Problem 81
Question
Recall from Section \(3.4\) that given a complex number \(z=a+b i\) its complex conjugate, denoted \(\bar{z}\), is given by \(\bar{z}=a-b i\) (a) Prove that \(|\bar{z}|=|z|\). (b) Prove that \(|z|=\sqrt{z \bar{z}}\) (c) Show that \(\operatorname{Re}(z)=\frac{z+\bar{z}}{2}\) and \(\operatorname{Im}(z)=\frac{z-\bar{z}}{2 i}\) (d) Show that if \(\theta \in \arg (z)\) then \(-\theta \in \arg (\bar{z})\). Interpret this result geometrically. (e) Is it always true that \(\operatorname{Arg}(\bar{z})=-\operatorname{Arg}(z) ?\)
Step-by-Step Solution
Verified Answer
(a) \(|\bar{z}|=|z|\); (b) \(|z|=\sqrt{z\bar{z}}\); (c) \(\operatorname{Re}(z)=\frac{z+\bar{z}}{2}\), \(\operatorname{Im}(z)=\frac{z-\bar{z}}{2i}\); (d) \(-\theta \in \arg (\bar{z})\); (e) Not always.
1Step 1: Prove that \(|\bar{z}|=|z|\)
Given a complex number \(z = a + bi\), its conjugate is \(\bar{z} = a - bi\). The magnitude of \(z\) is \(|z| = \sqrt{a^2 + b^2}\) and the magnitude of \(\bar{z}\) is \(|\bar{z}| = \sqrt{a^2 + (-b)^2} = \sqrt{a^2 + b^2}\). Thus, \(|\bar{z}| = |z|\).
2Step 2: Prove that \(|z|=\sqrt{z \bar{z}}\)
We have \(z = a + bi\) and \(\bar{z} = a - bi\). The product \(z \bar{z} = (a + bi)(a - bi) = a^2 - (bi)^2 = a^2 + b^2\) since \(i^2 = -1\). Therefore, \(\sqrt{z \bar{z}} = \sqrt{a^2 + b^2} = |z|\).
3Step 3: Show \(\operatorname{Re}(z)=\frac{z+\bar{z}}{2}\) and \(\operatorname{Im}(z)=\frac{z-\bar{z}}{2i}\)
For \(z = a + bi\) and \(\bar{z} = a - bi\), the real part is \(\operatorname{Re}(z) = a\). Calculating \(\frac{z+\bar{z}}{2} = \frac{(a+bi) + (a-bi)}{2} = \frac{2a}{2} = a\). For the imaginary part, \(\operatorname{Im}(z) = b\), and \(\frac{z - \bar{z}}{2i} = \frac{(a+bi)-(a-bi)}{2i} = \frac{2bi}{2i} = b\).
4Step 4: Show \(-\theta \in \arg (\bar{z})\) if \(\theta \in \arg (z)\)
If \(z = re^{i\theta}\), where \(r = |z|\) and \(\theta = \arg(z)\), then \(\bar{z} = re^{-i\theta}\). Thus \(\arg(\bar{z}) = -\theta\), interpreting geometrically means the conjugate reflects across the real axis.
5Step 5: Determine if \(\operatorname{Arg}(\bar{z})=-\operatorname{Arg}(z)\) is always true
The principal argument \(\operatorname{Arg}(z)\) usually takes values in \((-\pi, \pi]\). For \(\bar{z}\), the principal argument is \(-\theta\), which is in \((-\pi, \pi]\), thus \(\operatorname{Arg}(\bar{z})\) can equal \(-\operatorname{Arg}(z)\), but due to angles wrapping around, it is not always \(-\theta\) exactly.
Key Concepts
Complex ConjugateModulus of a Complex NumberReal and Imaginary Parts of Complex NumbersArgument of a Complex Number
Complex Conjugate
To get the complex conjugate of a complex number, flip the sign of the imaginary part. For example, for a complex number \( z = a + bi \), its conjugate is \( \bar{z} = a - bi \). This switch in sign is useful in various mathematical operations.
- It is used to simplify the division of complex numbers.
- It plays a critical role in finding the modulus (or absolute value) of complex numbers.
- Conjugates help by 'focusing' the point exactly opposite across the real axis.
Modulus of a Complex Number
The modulus of a complex number can be thought of as its "distance" from the origin in the complex plane. For a complex number \( z = a + bi \), its modulus is denoted as \( |z| \) and calculated by the formula:\[ |z| = \sqrt{a^2 + b^2} \]
- This is the geometric length of the vector represented by the complex number.
- The modulus is always a non-negative number.
- It embodies the Pythagorean theorem in the plane of complex numbers, relating length directly to its components.
Real and Imaginary Parts of Complex Numbers
Each complex number \( z = a + bi \), contains a real part \(\operatorname{Re}(z)\) and an imaginary part \(\operatorname{Im}(z)\). These can be extracted using:
- The real part: \( \operatorname{Re}(z) = \frac{z + \bar{z}}{2} \)
- The imaginary part: \( \operatorname{Im}(z) = \frac{z - \bar{z}}{2i} \)
- The real part works as a "horizontal" shift on the complex plane.
- The imaginary represents the "vertical" movement.
Argument of a Complex Number
The argument of a complex number is the angle \( \theta \) that the complex number's 'position vector' makes with the positive real axis. Notation used for this is \( \arg(z) \) for any complex number \( z \). If \( z = re^{i\theta} \), then \( \theta \) is the angle made by the line connecting the origin with the point \( (a, b) \).
- It typically ranges from \( -\pi \) to \( \pi \).
- This angle helps position any complex number within a unit circle.
- The principal argument is the specific angle used within this standard range.
Other exercises in this chapter
Problem 80
Convert the equation from polar coordinates into rectangular coordinates. $$ \theta=\frac{2 \pi}{3} $$
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Convert the equation from polar coordinates into rectangular coordinates. $$ \theta=\frac{2 \pi}{3} $$
View solution Problem 82
Convert the equation from polar coordinates into rectangular coordinates. $$ \theta=\pi $$
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Given any natural number \(n \geq 2\), the \(n\) complex \(n^{\text {th }}\) roots of the number \(z=1\) are called the \(\boldsymbol{n}^{\text {th }}\) Roots o
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