Problem 80
Question
Write an equation for each parabola with vertex at the origin. Through \((\sqrt{3}, 3) ;\) opening upward
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(y = x^2\).
1Step 1: Understand the Parabola Equation Structure
A parabola with its vertex at the origin and opening upward can be described by the equation \( y = ax^2 \). This form assumes the parabola is symmetric around the y-axis.
2Step 2: Substitute the Given Point into the Equation
Since the parabola passes through the point \((\sqrt{3}, 3) \), substitute \(\sqrt{3}\) for \(x\) and \(3\) for \(y\) in the equation \( y = ax^2 \) to find the value of \(a\). So, \( 3 = a (\sqrt{3})^2 \).
3Step 3: Simplify the Equation
Calculate \((\sqrt{3})^2 = 3\), so the equation becomes \(3 = a \cdot 3\).
4Step 4: Solve for \(a\)
Divide both sides of the equation \(3 = 3a \) by 3 to solve for \(a\). Thus, \( a = 1 \).
5Step 5: Write the Final Equation
Substitute \(a = 1\) back into the equation \(y = ax^2\), giving us the final equation \(y = x^2\).
Key Concepts
Vertex FormQuadratic FunctionSolving for ParametersOrigin in Parabolas
Vertex Form
In the study of parabolas, the vertex form of a quadratic equation is one of the most revealing and intuitive ways to represent a parabola. This form emphasizes the vertex of the parabola, which is either its highest or lowest point. In vertex form, a quadratic equation is expressed as \[ y = a(x-h)^2 + k \] where
- \( a \) represents the vertical stretch or compression of the parabola. If \( a \) is positive, the parabola opens upwards; if negative, it opens downwards.
- \( (h, k) \) is the vertex of the parabola. In scenarios where the vertex is at the origin, \( h = 0 \) and \( k = 0 \), simplifying the equation to \( y = ax^2 \).
Quadratic Function
Quadratic functions are fundamental in algebra and appear frequently in various applications. These functions are represented by polynomial equations of degree two. The most common form of a quadratic function is the standard form: \[ y = ax^2 + bx + c \] where
- \( a, b, \) and \( c \) are constants.
- The coefficient \( a \) determines the direction (upward or downward) and the width of the parabola.
- If \( a > 0 \), the parabola opens upwards. If \( a < 0 \), it opens downwards.
Solving for Parameters
Finding specific parameters in a quadratic equation is a common procedure when more information about the parabola is given, such as a point through which it passes. To solve for parameters like \( a \) in our situation where the vertex is at the origin:1. Start with the general formula: \( y = ax^2 \). This simplifies because the vertex is at (0, 0).2. Insert the known point on the parabola, say \((x, y)\).3. For example, using the point \((\sqrt{3}, 3)\), substitute into the equation: \( 3 = a(\sqrt{3})^2 \).4. Solve for \( a \) by simplifying and isolating it.A firm grasp of substituting points and manipulating equations is essential for accurately solving for these parameters, which ultimately define the specific shape and position of the parabola.
Origin in Parabolas
When the vertex of a parabola is at the origin, it simplifies the equation significantly. The vertex at the origin, (0, 0), means that both horizontal and vertical shifts (h and k in the vertex form) are zero.As a result, the equation of the parabola simplifies to \[ y = ax^2 \] This makes calculations and graphing more straightforward because:
- There's no need to adjust for shifts horizontally or vertically.
- The entire focus of the equation is on the coefficient \( a \), which dictates the openness and direction of the parabola.
Other exercises in this chapter
Problem 79
Write an equation for each parabola with vertex at the origin. Through \((2,-2 \sqrt{2}) ;\) opening to the right
View solution Problem 79
Use substitution to solve the nonlinear system of equations in three variables. Note that solutions are ordered triples. $$\begin{aligned} 2 x^{2}+y^{2}+3 z^{2}
View solution Problem 80
Use substitution to solve the nonlinear system of equations in three variables. Note that solutions are ordered triples. $$\begin{aligned} x^{2}+y^{2}+z^{2} &=4
View solution Problem 80
Write the equation in standard form for a hyperbola centered at ( \(h, k\) ). Identify the center and vertices. \(4 x^{2}+16 x-9 y^{2}+18 y=29\)
View solution