Problem 82
Question
Describe and sketch the curve that has the given parametric equations. \(x=3 \log _{10}(t), y=5 \log _{10}(t)\)
Step-by-Step Solution
Verified Answer
The curve is a straight line with slope \( \frac{5}{3} \) through the origin.
1Step 1: Identify the Parametric Equations
The problem provides the parametric equations: \( x = 3 \log_{10}(t) \) and \( y = 5 \log_{10}(t) \). These equations use the same parameter \( t \), and \( \log_{10}(t) \) signifies the dependency of \( x \) and \( y \) on the logarithm base 10 of \( t \).
2Step 2: Understand the Domain
The domain for \( t \) in a logarithm function \( \log_{10}(t) \) is \( t > 0 \). This is because logarithms are defined only for positive values of \( t \). Thus, the parametric equations are evaluated for \( t > 0 \).
3Step 3: Express y in Terms of x
To find a relation between \( x \) and \( y \), we use the equations: \( x = 3 \log_{10}(t) \) and \( y = 5 \log_{10}(t) \). Solve the first equation for \( \log_{10}(t) \): \( \log_{10}(t) = \frac{x}{3} \). Substitute into the second equation: \( y = 5 \cdot \frac{x}{3} \).
4Step 4: Simplify the Relation
The equation \( y = \frac{5}{3}x \) describes the linear relation between \( y \) and \( x \). This shows that the curve is a straight line with slope \( \frac{5}{3} \). This line passes through the origin because if \( x = 0 \), then \( y = 0 \).
5Step 5: Sketch the Curve
The curve represented by the parametric equations is a straight line. It can be sketched on a coordinate plane with the line passing through the origin (0,0) and having a slope of \( \frac{5}{3} \). The line extends indefinitely in the first quadrant due to the condition \( t > 0 \).
Key Concepts
Logarithmic FunctionsDomain of a FunctionLinear EquationsCurve Sketching
Logarithmic Functions
Logarithmic functions are mathematical expressions used to find the exponent to which a base number is raised to produce a given number. The common logarithm has a base of 10, expressed as \( \log_{10}(t) \). In other words, if \( 10^x = t \), then \( x = \log_{10}(t) \). Logarithms are useful for solving problems that involve exponential relationships by transforming them into linear forms.
Logarithmic functions are involved in many real-world applications, like measuring pH levels in chemistry or calculating sound intensity in decibels. These functions have unique properties:
Logarithmic functions are involved in many real-world applications, like measuring pH levels in chemistry or calculating sound intensity in decibels. These functions have unique properties:
- Addition: \( \log_{10}(a) + \log_{10}(b) = \log_{10}(ab) \)
- Subtraction: \( \log_{10}(a) - \log_{10}(b) = \log_{10}(\frac{a}{b}) \)
- Power: \( \log_{10}(a^b) = b\log_{10}(a) \)
Domain of a Function
The domain of a function refers to all possible input values (usually referred to as \( x \)) for which the function is defined. For a logarithmic function \( \log_{10}(t) \), the domain is specifically restricted to values where \( t > 0 \). If \( t \) is zero or negative, the logarithmic function is undefined because it is not possible to raise 10 to any power to achieve a negative number or zero.
Domains ensure the function values remain real and valid. They are crucial for correctly defining a function and understanding the set of values that can be used as inputs:
Domains ensure the function values remain real and valid. They are crucial for correctly defining a function and understanding the set of values that can be used as inputs:
- Pay special attention when functions involve logarithms or square roots, as their domains often exclude non-positive values.
- Properly identifying the domain is essential for any function manipulation, ensuring the function remains valid under all operations.
Linear Equations
A linear equation is a mathematical expression that represents a straight line in a coordinate system. These equations take the form \( y = mx + b \), where \( m \) is the slope of the line and \( b \) is the y-intercept. Linear equations can describe many relationships between two variables, including our parametric example where \( y = \frac{5}{3}x \). This indicates a line passing through the origin with a slope of \( \frac{5}{3} \).
Key features of linear equations include:
Key features of linear equations include:
- The slope \( m \) describes the steepness and direction of the line. A positive slope means the line rises, while a negative slope indicates it falls as \( x \) increases.
- The y-intercept \( b \) is the value of \( y \) when \( x \) is zero, positioning the line vertically on the graph.
- In our exercise, since \( x = 0, y = 0 \), the line intersects the origin.
Curve Sketching
Curve sketching is an essential skill in mathematics involving drawing the graph of a function based on its equation or parametric description. A primary goal is to identify key features such as intercepts, slope, and domain to accurately represent the function on a graph.
For parametric equations \( x = 3 \log_{10}(t) \) and \( y = 5 \log_{10}(t) \), we first simplify to \( y = \frac{5}{3}x \). This indicates that the curve forms a straight line. Key pointers in sketching include:
For parametric equations \( x = 3 \log_{10}(t) \) and \( y = 5 \log_{10}(t) \), we first simplify to \( y = \frac{5}{3}x \). This indicates that the curve forms a straight line. Key pointers in sketching include:
- Determine the domain—in this case, t must be greater than zero.
- Recognize intercepts: for this straight line, it starts at the origin (0,0).
- Understand the general shape: with our linear relation, the graph remains a line with slope \( \frac{5}{3} \).
Other exercises in this chapter
Problem 81
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Describe and sketch the curve that has the given parametric equations. \(x=\log _{10}(t) / \log _{10}(2), y=3 t\)
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