Problem 82
Question
Factor completely. $$x^{2}+\frac{2}{3} x+\frac{1}{9}$$
Step-by-Step Solution
Verified Answer
The completely factored form of the given expression is \((x + 1/3)^2\).
1Step 1: Identify the Perfect Square Trinomial
The given quadratic expression can be represented in the form \(a^2 + 2ab + b^2\), where \(a = x\), \(b = 1/3\) such that: 1. \(a^2 = x^2\), 2. \(2ab = 2*x*1/3 = 2x/3\), and 3. \(b^2 = (1/3)^2 = 1/9\). This confirms the quadratic is a perfect square trinomial.
2Step 2: Factorize the Trinomial
Since the given expression is a perfect square trinomial, it can be factored into \((a+b)^2\). Substituting the values of \(a = x\) and \(b = 1/3\) into the equation, we get \((x + 1/3)^2\).
Key Concepts
Perfect Square TrinomialAlgebraQuadratic Expression
Perfect Square Trinomial
A perfect square trinomial is a special type of quadratic expression. It has the form \(a^2 + 2ab + b^2\).
This type of expression results from squaring a binomial.
The completed square results in
Notice how \(x^2\) is \(a^2\), \(\frac{2}{3}x\) is \(2ab\), and \(\frac{1}{9}\) is \(b^2\).
By identifying \(a = x\) and \(b = \frac{1}{3}\), we confirm this is a perfect square trinomial as it matches the formula pattern.
This understanding helps us factor the trinomial easily as it is already in a recognizable form. The expression simplifies neatly to \((x + \frac{1}{3})^2\).
This type of expression results from squaring a binomial.
The completed square results in
- the first term being \(a^2\)
- the second term being \(2ab\)
- the third term being \(b^2\)
Notice how \(x^2\) is \(a^2\), \(\frac{2}{3}x\) is \(2ab\), and \(\frac{1}{9}\) is \(b^2\).
By identifying \(a = x\) and \(b = \frac{1}{3}\), we confirm this is a perfect square trinomial as it matches the formula pattern.
This understanding helps us factor the trinomial easily as it is already in a recognizable form. The expression simplifies neatly to \((x + \frac{1}{3})^2\).
Algebra
Algebra is a branch of mathematics that uses symbols and letters to represent numbers and quantities in formulas and equations.
It enables the solving of problems and the manipulation of mathematical expressions.
When working with expressions like \(x^{2} + \frac{2}{3}x + \frac{1}{9}\), algebraic manipulation is key.
This fundamental approach in algebra makes problem-solving intuitive and logical.
It enables the solving of problems and the manipulation of mathematical expressions.
When working with expressions like \(x^{2} + \frac{2}{3}x + \frac{1}{9}\), algebraic manipulation is key.
- Identify patterns: Look for recognizable patterns like the perfect square trinomial.
- Substitute correctly: Use substitution to identify parts of the expression, such as \(a = x\) and \(b = \frac{1}{3}\).
- Factor: Based on the identified pattern, rewrite the expression in its factored form, \((x + \frac{1}{3})^2\).
This fundamental approach in algebra makes problem-solving intuitive and logical.
Quadratic Expression
Quadratic expressions are a crucial part of algebra, characterized by the standard form \( ax^2 + bx + c \).
Quadratics can describe curves such as parabolas and are used in solving equations where variables are squared. The given expression, \(x^{2} + \frac{2}{3}x + \frac{1}{9}\), is an example of a quadratic expression.
Once the structure is recognized, especially if it's a special form like the perfect square trinomial, factoring into \((x + \frac{1}{3})^2\) becomes straightforward.
This process is essential for simplifying problems and finding solutions in more complex scenarios.
Quadratics can describe curves such as parabolas and are used in solving equations where variables are squared. The given expression, \(x^{2} + \frac{2}{3}x + \frac{1}{9}\), is an example of a quadratic expression.
- The term \(x^2\) represents the quadratic term
- \(\frac{2}{3}x\) as the linear term
- \(\frac{1}{9}\) as the constant term
Once the structure is recognized, especially if it's a special form like the perfect square trinomial, factoring into \((x + \frac{1}{3})^2\) becomes straightforward.
This process is essential for simplifying problems and finding solutions in more complex scenarios.
Other exercises in this chapter
Problem 81
Factor completely. $$12 x^{2}+10 x y-8 y^{2}$$
View solution Problem 82
Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$21 x^{2}-35 x y$$
View solution Problem 82
Factor using the formula for the sum or difference of two cubes. $$x^{3}-64$$
View solution Problem 82
Factor by grouping. $$10 x^{2}-12 x y+35 x y-42 y^{2}$$
View solution