Problem 82
Question
Factor. $$ x^{3 m}-y^{3 n} $$
Step-by-Step Solution
Verified Answer
The expression is factored as \((x^m - y^n)(x^{2m} + x^m y^n + y^{2n})\).
1Step 1: Identify the Expression Format
The expression given is \( x^{3m} - y^{3n} \), which is a difference of cubes. A difference of cubes follows the formula \( a^3 - b^3 = (a - b)(a^2 + ab + b^2) \).
2Step 2: Assign Appropriate Values
From \( x^{3m} - y^{3n} \), assign \( a = x^m \) and \( b = y^n \). This makes the provided expression equal to \( (x^m)^3 - (y^n)^3 \), fitting the difference of cubes formula.
3Step 3: Apply the Difference of Cubes Formula
Substitute \( a = x^m \) and \( b = y^n \) into the difference of cubes formula. This gives:\[(x^m - y^n)( (x^m)^2 + x^m y^n + (y^n)^2 )\].
4Step 4: Simplify Each Factor
Simplify each part of the expression:The first factor is \( (x^m - y^n) \).The second factor is:- \((x^m)^2 = x^{2m}\)- \(x^m y^n\) remains as is- \((y^n)^2 = y^{2n}\)Thus, the second factor becomes: \( x^{2m} + x^m y^n + y^{2n} \).
5Step 5: Write the Final Factored Expression
Combine both factors to obtain the factored form:\[(x^m - y^n)(x^{2m} + x^m y^n + y^{2n})\].
Key Concepts
Difference of CubesExponent RulesAlgebraic Formulas
Difference of Cubes
In algebra, one of the most important factorization techniques is the difference of cubes. This method is useful when you want to factor an expression of the form \(a^3 - b^3\). When you encounter such an expression, you can use the formula: \[a^3 - b^3 = (a - b)(a^2 + ab + b^2)\] This formula simplifies the process of breaking down the expression into a product of simpler terms.
- The first factor is \(a - b\), where \(a\) and \(b\) are the cube roots of the terms.
- The second factor is \(a^2 + ab + b^2\), which is a bit more complex but still manageable.
Exponent Rules
Exponents are a way to express repeated multiplication of a base number. For example, \(x^3\) means \(x\) multiplied by itself three times. In the context of our expression \(x^{3m} - y^{3n}\), we deal with exponents in several steps:When raising an exponent to another exponent, you multiply the exponents according to the rule \((x^m)^3 = x^{m \times 3} = x^{3m}\). This simplifies calculations significantly:
- For \((x^m)^2\), the result is \(x^{2m}\).
- For \((y^n)^2\), it becomes \(y^{2n}\).
Algebraic Formulas
Algebraic formulas like the difference of cubes come in handy when working with polynomial expressions. Formulas in algebra are often designed as shortcuts to simplify complex operations into manageable steps. The difference of cubes formula we applied is a textbook example of using algebraic formulas to rearrange terms efficiently:
- Structure Understanding: Recognizing \(a^3\) and \(b^3\) helps in identifying the type of expression we are dealing with.
- Simplification: An algebraic formula provides a streamlined path to reduce the expression into simpler, factorable parts.
- Application: Once the expression's type is recognized, formulas allow easy substitution of terms aligned with the given structure.
Other exercises in this chapter
Problem 82
Solve each equation. $$ 4 y^{2}-11 y-3=0 $$
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Factor. $$ g^{3}-121 g $$
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Factor. If an expression is prime, so indicate. $$ -28 u^{3} v^{3}+26 u^{2} v^{4}-6 u v^{5} $$
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Factor by grouping. $$ 9 s^{3}-2 s^{2}+36 s-8 $$
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