Problem 82
Question
A student who is in a great hurry to finish his laboratory work decides that his qualitative analysis unknown contains a metal ion from group 4 of Figure \(17.23 .\) He therefore tests his sample directly with \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4},\) skipping earlier tests for the metal ions in groups \(1,2,\) and 3 . He observes a precipitate and concludes that a metal ion from group 4 is indeed present. Why is this possibly an erroneous conclusion?
Step-by-Step Solution
Verified Answer
Group 1, 2, or 3 ions could also form a precipitate, causing a false positive.
1Step 1: Understand the Test Performed
The student is testing for the presence of metal ions using \((\mathrm{NH}_{4})_{2} \mathrm{HPO}_{4}\), which specifically reacts with metal ions from group 4 to form a precipitate. However, by skipping the tests for groups 1, 2, and 3, the student has skipped interactions that could also result in precipitates.
2Step 2: Recall Precipitation Reactions of Earlier Groups
Metal ions in groups 1, 2, and 3 can also form precipitates with certain reagents. If any of these ions are present in the sample, they may also react with \((\mathrm{NH}_{4})_{2} \mathrm{HPO}_{4}\) to form a precipitate. For instance, Group 3 cations like \( \text{Al}^{3+} \) can form precipitates under different conditions.
3Step 3: Evaluate Specificity of the Test
The precipitation with \((\mathrm{NH}_{4})_{2} \mathrm{HPO}_{4}\) is not specific to just the group 4 metal ions. If the student had first identified and removed ions from groups 1 to 3, the test would be more specific to group 4. Without this step, any metal ion capable of forming a precipitate may lead to a false conclusion.
4Step 4: Conclusion of the Error in Test Assumption
By directly testing for Group 4 ions and skipping earlier tests, the student assumes any precipitate confirms the presence of a Group 4 ion, which is incorrect. The precipitate could also be due to the presence of ions from Groups 1, 2, or 3.
Key Concepts
Precipitation ReactionsGroup Separation in Qualitative AnalysisMetal Ions Identification
Precipitation Reactions
Precipitation reactions are an essential part of qualitative analysis, especially when identifying metal ions in a solution. These reactions occur when two soluble salts react in a solution to form one or more insoluble products known as precipitates. This is a key method in identifying the presence of specific ions within a mixed sample.
- When a solution containing metal ions is mixed with a suitable reagent, an insoluble compound can form, allowing us to visually detect the ions present.
- Different metal ions will form unique precipitates with specific reagents due to differences in their chemical properties.
- The formation of a precipitate helps in narrowing down the possible metal ions present in the sample.
Group Separation in Qualitative Analysis
Qualitative analysis often involves group separation, a systematic approach to distinguish between different metal ions in a mixture. This is crucial for correctly identifying ions step by step.
- Metal ions are categorized into groups based on their common chemical properties and behaviors towards specific reagents.
- For example, groups 1 to 4 are separated through selective precipitation reactions that separate ions based on solubility differences.
- Each group is tested sequentially, ensuring that ions from earlier groups do not interfere in the detection of ions from later groups.
Metal Ions Identification
Metal ion identification using precipitation reactions is part of a larger framework in qualitative analysis. Correct identification relies on understanding both the reagents involved and the reactivity of different metal groups.
- Each group of metal ions reacts uniquely to specific reagents, allowing their identification through systematic steps.
- After separating the groups, specific tests, such as the one performed with \((\mathrm{NH}_{4})_{2} \mathrm{HPO}_{4}\), can be accurately used to conclusively identify the presence of particular metal ions.
- Skipping these steps, as seen in the student's approach, can result in misinterpretation because other metal ions might respond similarly to the test reagent, leading to incorrect identification.
Other exercises in this chapter
Problem 77
A solution containing several metal ions is treated with dilute HCl; no precipitate forms. The pH is adjusted to about \(1,\) and \(\mathrm{H}_{2} \mathrm{~S}\)
View solution Problem 80
Suggest how the cations in each of the following solution mixtures can be separated: (a) \(\mathrm{Na}^{+}\) and \(\mathrm{Cd}^{2+},(\mathbf{b}) \mathrm{Cu}^{2+
View solution Problem 83
Derive an equation similar to the Henderson-Hasselbalch equation relating the pOH of a buffer to the \(\mathrm{p} K_{b}\) of its base component.
View solution Problem 85
Furoic acid \(\left(\mathrm{HC}_{5} \mathrm{H}_{3} \mathrm{O}_{3}\right)\) has a \(K_{a}\) value of \(6.76 \times 10^{-4} \mathrm{at}\) \(25^{\circ} \mathrm{C}\
View solution