Problem 81
Question
What is wrong with the following calculation? \( 0 = 0 + 0 + 0 + \cdot \cdot \cdot \) \( = (1 - 1) + (1 - 1) + (1 - 1) + \cdot \cdot \cdot \) \( = 1 - 1 + 1 - 1 + 1 - 1 + \cdot \cdot \cdot \) \( = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + \cdot \cdot \cdot \) \( = 1 + 0 + 0 + 0 + \cdot \cdot \cdot = 1 \) (Guido Ubaldus thought that this proved the existence of God because "something has been created out of nothing.")
Step-by-Step Solution
Verified Answer
The computation incorrectly assumes infinite series can be rearranged without changing the result.
1Step 1: Identify the Initial Expression
The exercise begins with the equation: \[ 0 = 0 + 0 + 0 + ext{...} \] This represents a series of zeros being summed indefinitely, which clearly equals zero.
2Step 2: Substitute Zeros with (1 - 1)
Each zero in the series is replaced with \((1 - 1)\), thus: \[ 0 = (1 - 1) + (1 - 1) + (1 - 1) + ext{...} \] This step is valid since \(1 - 1 = 0\).
3Step 3: Rearrange the Terms
The equation now insinuates rearranging the subtracted and added parts: \[ = 1 - 1 + 1 - 1 + 1 - 1 + ext{...} \] However, changing the order in an infinite series without proper convergence checks can produce incorrect results.
4Step 4: Group the Terms
The terms are now grouped differently: \[ = 1 + (-1 + 1) + (-1 + 1) + ext{...} \] This rearrangement assumes that the series can be split and recombined as finite sums, which is not necessarily true for an infinite series.
5Step 5: Evaluate the Grouped Expression
Assuming the grouping was correct, it yields:\[ = 1 + 0 + 0 + ext{...} = 1 \] This step incorrectly assumes that adding zeros to one results in one, while it actually results in zero as the original series was infinite.
6Step 6: Identify the Error
The error lies in the assumption that an infinite series can be arbitrarily rearranged without affecting convergence. Infinite series require rigorous treatment and cannot generally be rearranged without consequences.
Key Concepts
ConvergenceRearrangement of SeriesSummation of SeriesMathematical Errors
Convergence
In mathematics, convergence refers to the behavior of an infinite series as the number of terms increases. When we say a series converges, it means that as you add more and more terms, the total sum approaches a specific finite value.
For example, the series \( \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \) converges to 1. This is because as you continue to add the fractions, the sum gets closer and closer to 1 without ever exceeding it.
On the other hand, a diverging series will not approach any particular value as you add more terms; it may go to infinity or oscillate between values. Understanding whether a series converges is crucial, especially in cases like the exercise above, where the rearrangement of an alternating series can cause significant errors if its convergence is not established first.
For example, the series \( \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \) converges to 1. This is because as you continue to add the fractions, the sum gets closer and closer to 1 without ever exceeding it.
On the other hand, a diverging series will not approach any particular value as you add more terms; it may go to infinity or oscillate between values. Understanding whether a series converges is crucial, especially in cases like the exercise above, where the rearrangement of an alternating series can cause significant errors if its convergence is not established first.
Rearrangement of Series
The rearrangement of terms in an infinite series can deceive and lead to incorrect conclusions if not approached with care. In mathematics, especially in dealing with infinite series, rearranging terms is not as straightforward as it might seem with finite sums.
When a series is conditionally convergent, rearranging the terms can lead to a different sum. This is known as the Riemann rearrangement theorem.
When a series is conditionally convergent, rearranging the terms can lead to a different sum. This is known as the Riemann rearrangement theorem.
- A series is conditionally convergent if it converges but does not converge absolutely.
- An absolutely convergent series remains the same irrespective of rearrangement.
Summation of Series
Summation of series is the process of adding up the terms of a sequence. In the context of infinite series, this becomes more complex due to the infinite nature of the sequence.
Consider the geometric series, where each term is a constant multiple of the previous one. An example is: \(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots\).
This series converges and adds up to 2 because each subsequent fraction adds up to a smaller total that converges to a finite number as more terms are added.
In infinite series like the one in the original exercise, the apparent error in summation comes from assuming each small section of the series sums up independently, ignoring the implications of the infinite summation. The idea that an infinite series of zeros can sum up to one through incorrect grouping is a fundamental mistake.
Consider the geometric series, where each term is a constant multiple of the previous one. An example is: \(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots\).
This series converges and adds up to 2 because each subsequent fraction adds up to a smaller total that converges to a finite number as more terms are added.
In infinite series like the one in the original exercise, the apparent error in summation comes from assuming each small section of the series sums up independently, ignoring the implications of the infinite summation. The idea that an infinite series of zeros can sum up to one through incorrect grouping is a fundamental mistake.
Mathematical Errors
Mathematical errors in handling infinite series often arise from a misunderstanding of convergence and ordering. One common mistake is assuming an infinite series behaves like a finite sum.
In infinite series, grouping or rearranging can change the outcome unless the series converges absolutely.
Another common error lies in misinterpreting the infinite nature of series. For instance, as shown in the original exercise, replacing zeros with \(1 - 1\) did not change the series inherently, but the steps that followed contained logical missteps.
In infinite series, grouping or rearranging can change the outcome unless the series converges absolutely.
Another common error lies in misinterpreting the infinite nature of series. For instance, as shown in the original exercise, replacing zeros with \(1 - 1\) did not change the series inherently, but the steps that followed contained logical missteps.
- Firstly, it misunderstood convergence by rearranging terms without considering the implications.
- Secondly, it improperly grouped terms under the assumption that adding infinitely many zeros to one could result in one, whereas the infinite context invalidated that logic.
Other exercises in this chapter
Problem 79
Find the limit of the sequence \( \left\\{ \sqrt 2, \sqrt{2\sqrt2}, \sqrt{2\sqrt{2\sqrt2}}, \cdot \cdot \cdot \right\\} \)
View solution Problem 80
A sequence \( \left\\{ a_n \right\\} \) is given by \( a_1 = \sqrt 2, a_{n + 1} = \sqrt {2 + a_n}. \) (a) By induction or otherwise, show that \( \left\\{ a_n \
View solution Problem 81
Show that the sequence defined by \( a_1 = 1 \) \( a_{n + 1} = 3 - \frac{1}{a_n} \) is increasing and \( a_n
View solution Problem 82
If \(f(x)=\left(1+x^{3}\right)^{30},\) what is \(f^{(5)}(0) ?\)
View solution