Problem 81
Question
Use a graphing utility to graph the function. Use the graph to determine whether the function has an inverse that is a function (that is, whether the function is one-to-one). $$f(x)=|x-2|$$
Step-by-Step Solution
Verified Answer
By graphing the function \(f(x) = |x-2|\), we see that the graph increases to the left and right of the point (2,0). Applying the Horizontal Line Test, we find that any horizontal line will touch the graph at more than one point. Therefore, the function is not one-to-one and does not have an inverse that is also a function.
1Step 1: Graphing the Function
Construct the graph of the given function \(f(x) = |x-2|\). This is an absolute function which is shifted 2 units to the right. Hence, the graph should reflect this shift. The graph should increase to the left and right of the point (2,0).
2Step 2: Applying the Horizontal Line Test
Now, apply the Horizontal Line Test to check if the function is one-to-one. This test is done by imagining or drawing a horizontal line on the graph, then checking if that line touches the graph at more than one point.
3Step 3: Interpreting the Result
If the horizontal line touches the graph at only one point, the function passes the test and therefore, has an inverse that is also a function indicating it as one-to-one. However, if the line touches the graph at more than one point, then the function is not one-to-one and does not have an inverse that is a function.
Other exercises in this chapter
Problem 80
Find the value of \(y\) if the line through the two given points is to have the indicated slope. (-2, y) \text { and }(4,-4), m=\frac{1}{3}
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Does \((x-3)^{2}+(y-5)^{2}=-25\) represent the equation of a circle? What sort of set is the graph of this equation?
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write a piecewise function that models each cellphone billing plan. Then graph the function. \(\$ 50\) per month buys 400 minutes. Additional time costs \(\$ 0.
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Express the given function \(h\) as a composition of two functions \(f\) and \(g\) so that \(h(x)=(f \circ g)(x)\). $$h(x)=\frac{1}{2 x-3}$$
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