Problem 81
Question
Simplify. Write the result in the form \(a+b i\) $$ (6-8 i)^{2} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-28 - 96i\).
1Step 1: Identify the Expression
We are given the expression \((6 - 8i)^2 \)which needs to be simplified and written in the form \(a + bi\).
2Step 2: Apply the Formula for Squaring a Binomial
Recall the formula \((a-b)^2 = a^2 - 2ab + b^2\).Apply it here: \((6 - 8i)^2 = 6^2 - 2(6)(8i) + (8i)^2\).
3Step 3: Calculate Each Term
Compute each term separately:- \(6^2 = 36\)- \(-2(6)(8i) = -96i\)- \((8i)^2 = 64i^2\). Remember that \(i^2 = -1\), so \((8i)^2 = 64(-1) = -64\).
4Step 4: Simplify the Expression
Substitute the calculated terms back into the expression:\(36 - 96i - 64\). Combine like terms: the real parts \(36 - 64 = -28\) and the imaginary part \(-96i\) stays the same.
5Step 5: Write the Answer in Standard Form
The simplified form of the expression is:\(-28 - 96i\). This is already in the form \(a + bi\), where \(a = -28\) and \(b = -96\).
Key Concepts
Binomial SquaringImaginary UnitSimplifying Expressions
Binomial Squaring
Binomial squaring is a fundamental mathematical technique often used for expanding expressions of the form \((a-b)^2\) or \((a+b)^2\). Understanding this is crucial when working with complex numbers. The general formula for squaring a binomial is given by:
- \((a-b)^2 = a^2 - 2ab + b^2\)
- \((a+b)^2 = a^2 + 2ab + b^2\)
Imaginary Unit
The imaginary unit, commonly denoted as \(i\), represents the square root of \(-1\). This is a cornerstone concept in complex numbers, making it possible to extend the real number system. This magical unit helps solve equations that don't have solutions within the realm of real numbers.Here are a few properties to remember:
- \(i^2 = -1\)
- \(i^3 = -i\)
- \(i^4 = 1\)
Simplifying Expressions
Simplifying expressions, especially those involving complex numbers, requires special care to combine like terms correctly. Begin with calculating the numerical values for real and imaginary parts. Here's how you can methodically simplify them:1. **Compute Each Component**: Each part of a binomial is calculated separately. - For real numbers, compute using basic arithmetic rules. - Use the imaginary unit properties for imaginary numbers.2. **Combine Like Terms**: Gather all real numbers and combine them. Next, do the same for imaginary numbers. This often involves algebraically adding or subtracting these components.For instance, with the expression \((6 - 8i)^2\), once expanded and calculated, it becomes \(36 - 96i - 64\). Following your mathematical operations, combine the real parts, resulting in \(36 - 64 = -28\), and then process the imaginary part, \(-96i\).Finally, ensure the simplified expression is in the standard form \(a + bi\), which in this case is \(-28 - 96i\). Grasping these steps guarantees that your results are both accurate and easy to interpret.
Other exercises in this chapter
Problem 81
Write each logarithmic expression as one logarithm. See Example 7. $$ \frac{1}{3}\left[\log _{b}\left(M^{2}-9\right)-\log _{b}(M+3)\right] $$
View solution Problem 81
Solve each equation. Give the exact solution and, when appropriate, an approximation to four decimal places. $$ 2 \log _{2} x=3+\log _{2}(x-2) $$
View solution Problem 82
Bed Bugs. If not checked, the population of a colony of bed bugs will grow exponentially at a rate of \(65 \%\) per week. If a colony currently has 50 bedbugs,
View solution Problem 82
Write each logarithmic expression as one logarithm. See Example 7. $$ \frac{1}{4}\left[\log _{r}\left(n^{2}-16\right)-\log _{r}(n-4)\right] $$
View solution