Problem 82
Question
Compute the indefinite integrals. $$ \int \frac{2 x+5}{x} d x $$
Step-by-Step Solution
Verified Answer
The indefinite integral is \( 2x + 5 \ln |x| + C \).
1Step 1: Split the Fraction
Break down the given function into simpler terms by dividing each term of the numerator by the denominator. This gives us \[\int \left( \frac{2x}{x} + \frac{5}{x} \right) \, dx\] which simplifies to \[\int (2 + \frac{5}{x}) \, dx\].
2Step 2: Integrate Term by Term
Integrate each term of the function separately. The integral of a constant 2 is \[2x\]. The integral of \( \frac{5}{x} \) is \[5 \ln |x|\]. This uses the rule \( \int \frac{1}{x} \, dx = \ln |x| + C \).
3Step 3: Combine the Results
Combine the integrals of the terms to obtain the complete integral. Thus, the integral of the original expression is \[2x + 5 \ln |x| + C\], where \( C \) is the constant of integration.
Key Concepts
Fraction DecompositionTerm-by-Term IntegrationConstant of Integration
Fraction Decomposition
In calculus, simplifying complex fractions is a common step when dealing with integrals. This process usually involves breaking down a complicated fraction into simpler, more manageable terms. For example, in the given exercise, the fraction \( \frac{2x+5}{x} \) is split. Here's how you can do it:
- Separate each term of the numerator.
- Divide these terms individually by the denominator.
Term-by-Term Integration
Once you've decomposed your fraction, it's time to integrate each term separately. Integrating term-by-term lets you focus on simpler, individual functions rather than a complex whole:
- First, integrate the constant \(2\). For any constant \(a\), the rule is \(\int a \, dx = ax\).
- Next, handle the term \(\frac{5}{x}\). This follows the basic integral \(\int \frac{1}{x} \, dx = \ln |x|\).
Constant of Integration
The constant of integration, represented as \(C\), is a pivotal part of indefinite integrals. It emerges because integration can reverse derivatives, but it doesn't capture the constant vertical shifts of a function. Here's why it's important:
- When you calculate an indefinite integral, you're essentially finding a family of functions that could fit the original derivative.
- The constant \(C\) represents all possible vertical shifts of the resulting function.
- Every valid antiderivative of a function includes an arbitrary constant, due to this reason.
Other exercises in this chapter
Problem 81
Compute the indefinite integrals. $$ \int \frac{2 x-1}{3 x} d x $$
View solution Problem 81
Find the value of \(a \in[0,2 \pi]\) that maximizes \(\int_{0}^{a} \cos x d x\).
View solution Problem 82
Find \(a \in(0,2 \pi]\) such that $$ \int_{0}^{a} \sin x d x=0 $$
View solution Problem 83
Compute the indefinite integrals. $$ \int \frac{x+3}{x^{2}-9} d x $$
View solution