Problem 82
Question
Find each power of \(i .\) See Example 6. $$ i^{10} $$
Step-by-Step Solution
Verified Answer
\(i^{10} = -1\).
1Step 1: Understand the Cycle of Powers of i
The imaginary unit \( i \) has a cyclical pattern for its powers. Specifically, the powers of \( i \) cycle every four exponents: - \( i^1 = i \) - \( i^2 = -1 \) - \( i^3 = -i \) - \( i^4 = 1 \) This pattern repeats for every next group of four powers.
2Step 2: Divide the Exponent by 4
To find \( i^{10} \), divide the exponent by 4 and find the remainder. The remainder will help us determine which power in the cycle it corresponds to. Perform the division: \[ 10 \div 4 = 2 ext{ remainder } 2 \]So, the remainder when 10 is divided by 4 is 2.
3Step 3: Use the Remainder to Find the Power
Refer to the cycle of powers of \( i \) determined in Step 1. Since the remainder is 2, \( i^{10} \) corresponds to \( i^2 \).Thus, \( i^2 = -1 \).
Key Concepts
Imaginary UnitCyclical PatternRemainderImaginary Numbers
Imaginary Unit
The imaginary unit, denoted by \( i \), is a mathematical concept used to extend the real number system. It is defined by the property \( i^2 = -1 \). This means when you square the imaginary unit, you get \(-1\). This notion allows us to develop complex numbers, where a number can be expressed as a sum of a real part and an imaginary part. This innovation makes it possible to solve equations that lack real solutions, such as \( x^2 + 1 = 0 \). By introducing \( i \), we can say the solutions are \( x = i \) and \( x = -i \), fundamentally changing the landscape of algebra and calculus.
Cyclical Pattern
A fascinating feature of the powers of \( i \) is their cyclical pattern. This cycle is easy to recognize and memorize:
- \( i^1 = i \)
- \( i^2 = -1 \)
- \( i^3 = -i \)
- \( i^4 = 1 \)
Remainder
To find where a specific power of \( i \) fits within its four-value cycle, we use division to find the remainder. For example, if we want to find \( i^{10} \), dividing 10 by 4 gives a remainder of 2. This remainder tells us which power in the sequence of \( i^1, i^2, i^3, i^4 \) corresponds to \( i^{10} \). In this instance, a remainder of 2 aligns with \( i^2 \), indicating that \( i^{10} = i^2 = -1 \). This method effectively reduces potentially complex calculations to simple arithmetic, leveraging the cyclical nature of the powers of \( i \).
Imaginary Numbers
Imaginary numbers are a fundamental extension of the real numbers, allowing us to solve equations that don't have solutions within the real number system. Each imaginary number is a multiple of the imaginary unit \( i \). When combined with real numbers, they form complex numbers of the form \( a + bi \), where \( a \) and \( b \) are real numbers.
Imaginary numbers broaden the scope of mathematical solutions, enabling new insights and applications. They play a crucial role in various fields, including engineering, physics, and computer science, where complex numbers are used to describe phenomena such as electrical currents and signal processing.
Imaginary numbers broaden the scope of mathematical solutions, enabling new insights and applications. They play a crucial role in various fields, including engineering, physics, and computer science, where complex numbers are used to describe phenomena such as electrical currents and signal processing.
Other exercises in this chapter
Problem 82
Find the distance between each pair of points. Give an exact distance and a three-decimal-place approximation. See Example 6 $$ (-5,-2) \text { and }(-6,-6) $$
View solution Problem 82
Factor each mumerator and denominator. Then simplify if possible. $$ \frac{14 r-28 r^{2} s^{2}}{7 r s} $$
View solution Problem 83
If \(f(x)=\sqrt{2 x+3}\) and \(g(x)=\sqrt[3]{x-8},\) find the following function values. $$ f(2) $$
View solution Problem 83
Use rational exponents to simplify each radical. Assume that all variables represent positive numbers. $$ \sqrt[4]{(x+3)^{2}} $$
View solution