Problem 81
Question
Rationalize each denominator. All variables represent positive real numbers. $$ \sqrt[3]{\frac{4}{81}} $$
Step-by-Step Solution
Verified Answer
The rationalized expression is \( \frac{\sqrt[3]{36}}{3} \).
1Step 1: Identify the Expression
We have the expression \( \sqrt[3]{\frac{4}{81}} \). Here, the goal is to rationalize the denominator such that there are no cube roots.
2Step 2: Separate the Fractional Cube Root
Express the cube root of the fraction as the quotient of cube roots: \( \frac{\sqrt[3]{4}}{\sqrt[3]{81}} \).
3Step 3: Simplify the Denominator
Recognize that \( 81 = 3^4 \) and therefore, \( \sqrt[3]{81} = (3^4)^{\frac{1}{3}} = 3^{\frac{4}{3}} = 3 \cdot \sqrt[3]{3} \).
4Step 4: Rationalize the Denominator
Multiply both the numerator and the denominator by \( \sqrt[3]{9} = (3^2)^{\frac{1}{3}} \) to eliminate the cube root in the denominator. This gives:\[ \frac{\sqrt[3]{4} \cdot \sqrt[3]{9}}{\sqrt[3]{81} \cdot \sqrt[3]{9}} = \frac{\sqrt[3]{36}}{3} \].
5Step 5: Write the Simplified Expression
The rationalized expression is \( \frac{\sqrt[3]{36}}{3} \), where \( 3 \) is free of any cube roots.
Key Concepts
Cube RootsFractional ExponentsSimplifying Expressions
Cube Roots
When we talk about cube roots, we're exploring how to find a number that, when multiplied by itself twice, gives the original number. For example, the cube root of 8 is 2 because 2 multiplied by itself three times (2 × 2 × 2) equals 8.
Cube roots are represented using the radical symbol with a small 3, like this: \( \sqrt[3]{x} \). In our exercise, we deal with the cube root \( \sqrt[3]{\frac{4}{81}} \), which asks us to determine the cube root of the entire fraction.
To handle a fractional cube root, each part of the fraction can be treated separately, giving us \( \frac{\sqrt[3]{4}}{\sqrt[3]{81}} \).
This step compartmentalizes the cube root problem, allowing us to address the numerator and denominator individually, making it easier to conjugate the cube root.
Cube roots are represented using the radical symbol with a small 3, like this: \( \sqrt[3]{x} \). In our exercise, we deal with the cube root \( \sqrt[3]{\frac{4}{81}} \), which asks us to determine the cube root of the entire fraction.
To handle a fractional cube root, each part of the fraction can be treated separately, giving us \( \frac{\sqrt[3]{4}}{\sqrt[3]{81}} \).
This step compartmentalizes the cube root problem, allowing us to address the numerator and denominator individually, making it easier to conjugate the cube root.
Fractional Exponents
Fractional exponents are another way to express roots. When you see an exponent like \( x^{m/n} \), it means taking the \( n^{th} \) root of \( x \), and then raising the result to the \( m^{th} \) power.
For instance, \( x^{1/3} \) indicates the cube root of \( x \): \( \sqrt[3]{x} \).
So when simplifying our expression \( \sqrt[3]{81} \), we convert it to its fractional exponent form \( (81)^{1/3} \). Recognizing that 81 is \( 3^4 \), we can write \( 81^{1/3} \) as \( (3^4)^{1/3} = 3^{4/3} = 3 \times 3^{1/3} \).
This step illustrates the value of understanding fractional exponents, particularly in breaking down complex roots into more manageable parts.
For instance, \( x^{1/3} \) indicates the cube root of \( x \): \( \sqrt[3]{x} \).
So when simplifying our expression \( \sqrt[3]{81} \), we convert it to its fractional exponent form \( (81)^{1/3} \). Recognizing that 81 is \( 3^4 \), we can write \( 81^{1/3} \) as \( (3^4)^{1/3} = 3^{4/3} = 3 \times 3^{1/3} \).
This step illustrates the value of understanding fractional exponents, particularly in breaking down complex roots into more manageable parts.
Simplifying Expressions
Once our fraction is broken into parts, the focus shifts to simplifying the expression to make it easier to work with. Our goal with rationalizing denominators, as outlined in the exercise, is to eliminate roots from the denominator entirely.
After separating \( \frac{\sqrt[3]{4}}{\sqrt[3]{81}} \), and knowing that \( \sqrt[3]{81} = 3 \times \sqrt[3]{3} \), we need to multiply both the numerator and denominator by \( \sqrt[3]{9} \) — which corresponds to \( (3^2)^{1/3} \).
This allows us to cancel out the cube root of the denominator. The simplification yields \( \frac{\sqrt[3]{36}}{3} \). The process simplifies further, if needed, to ensure the denominator is a simple whole number, devoid of cubic roots, culminating in a more refined and practical expression for use in further calculations.
After separating \( \frac{\sqrt[3]{4}}{\sqrt[3]{81}} \), and knowing that \( \sqrt[3]{81} = 3 \times \sqrt[3]{3} \), we need to multiply both the numerator and denominator by \( \sqrt[3]{9} \) — which corresponds to \( (3^2)^{1/3} \).
This allows us to cancel out the cube root of the denominator. The simplification yields \( \frac{\sqrt[3]{36}}{3} \). The process simplifies further, if needed, to ensure the denominator is a simple whole number, devoid of cubic roots, culminating in a more refined and practical expression for use in further calculations.
Other exercises in this chapter
Problem 81
Simplify each expression. Write the answers without negative exponents. All variables represent positive real numbers. See Example 8. $$ \left(m^{2 / 3} m^{1 /
View solution Problem 81
Divide. Write all answers in the form \(a+b i.\) $$ \frac{8+\sqrt{-144}}{2+\sqrt{-9}} $$
View solution Problem 81
Simplify each expression, if possible. All variables represent positive real numbers. $$ \sqrt{\frac{125 n^{5}}{64 n}} $$
View solution Problem 82
Solve each equation. Write all proposed solutions. Cross out those that are extraneous. $$ 4=\sqrt{x+8}-\sqrt{x}+2 $$
View solution