Problem 80
Question
You buy a new car for \(\$ 24,000 .\) At the end of \(n\) years, the value of your car is given by the sequence $$a_{n}-24,000\left(\frac{3}{4}\right)^{n}, \quad n-1,2,3, \dots$$ Find \(a_{5}\) and write a sentence explaining what this value represents. Describe the \(n\) the term of the sequence in terms of the value of your car at the end of each year.
Step-by-Step Solution
Verified Answer
The value of the car at the end of the 5th year, represented by \(a_5\), is approximately \$5,062.50. This value represents how much the car has depreciated after five years of use. The nth term of the sequence represents the value of the car at the end of n years, assuming a yearly depreciation of 25%.
1Step 1: Identify the formula and the parameters
The depreciation of the car's value is modelled by the sequence \(a_n = 24,000 * (3/4)^n\), with n = 1, 2, 3, .... This formula is applied for each year that passes, starting from n=1 (the end of the first year).
2Step 2: Apply the formula for the 5th year
To find the value of the car at the end of the 5th year (\(a_5\)), substitute n with 5 in the formula: \(a_5 = 24,000 * (3/4)^5\). Calculating, we find that \(a_5 = 5,062.50\) dollars.
3Step 3: Interpret the obtained result
\(a_5 = 5,062.50\) dollars represents the value of the car at the end of the 5th year. This is showing how much the car has depreciated after five years.
4Step 4: Describe the nth term of the sequence in terms of the car value.
The nth term of the sequence, \(a_n = 24,000 * (3/4)^n\), represents the value of the car at the end of the nth year. With each year that passes, the value of your car depreciates by 25%, hence the factor of (\(3/4)^n\). The depreciation starts from the initial value of \$24,000 and gets compounded year by year.
Key Concepts
DepreciationNth TermSequence FormulaCar Value
Depreciation
Depreciation refers to the reduction in value of an asset over time. For cars, this is a common phenomenon due to wear and tear or advancements in technology. When we talk about car depreciation in a sequence, specifically, it shows how much the car’s value will decrease each year.
The given formula, \( a_n = 24,000 \times \left( \frac{3}{4} \right)^n \), reflects how the car’s worth changes yearly. The factor \( \frac{3}{4} \) indicates that the car retains 75% of its value each year and depreciates by 25%. This is a geometric progression since the car’s value decreases proportionally with each passing year.
The given formula, \( a_n = 24,000 \times \left( \frac{3}{4} \right)^n \), reflects how the car’s worth changes yearly. The factor \( \frac{3}{4} \) indicates that the car retains 75% of its value each year and depreciates by 25%. This is a geometric progression since the car’s value decreases proportionally with each passing year.
Nth Term
The nth term in a sequence formula gives you a specific value that corresponds to a certain position within the sequence. In this context, "n" represents the number of years. For a car value sequence, the nth term tells you the car's value at the end of "n" years.
You can determine any year's value using \( a_n = 24,000 \times \left( \frac{3}{4} \right)^n \). For example, \( a_5 \) means the car's value at the end of year five. Knowing the nth term helps you predict future values and understand how depreciation affects the car over time.
You can determine any year's value using \( a_n = 24,000 \times \left( \frac{3}{4} \right)^n \). For example, \( a_5 \) means the car's value at the end of year five. Knowing the nth term helps you predict future values and understand how depreciation affects the car over time.
Sequence Formula
A sequence formula provides a systematic method to calculate the terms of a sequence. Here, the formula \( a_n = 24,000 \times \left( \frac{3}{4} \right)^n \) is used to model how the car's value decreases each year.
- The initial term is \( 24,000 \), representing the purchase price of the car.
- The common ratio is \( \frac{3}{4} \), which reflects a 25% decrease annually.
- Using this formula helps determine the car's value after any number of years \( n \).
Car Value
Understanding car value in terms of depreciation helps you make informed decisions. Initially, the car is worth \( \$24,000 \). With each passing year, this value declines as described by the sequence formula.
For instance, after five years, the car is valued at \( 5,062.50 \) dollars, indicating significant depreciation. Recognizing the changing car value is helpful for:
For instance, after five years, the car is valued at \( 5,062.50 \) dollars, indicating significant depreciation. Recognizing the changing car value is helpful for:
- Resale and trade-in strategies.
- Setting budgets for maintenance and insurance based on the car’s worth.
- Forecasting long-term financial impact due to depreciation.
Other exercises in this chapter
Problem 79
Use the formula for the value of an annuity to solve,Round answers to the nearest dollar. At age \(25,\) to save for retirement, you decide to deposit \(\$ 50\)
View solution Problem 80
Make Sense? In Exercises \(78-81,\) determine whether each statement makes sense or does not make sense, and explain your reasoning. The sequence for the number
View solution Problem 80
Use the formula for the value of an annuity to solve,Round answers to the nearest dollar. At age \(25,\) to save for retirement, you decide to deposit \(\$ 75\)
View solution Problem 81
Make Sense? In Exercises \(78-81,\) determine whether each statement makes sense or does not make sense, and explain your reasoning. Beginning at 6: 45 A.M.., a
View solution