Problem 80
Question
Propanal and propanone, both have same molecular formula \(\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\right)\), what do you expect about their boiling points? (a) Both have same boiling point. (b) Boiling point of propanal is higher than the boiling point of propanone. (c) Boiling point of propanal is lower than the boiling point of propanone. (d) Nothing can be predicted.
Step-by-Step Solution
Verified Answer
(c) Boiling point of propanal is lower than the boiling point of propanone.
1Step 1: Understand the Structures
Propanal is an aldehyde with the structure CH₃CH₂CHO, while propanone (acetone) is a ketone with the structure CH₃COCH₃.
2Step 2: Consider Intermolecular Forces
Ketones like propanone have a carbonyl group (C=O) with a polar bond which can engage in dipole-dipole interactions. Aldehydes, although also polar, often have fewer of these interactions due to their structure.
3Step 3: Assess the Impact on Boiling Points
Dipole-dipole interactions in ketones are typically stronger than in aldehydes due to symmetrical placement around the central carbon, which can lead to slightly higher boiling points for ketones compared to similar aldehydes.
4Step 4: Conclusion
Propanone is thus expected to have a higher boiling point than propanal due to stronger intermolecular interactions.
Key Concepts
Intermolecular ForcesBoiling Point TrendsAldehydes and Ketones
Intermolecular Forces
Intermolecular forces are crucial when understanding the behavior and properties of molecules in chemistry. These forces are the interactions that occur between molecules as opposed to intramolecular forces, which occur within a molecule. The main types of intermolecular forces are:
- Van der Waals Forces: These are the weakest and occur between all molecules, especially non-polar ones. They arise from temporary shifts in electron density.
- Dipole-Dipole Interactions: These occur in polar molecules where permanent dipoles within molecules cause electrostatic attractions between the slightly positive end of one molecule and the slightly negative end of another.
- Hydrogen Bonding: A special type of dipole-dipole interaction that is stronger, occurring specifically between hydrogen and the electronegative atoms nitrogen, oxygen, or fluorine.
Boiling Point Trends
The boiling point of a substance is significantly influenced by the strength and nature of its intermolecular forces. Generally, stronger intermolecular forces lead to higher boiling points because greater energy is required to break these forces. For instance:
- Van der Waals Forces: Often result in low boiling points.
- Dipole-Dipole Interactions: Lead to moderate boiling points, higher than those seen with van der Waals forces.
- Hydrogen Bonding: Results in significantly higher boiling points.
Aldehydes and Ketones
Aldehydes and ketones are organic compounds characterized by the presence of the carbonyl group (4C=O5). This group is crucial in conferring distinct chemical and physical properties to these molecules. Despite having similar formulas, aldehydes and ketones differ primarily in the placement of the carbonyl group:
- Aldehydes: The carbonyl group is bonded to at least one hydrogen atom and is always terminally positioned, making molecules like propanal (4CH₃CH₂CHO5) slightly less capable of forming strong dipole-dipole interactions due to their asymmetrical structure.
- Ketones: The carbonyl group is bonded to two carbon atoms and is never at the end of a molecule. This leads to a more uniform distribution of the molecule's dipoles, as seen in propanone (4CH₃COCH₃5), making them more effective in dipole-dipole interactions compared to aldehydes.
Other exercises in this chapter
Problem 77
Which of the following has highest and lowest hydration equilibrium constant? \(\mathrm{HCHO}, \mathrm{CH}_{3} \mathrm{CHO}, \mathrm{CH}_{3} \mathrm{COCH}_{3}\)
View solution Problem 78
\(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{Cl} \stackrel{\mathrm{OH}^{-}, \mathrm{Cl}_{2}}{\longrightarrow}\) Product \(\mathrm{P}\) is (a) \(\mathrm{ClCH}_{2}
View solution Problem 82
In dilute aqueous solution, formaldehyde exists as (a) Formaldehyde (b) Paraldehyde (c) Trioxymethylene (d) Methyleneglycol
View solution Problem 83
The major driving force for the hydration of chloral is (a) less steric hinderance in the product (b) less force of repulsion in the product (c) hydrogen bondin
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