Problem 81
Question
A radioactive isotope decays at such a rate that after 192 minutes only \(1 / 16\) of the origin amount remains. The half-life of the radioactive isotope is (a) \(12 \mathrm{~min}\) (b) \(24 \mathrm{~min}\) (c) \(32 \mathrm{~min}\) (d) \(48 \mathrm{~min}\)
Step-by-Step Solution
Verified Answer
The half-life of the radioactive isotope is 48 minutes.
1Step 1: Understanding the Problem
We are given that a radioactive isotope decays such that after 192 minutes, only \(\frac{1}{16}\) of the original amount remains. We need to find out the half-life of the isotope.
2Step 2: Expressing Remaining Amount Mathematically
We know that the remaining amount of a substance after time \(t\) is given by the function \( A(t) = A_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}}, \) where \( A_0 \) is the original amount and \( T_{1/2} \) is the half-life. In this problem, after 192 minutes, \( A(t) = \frac{A_0}{16} \).
3Step 3: Set up the Equation
We have \( \frac{A_0}{16} = A_0 \left( \frac{1}{2} \right)^{\frac{192}{T_{1/2}}} \). This reduces to the equation \( \left( \frac{1}{2} \right)^{\frac{192}{T_{1/2}}} = \frac{1}{16} \).
4Step 4: Simplify the Equation
The equation \( \frac{1}{16} \) can be rewritten as \( \left( \frac{1}{2} \right)^4 \). Therefore, equating the exponents gives us \( \frac{192}{T_{1/2}} = 4 \).
5Step 5: Solve for the Half-Life
Rearrange the equation to solve for \( T_{1/2} \): \( T_{1/2} = \frac{192}{4} \). Calculate this to find \( T_{1/2} = 48 \) minutes.
Key Concepts
Radioactive DecayExponential DecayRadioactive Isotopes
Radioactive Decay
Radioactive decay is a natural process in which an unstable atomic nucleus loses energy by emitting radiation in the form of particles or electromagnetic waves. This is a path to reach a more stable state.
In this decay process, the isotope transforms into a different element or a different isotope of the same element. Common types of decay include:
In this decay process, the isotope transforms into a different element or a different isotope of the same element. Common types of decay include:
- Alpha decay (emitting helium nuclei)
- Beta decay (emitting beta particles/electrons or positrons)
- Gamma decay (emitting electromagnetic rays)
Exponential Decay
Exponential decay describes a process where the quantity reduces at a rate proportional to its current value, resulting in a rapid decrease initially that slows over time. It's represented by the mathematical function:
\[ A(t) = A_0 imes e^{-kt} \]
where:
\[ A(t) = A_0 imes e^{-kt} \]
where:
- \( A(t) \) is the amount remaining at time \( t \).
- \( A_0 \) is the initial amount.
- \( k \) is the decay constant, a positive number.
Radioactive Isotopes
Radioactive isotopes, or radioisotopes, are variants of elements that have unstable nuclei and exhibit radioactive decay. These isotopes emit radiation as they transform into more stable isotopes.
The decay rate and the type of radiation emitted are characteristic of each radioisotope, making them useful in a variety of applications:
The decay rate and the type of radiation emitted are characteristic of each radioisotope, making them useful in a variety of applications:
- **Carbon-14** is widely used in radiocarbon dating to determine the age of archaeological artifacts.
- **Iodine-131** and **Technetium-99m** have significant uses in medical diagnostics and treatment.
- **Uranium-238** and **Plutonium-239** are critical in nuclear power generation and nuclear weaponry.
Other exercises in this chapter
Problem 79
The half-life period of radium is 1580 years. It remains \(1 / 16\) after how many years? (a) 1580 years (b) 3160 years (c) 4740 years (d) 6320 years
View solution Problem 80
The radioisotope, tritium \(\left({ }_{3}^{1} \mathrm{H}\right)\) has a half- life of \(12.3\) years. If the initial amount of tritium is \(32 \mathrm{mg}\), ho
View solution Problem 82
An artificial radioactive isotope has \(_{7} \mathrm{~N}^{14}\) after two successive \(\beta\) particle emissions. The number of neutrons in the parent nucleus
View solution Problem 83
A radioactive isotope has a half-life of 8 days. If today \(125 \mathrm{mg}\) is left over, what was its original weight 32 days earlier? (a) \(2 \mathrm{~g}\)
View solution