Problem 81
Question
(a) When 1 -chloro-2-pentene is reacted with concentrated solution of sodium ethoxide, the rate of reaction depends on the concentration of both allylhalide and ethoxide ion. The product of reaction is exclusively $$ \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OC}_{2} \mathrm{H}_{5} $$ (b) In dilute solution of sodium ethoxide, the reaction rate is dependent only on the concentration of allylhalide. (c) In the presence of traces of water, 1 -chloro-2-pentene is slowly converted to a mixture of 1 -chloro-2-pentene and 3-chloro-1-pentene In case (a) the mechanism exclusively followed by reaction is (a) \(\mathrm{S}_{\mathrm{N}} 1\) (b) \(\mathrm{S}_{\mathrm{N}} 2\) (c) \(\mathrm{E}\) (d) \(\mathrm{E}_{2}\)
Step-by-Step Solution
VerifiedKey Concepts
Nucleophilic Substitution
There are two main types of nucleophilic substitution mechanisms: \(\mathrm{S}_{\mathrm{N}}1\) and \(\mathrm{S}_{\mathrm{N}}2\). The term \(\mathrm{S}_{\mathrm{N}}2\) stands for bimolecular nucleophilic substitution, with the '2' indicating that two species are involved in the rate-determining step. This matches part (a) of the problem, where the reaction rate relies on both the concentration of the allyl halide and the ethoxide ion.
This type of reaction is concerted, meaning that the bond between the nucleophile and the carbon is forming, while the bond between the carbon and the leaving group is breaking simultaneously, resulting in a transition state with partial bond character.
Allyl Halide
In the given exercise, 1-chloro-2-pentene acts as the allyl halide. The presence of the double bond in 1-chloro-2-pentene provides electron-withdrawing characteristics that stabilize negative charges through resonance. This stabilization makes the allylic position particularly suitable for nucleophilic attacks. Hence, the allylic chlorine in 1-chloro-2-pentene is the ideal target for ethoxide, the nucleophile in the reaction.
The result is a product where the allylic chlorine has been substituted by the ethoxy group \(-OC_2H_5\), leading to \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}\mathrm{OC}_{2} \mathrm{H}_{5}\).
Reaction Kinetics
In a concentrated solution of sodium ethoxide, as in part (a), the reaction rate depends on both the concentrations of allyl halide and ethoxide ion. This dependency on two reactants is a hallmark of the \(\mathrm{S}_{\mathrm{N}}2\) mechanism. Such second-order kinetics suggest that both the nucleophile and the substrate come together in a single transition state, leading to the reaction occurring at an appreaciably fast rate.
Conversely, in more dilute solutions of the ethoxide, the reaction rate might only rely on the concentration of the allyl halide itself, potentially suggesting a shift towards \(\mathrm{S}_{\mathrm{N}}1\)-like behavior, where the rate is determined by the unimolecular formation of a carbocation. However, in the current exercise, conditions remain firmly in favor of \(\mathrm{S}_{\mathrm{N}}2\) reaction kinetics.
Concentrated Sodium Ethoxide
In the case of 1-chloro-2-pentene, its concentrated nature enables the ethoxide ion to effectively attack the allylic carbon position. The high concentration leads to more ethoxide ions in the solution, increasing the likelihood of collision with the substrate and facilitating the \(\mathrm{S}_{\mathrm{N}}2\) mechanism.
Therefore, the concentrated solution ensures that the ethoxide ion is sufficiently available to simultaneously interact with 1-chloro-2-pentene, increasing the reaction rate and effectively replacing the chlorine group with an ethoxy group to form the desired product.