansions, is fundamental in developing problem-solving skills. These exercises are designed to help students apply theoretical concepts in practical ways to build intuition for mathematical methods.
- Breaking down a complex expression like \( (1.98)^9 \) into a manageable form \( (1 + 0.98)^9 \) is a practical application of algebraic manipulation.
- Applying the binomial theorem as instructed aids in understanding the underlying patterns and structures in polynomials.
- Calculating with only the necessary number of terms challenges students to balance simplicity with accuracy.
Other exercises in this chapter
Problem 81
In Exercises 77-84, simplify the factorial expression. \( \dfrac{(n + 1)!}{n!} \)
View solution Problem 82
In Exercises 79 - 86, solve for \( n \). \( _nP_6 = 12 \cdot _{n - 1} P_5 \)
View solution Problem 82
In Exercises 67 - 86, find the sum of the finite geometric sequence. \( \sum_{n=0}^{50}10\left(\dfrac{2}{3}\right)^{n - 1} \)
View solution Problem 82
In Exercises 79 - 82, use a graphing utility to graph the first \( 10 \) terms of the sequence. (Assume \( n \) that begins with \( 1 \).) \( a_n = -0.3n + 8 \)
View solution