Problem 81
Question
Water has a density of \(0.997 \mathrm{~g} / \mathrm{cm}^{3}\) at \(25^{\circ} \mathrm{C} ;\) ice has a density of \(0.917 \mathrm{~g} / \mathrm{cm}^{3}\) at \(-10^{\circ} \mathrm{C} .\) (a) If a soft-drink bottle whose volume is \(1.50 \mathrm{~L}\) is completely filled with water and then frozen to \(-10^{\circ} \mathrm{C},\) what volume does the ice occupy? (b) Can the ice be contained within the bottle?
Step-by-Step Solution
Verified Answer
(a) Ice occupies approximately 1630.64 cm³. (b) No, the ice cannot be contained within the bottle.
1Step 1: Convert Volume to Consistent Units
The given volume of the bottle is in liters, but the densities of water and ice are given in grams per cubic centimeter. We need to convert the volume of the bottle from liters to cubic centimeters. Since 1 liter is equal to 1000 cubic centimeters, we convert 1.50 liters to cubic centimeters: \[ 1.50 \text{ L} = 1.50 \times 1000 \text{ cm}^3 = 1500 \text{ cm}^3. \]
2Step 2: Calculate the Mass of Water
The mass of water in the bottle can be calculated using the density of water and the volume of the bottle. The formula for mass is given by: \[ \text{mass} = \text{density} \times \text{volume}. \] Substitute the given density of water (0.997 g/cm³) and the volume we converted: \[ \text{mass} = 0.997 \text{ g/cm}^3 \times 1500 \text{ cm}^3 = 1495.5 \text{ g}. \]
3Step 3: Determine the Volume of Ice
The mass of the ice will be the same as the mass of the water because mass is conserved in this process. To find the volume that this mass of ice occupies, we use the ice density: \[ \text{volume of ice} = \frac{\text{mass}}{\text{density}}. \] Using the mass of 1495.5 g and the density of ice (0.917 g/cm³): \[ \text{volume of ice} = \frac{1495.5 \text{ g}}{0.917 \text{ g/cm}^3} \approx 1630.64 \text{ cm}^3. \]
4Step 4: Analyze Whether Ice Fits in the Bottle
The volume of the bottle is 1500 cm³, but the volume of ice is approximately 1630.64 cm³. As the volume of ice is greater than the volume of the bottle, the ice cannot be fully contained within 1.50 L bottle.
Key Concepts
Volume ConversionMass CalculationPhase Change
Volume Conversion
When working with different units, it's essential to ensure consistency, particularly in science. In this scenario, we have a volume measured in liters, while densities are provided in grams per cubic centimeter. To resolve this disparity, we convert all measurements to a single unit.
A liter is equivalent to 1000 cubic centimeters (cm³). This conversion factor is crucial. By applying it to the bottle's volume of 1.50 liters, we find the volume in cubic centimeters:
A liter is equivalent to 1000 cubic centimeters (cm³). This conversion factor is crucial. By applying it to the bottle's volume of 1.50 liters, we find the volume in cubic centimeters:
- 1 liter = 1000 cm³
- 1.50 liters = 1.50 x 1000 = 1500 cm³
Mass Calculation
After converting the volume, calculating the mass of a substance requires understanding the relationship between mass, density, and volume. The formula is \[ \text{mass} = \text{density} \times \text{volume}. \] In this case, using the density of water (\(0.997 \text{ g/cm}^3\)) and the volume (\(1500 \text{ cm}^3\)) allows us to find the mass of the water:
- Mass = 0.997 g/cm³ x 1500 cm³
- Mass = 1495.5 g
Phase Change
Phase change refers to the transition between different states of matter, such as from liquid to solid. During this process, the mass is conserved, meaning it doesn't change, but volume can vary significantly due to different densities in each state.
Consider water freezing into ice. To find out how much space ice occupies, you apply the formula: \[ \text{volume of ice} = \frac{\text{mass}}{\text{density}}. \] With a mass of 1495.5 g and the density of ice (\(0.917 \text{ g/cm}^3\)), we find:
Consider water freezing into ice. To find out how much space ice occupies, you apply the formula: \[ \text{volume of ice} = \frac{\text{mass}}{\text{density}}. \] With a mass of 1495.5 g and the density of ice (\(0.917 \text{ g/cm}^3\)), we find:
- Volume of ice = 1495.5 g / 0.917 g/cm³
- Volume of ice ≈ 1630.64 cm³
Other exercises in this chapter
Problem 78
Suppose you decide to define your own temperature scale with units of \(\mathrm{O}\), using the freezing point \(\left(13^{\circ} \mathrm{C}\right)\) and boilin
View solution Problem 79
Hexane (density \(=0.659 \mathrm{~g} / \mathrm{mL}\) ) and acetic acid (density = \(1.0446 \mathrm{~g} / \mathrm{mL}\) ) do not form a solution when mixed but a
View solution Problem 82
A \(32.65-g\) sample of a solid is placed in a flask. Toluene, in which the solid is insoluble, is added to the flask so that the total volume of solid and liqu
View solution Problem 83
A thief plans to steal a cylindrical platinum medal with a radius of \(2.3 \mathrm{~cm}\) and a thickness of \(0.8 \mathrm{~cm}\) from a jewellery store. If the
View solution