Problem 81
Question
If \(a_{1}, a_{2}\) \(a_{3}, \ldots\) is an arithmetic sequence with common difference \(d\) show that the sequence $$10^{a_{1}}, 10^{a_{2}}, 10^{a_{3}}, \dots$$ is a geometric sequence, and find the common ratio.
Step-by-Step Solution
Verified Answer
The sequence is geometric with a common ratio of \(10^d\).
1Step 1: Understanding the Arithmetic Sequence
An arithmetic sequence has the form \( a_1, a_2, a_3, \ldots \), where each term is given by \( a_n = a_1 + (n-1)d \). Here, \(d\) is the common difference between consecutive terms.
2Step 2: Finding General Terms
From the arithmetic sequence, the \(n\)-th term is \( a_n = a_1 + (n-1)d \). Therefore, the \(n\)-th term of the new sequence is \( 10^{a_n} = 10^{a_1 + (n-1)d} \).
3Step 3: Recognizing a Geometric Sequence
A sequence is geometric if the ratio of consecutive terms is constant. Compute the ratio \( \frac{10^{a_{n+1}}}{10^{a_n}} \).
4Step 4: Calculating the Common Ratio
Using properties of exponents, \( \frac{10^{a_{n+1}}}{10^{a_n}} = \frac{10^{a_1 + nd}}{10^{a_1 + (n-1)d}} = 10^{a_1 + nd - a_1 - (n-1)d} = 10^d \).
5Step 5: Conclusion on Common Ratio
The ratio \( 10^d \) is constant for all \(n\), confirming the sequence is geometric with common ratio \( 10^d \).
Key Concepts
Arithmetic SequenceGeometric SequenceCommon DifferenceCommon Ratio
Arithmetic Sequence
An arithmetic sequence is a series of numbers in which each term increases by a constant amount, known as the common difference. For example, in the sequence 2, 4, 6, 8, 10, each number is obtained by adding 2 to the previous one. Here's how an arithmetic sequence can be understood:
- The first term is denoted by \(a_1\).
- Each subsequent term is calculated by adding the common difference \(d\) to the preceding term.
Geometric Sequence
A geometric sequence is quite different from an arithmetic one. Here, each term is derived by multiplying the previous term by a constant known as the common ratio. Consider the sequence 3, 9, 27, 81. Each term is obtained by multiplying the preceding term by 3. Characteristics of a geometric sequence include:
- The first term, \(a_1\).
- Each next term is found by multiplying the previous term by the common ratio \(r\).
Common Difference
The common difference in an arithmetic sequence plays a crucial role. It is the fixed amount added to each term to get the next term. To determine the common difference in a simple sequence, subtract the previous term from the current one. For instance, in the sequence 5, 10, 15, the common difference \(d\) is 5, because each term increases by 5.
Recognizing the common difference helps in constructing the rule \(a_n = a_1 + (n-1)d\), which is instrumental in solving problems related to arithmetic sequences and predicting unknown terms efficiently.
Recognizing the common difference helps in constructing the rule \(a_n = a_1 + (n-1)d\), which is instrumental in solving problems related to arithmetic sequences and predicting unknown terms efficiently.
Common Ratio
In a geometric sequence, the common ratio is a constant multiplier used to find the subsequent term from the preceding one. It is crucial in identifying a sequence as geometric. To find the common ratio \(r\), simply divide any term by its previous term.
- Example: In the sequence 2, 6, 18, 54, the common ratio \(r\) is 3, since each term is obtained by multiplying the previous term by 3.
- Working with exponential sequences, like \(10^{a_1}, 10^{a_2}, 10^{a_3}, \ldots\), a sequence can transform into a geometric one where \(10^d\) becomes the common ratio if the original values form an arithmetic sequence.
Other exercises in this chapter
Problem 80
If \(a_{1}, a_{2}, a_{3}, \ldots\) is a geometric sequence with a common ratio \(r>0\) and \(a_{1}>0,\) show that the sequence $$\log a_{1}, \log a_{2}, \log a_
View solution Problem 80
A Different Type of Recursion Find the first 10 terms of the sequence defined by $$ a_{n}=a_{n-a_{n-1}}+a_{n-a_{n-2}} $$ with $$ a_{1}=1 \quad \text { and } \qu
View solution Problem 78
Different Sequences That Start the Same (a) Show that the first four terms of the sequence \(a_{n}=n^{2}\) are $$ 1,4,9,16, \dots $$ (b) Show that the first fou
View solution