Problem 81
Question
A metal sign for a car dealership is a thin, uniform right triangle with base length \(b\) and height \(h\) . The sign has mass \(M\) . (a) What is the moment of inertia of the sign for rotation about the side of length \(h ?\) If \(M=5.40 \mathrm{kg}, b=1.60 \mathrm{m},\) and \(h=1.20 \mathrm{m},\) what is the kinetic energy of the sign when it is rotating about an axis along the \(1.20-\mathrm{m}\) side at 2.00 \(\mathrm{rev} / \mathrm{s} ?\)
Step-by-Step Solution
Verified Answer
The moment of inertia is 4.608 kg⋅m², and the kinetic energy is approximately 364.78 J.
1Step 1: Calculating the Moment of Inertia
The moment of inertia for a uniform right triangle rotating about one of its sides can be calculated using the formula for a right triangle, which is: \[ I = \frac{1}{3} M b^2 \] where \( M \) is the mass of the triangle, and \( b \) is the base of the triangle. Here, \( M = 5.40\, \text{kg} \) and \( b = 1.60\, \text{m} \). Substitute the given values: \[ I = \frac{1}{3} \times 5.40\, \text{kg} \times (1.60\, \text{m})^2 = \frac{1}{3} \times 5.40 \times 2.56 = 4.608\, \text{kg} \cdot \text{m}^2 \].
2Step 2: Convert Rotational Speed to Radians per Second
Since the rotational speed is given in revolutions per second, it can be converted to units of radians per second by using the conversion factor \(1\, \text{rev} = 2\pi\, \text{rad}\). So, if the rotational speed is \(2.00\, \text{rev/s}\), the corresponding rotational speed in radians per second is \[ \omega = 2.00 \times 2\pi = 4\pi \approx 12.57\, \text{rad/s} \].
3Step 3: Calculating the Kinetic Energy
The kinetic energy of a rotating object can be calculated using the formula: \[ KE = \frac{1}{2} I \omega^2 \] where \( I \) is the moment of inertia and \( \omega \) is the angular velocity. Substitute \( I = 4.608\, \text{kg}\cdot\text{m}^2 \) and \( \omega = 12.57\, \text{rad/s} \): \[ KE = \frac{1}{2} \times 4.608 \times (12.57)^2 \approx 364.78\, \text{J} \].
Key Concepts
Kinetic EnergyRight TriangleRotational Motion
Kinetic Energy
Kinetic energy represents the energy that an object possesses due to its motion. For rotational motion, the formula to calculate kinetic energy is slightly different from that of linear motion. In rotational systems, we use the formula: \[ KE = \frac{1}{2} I \omega^2 \]This equation depends on two main factors: the moment of inertia \( I \) and the angular velocity \( \omega \). The moment of inertia measures how the mass is distributed relative to the axis of rotation. The angular velocity is the rate at which the object spins, measured in radians per second.
- Moment of inertia is comparable to mass in linear motion and affects how easily an object can start or stop rotating. - Angular velocity indicates the speed of rotation.
In our exercise, we calculated a kinetic energy of approximately 364.78 Joules for a rotating right triangle sign, meaning it uses that amount of energy to maintain its rotational speed.
- Moment of inertia is comparable to mass in linear motion and affects how easily an object can start or stop rotating. - Angular velocity indicates the speed of rotation.
In our exercise, we calculated a kinetic energy of approximately 364.78 Joules for a rotating right triangle sign, meaning it uses that amount of energy to maintain its rotational speed.
Right Triangle
A right triangle is a specific type of triangle with one angle measuring exactly 90 degrees. This triangle has several unique properties that make it crucial in calculations related to geometry and physics. - The two sides forming the right angle are called the 'legs', and the side opposite the right angle is the 'hypotenuse'.
In our scenario, the metal sign is a right triangle with a base \( b \) and a height \( h \). For calculating the moment of inertia, only the base and the mass of the triangle are needed using the formula \[ I = \frac{1}{3} M b^2 \]This indicates that the sign rotates about one of its legs, treating the base as the axis. When considering rotational motion, the structure and proportions of a right triangle critically influence the computation of rotational attributes.
In our scenario, the metal sign is a right triangle with a base \( b \) and a height \( h \). For calculating the moment of inertia, only the base and the mass of the triangle are needed using the formula \[ I = \frac{1}{3} M b^2 \]This indicates that the sign rotates about one of its legs, treating the base as the axis. When considering rotational motion, the structure and proportions of a right triangle critically influence the computation of rotational attributes.
Rotational Motion
Rotational motion occurs when an object spins around an axis. It is a fundamental concept in physics involving parameters like moment of inertia, angular velocity, and angular acceleration.
The motion of a body rotating about an axis involves different calculations compared to objects moving linearly:- **Angular Velocity (\( \omega \))**: It measures how fast an object rotates or revolves relative to another point, expressed in radians per second.- **Moment of Inertia (\( I \))**: This gives an idea of how difficult it is to change the rotation of an object. It is dependent on the mass distribution of the object.
In our scenario, the right triangle is rotating about its side, and its angular velocity was given in revolutions per second. We converted this to radians per second using \( 1 \text{ rev} = 2\pi \text{ rad} \).The connection between these elements affects both the angular momentum and the kinetic energy of the rotating object. More mass farther from the center of rotation increases the moment of inertia, making the object harder to spin or stop.
The motion of a body rotating about an axis involves different calculations compared to objects moving linearly:- **Angular Velocity (\( \omega \))**: It measures how fast an object rotates or revolves relative to another point, expressed in radians per second.- **Moment of Inertia (\( I \))**: This gives an idea of how difficult it is to change the rotation of an object. It is dependent on the mass distribution of the object.
In our scenario, the right triangle is rotating about its side, and its angular velocity was given in revolutions per second. We converted this to radians per second using \( 1 \text{ rev} = 2\pi \text{ rad} \).The connection between these elements affects both the angular momentum and the kinetic energy of the rotating object. More mass farther from the center of rotation increases the moment of inertia, making the object harder to spin or stop.
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