Problem 81
Question
You are asked to calibrate a spectrophotometer in the laboratory and collect the following data. Plot the data with concentration on the \(x\) -axis and absorbance on the \(y\) -axis. Draw the best straight line using the points on the graph (or do a least-squares or linear regression analysis using a computer program) and then write the equation for the resulting straight line. What is the slope of the line? What is the concentration when the absorbance is \(0.635 ?\) $$\begin{array}{ll} \hline \text { Concentration }(\mathrm{M}) & \text { Absorbance } \\ \hline 0.00 & 0.00 \\ 1.029 \times 10^{-3} & 0.257 \\ 2.058 \times 10^{-3} & 0.518 \\ 3.087 \times 10^{-3} & 0.771 \\ 4.116 \times 10^{-3} & 1.021 \\ \hline \end{array}$$
Step-by-Step Solution
VerifiedKey Concepts
Linear Regression Analysis
To perform a linear regression, one needs to plot the given data points onto a graph and calculate the line that minimizes the distance from all data points to the line. This line is commonly called the line of best fit.
Using software, like Excel, or statistical calculators, you can carry out linear regression analysis efficiently. The tool calculates the slope (\(m\)) and the intercept (\(c\)) of the line, yielding an equation in the form \(y = mx + c\). This equation helps predict the absorbance for unknown concentrations, providing a straightforward method to interpret spectrophotometer data.
Absorbance Measurement
Each data point on our graph of concentration versus absorbance represents a solution's visually measured absorbance. By plotting these points, the aim is to see how absorbance increases as concentration increases. Generally, this relationship is linear, meaning the plot should closely form a straight line.
Since the initial concentration is zero, the absorbance should naturally start at zero. As concentration rises, absorbance data points will climb, showing the trend that will aid in forming the best fit line through our key data points.
Concentration Determination
For instance, if we know an absorbance value and wish to find the corresponding concentration, we rearrange the line equation \(y = 0.248x\) to solve for \(x\) (concentration). Using \(0.635\) as the absorbance, you replace \(y\) and solve: \(x = \frac{0.635}{0.248}\).
This gives you the concentration \(x\), which is approximately\(2.56 \times 10^{-3}M\). Utilizing this method ensures that even if the samples vary in absorbance, their concentration can be accurately calculated.