Problem 81
Question
Find each power of \(i\). $$ (-3 i)^{5} $$
Step-by-Step Solution
Verified Answer
(-3i)^5 = -243i.
1Step 1: Identify the Properties of i
The imaginary unit \(i\) is defined such that \(i^2 = -1\). Therefore, powers of \(i\) repeat in a cycle: \(i^1 = i\), \(i^2 = -1\), \(i^3 = -i\), and \(i^4 = 1\). This cycle repeats every four powers.
2Step 2: Simplify the Base
The expression is \((-3i)^5\), where \(-3i\) can be considered as a single unit. First express it as \((-1)^5 \times 3^5 \times i^5\), which simplifies to \(-243i^5\).
3Step 3: Find i^5 Using Cycle
From the cycle of powers of \(i\), \(i^5\) is the same as \(i^{4+1} = i^4 \times i^1 = 1 \times i = i\).
4Step 4: Calculate the Final Expression
Substitute the last result into the expression: \(-243i^5 = -243i\). Therefore, \((-3i)^5 = -243i\).
Key Concepts
Imaginary UnitComplex NumbersAlgebraic Expressions
Imaginary Unit
When diving into the world of complex numbers, one of the first concepts you'll encounter is the imaginary unit, denoted as \(i\). This unit is a fundamental building block in the realm of complex numbers. Its defining property is quite intriguing: \(i^2 = -1\). Hence, the imaginary unit helps us extend the real number system to tackle operations that are otherwise not possible, like taking the square root of negative numbers.
A unique feature of \(i\) is the cycle it creates when raised to different powers. This cycle repeats every four exponents:
A unique feature of \(i\) is the cycle it creates when raised to different powers. This cycle repeats every four exponents:
- \(i^1 = i\)
- \(i^2 = -1\)
- \(i^3 = -i\)
- \(i^4 = 1\)
Complex Numbers
Complex numbers are an extension of the real numbers. They include a component involving the imaginary unit \(i\). A complex number is generally represented in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit.
These numbers add a second dimension to the number line, allowing for advanced computations. For instance, operations like addition and multiplication can be uniformly applied with real numbers, but need special attention with the involvement of \(i\).
In the context of our problem,
These numbers add a second dimension to the number line, allowing for advanced computations. For instance, operations like addition and multiplication can be uniformly applied with real numbers, but need special attention with the involvement of \(i\).
In the context of our problem,
- We encountered an expression involving complex numbers: \((-3i)^5\).
- By treating it as a single complex number, we could systematically decompose the expression, using properties of powers, to simplify it.
Algebraic Expressions
Algebraic expressions can become quite complex when they involve powers of \(i\). The key to managing these expressions is a solid understanding of the properties of \(i\) and how it behaves in algebraic operations.
Suppose you have an expression like our original exercise, \((-3i)^5\). This expression combines real and imaginary components, requiring a strategic approach for simplification.
Suppose you have an expression like our original exercise, \((-3i)^5\). This expression combines real and imaginary components, requiring a strategic approach for simplification.
- First, break it down using the properties of exponentiation and the cycle of \(i\).
- This means expressing it as \((-1)^5 \times 3^5 \times i^5\).
- The breakdown helps separate the real part, \(-243\), from the imaginary power, \(i^5\), which reduces to \(i\) using the cycle.
Other exercises in this chapter
Problem 81
Find the distance between each pair of points. Give an exact distance and a three-decimal-place approximation. (-9,4) and (-8,1)
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Factor each numerator and denominator. Then simplify if possible. $$ \frac{6 a^{2} b-9 a b}{3 a b} $$
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Explain why rationalizing the numerator does not change the value of the original expression.
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Simplify. $$ \frac{\frac{1}{y}+\frac{4}{5}}{\frac{-3}{20}} $$
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