Problem 80
Question
This Lewis structure for \(\mathrm{SF}_{5}^{+}\) is drawn incorrectly. What error was made when determining the number of valence electrons?
Step-by-Step Solution
Verified Answer
The total valence electrons should be 40.
1Step 1: Determine the Elemental Valence Electrons
First, identify the number of valence electrons for each element in the species based on the periodic table. Sulfur typically has 6 valence electrons, and each fluorine atom has 7 valence electrons.
2Step 2: Sum the Valence Electrons
As \(\mathrm{SF}_5^{+}\) has one sulfur atom and five fluorine atoms, calculate their total valence electrons. Add sulfur's 6 electrons to fluorine's total, which is \5 \times 7 = 35\, resulting in \6 + 35 = 41\ valence electrons.
3Step 3: Account for the Positive Charge
For a positively charged ion (\(\mathrm{+1})\), subtract one electron from the sum calculated in Step 2. This gives \41 - 1 = 40\ valence electrons.
4Step 4: Identify the Error in the Lewis Structure
The mistake in drawing the Lewis structure was using an incorrect total of valence electrons. The correct number of electrons should be 40 after accounting for the positive charge, not 41 or any other number.
Key Concepts
Valence ElectronsMolecular IonsChemical BondingSulfur Fluoride Compounds
Valence Electrons
Valence electrons are the electrons in the outermost shell of an atom. These electrons are crucial because they determine how atoms interact, bond, and form molecules. For a Lewis structure, knowing the number of valence electrons is essential as it helps create an accurate depiction of the molecule’s electronic structure. Each element in the periodic table has a specific number of valence electrons. For example:
- Sulfur, found in group 16, typically has 6 valence electrons.
- Fluorine, found in group 17, usually has 7 valence electrons.
Molecular Ions
Molecular ions are molecules that have gained or lost electrons, resulting in an overall charge. In the case of \(\mathrm{SF}_{5}^{+}\), the molecule is a cation, meaning it has lost an electron and carries a positive charge. Calculating the correct number of valence electrons for a molecular ion involves:
- Adding electrons if the ion is negatively charged (anion).
- Subtracting electrons if the ion is positively charged (cation).
Chemical Bonding
Chemical bonding is the force that holds atoms together in a molecule. For \(\mathrm{SF}_{5}^{+}\), these bonds involve sharing valence electrons between sulfur and fluorine atoms, forming covalent bonds. In covalent bonding:
- Atoms share pairs of electrons to reach a stable electronic configuration.
- Sulfur, with its six valence electrons, needs two more to complete its octet, while each fluorine atom with seven valence electrons needs one more.
- When sulfur bonds with five fluorine atoms, the molecule must ensure all atoms achieve stable configurations, following the octet rule for fluorine and an expanded octet possibility for sulfur due to its ability to utilize d orbitals.
Sulfur Fluoride Compounds
Sulfur fluoride compounds are a class of chemicals that include various sulfur and fluorine bonded units. These compounds can exhibit different properties and structures depending on their electron count and the specific atoms involved. Some key points include:
- Sulfur can form multiple bonds with fluorine, creating compounds such as \(\mathrm{SF}_{2}\), \(\mathrm{SF}_{4}\), and \(\mathrm{SF}_{6}\), besides \(\mathrm{SF}_{5}^{+}\).
- In compounds like \(\mathrm{SF}_{5}^{+}\), sulfur uses its ability to expand its valence shell and form more than four bonds, accommodating five fluorines, which is unique compared to typical main-group elements.
- The chemical behavior of these compounds often involves interactions due to the highly electronegative fluorine atoms, affecting properties like reactivity and molecular geometry.
Other exercises in this chapter
Problem 77
Write a Lewis structure for each molecule. Which formulas represent alkanes? Which are probably aromatic? Which fall into neither category? (a) \(\mathrm{C}_{8}
View solution Problem 79
A student drew this incorrect Lewis structure for \(\mathrm{ClO}_{3}^{-}\). What errors were made when determining the number of valence electrons?
View solution Problem 81
Tribromide, \(\mathrm{Br}_{3}^{-},\) and triiodide \(, \mathrm{I}_{3}^{-},\) ions are often found in aqueous solutions, but trifluoride ion, \(\mathrm{F}_{3}^{-
View solution Problem 82
Explain why nonmetal atoms in Period 3 and beyond can accommodate greater than an octet of electrons and those in Period 2 cannot do so.
View solution