Problem 80
Question
Perform the indicated operations, and simplify. \(\left(c+\frac{1}{c}\right)^{2}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(c^2 + 2 + \frac{1}{c^2}\).
1Step 1: Expand the Square
We begin with the expression \( \left(c + \frac{1}{c}\right)^2 \). This can be expanded using the identity \((a+b)^2 = a^2 + 2ab + b^2\). Here, \(a = c\) and \(b = \frac{1}{c}\).
2Step 2: Apply the Formula
Using the formula from the previous step, we substitute \(a\) and \(b\) to get: \[a^2 + 2ab + b^2 = c^2 + 2 \cdot c \cdot \frac{1}{c} + \left(\frac{1}{c}\right)^2.\] This simplifies to: \[c^2 + 2 + \frac{1}{c^2}.\]
3Step 3: Simplify the Expression
Combine all the terms into a single expression to complete the simplification: \[c^2 + 2 + \frac{1}{c^2}.\] Here, we observed that the middle term 2 comes from the \(2 \times c \times \frac{1}{c}\) simplifying to 2.
Key Concepts
Expanding BinomialsSquaring a BinomialSimplifying ExpressionsAlgebraic Expressions
Expanding Binomials
The process of expanding binomials is crucial in algebra as it helps us express the square of a binomial expression as a trinomial. This typically involves using a well-known algebraic identity that relates to multiplying out the terms of a binomial raised to a power, usually 2. The key identity used is \((a + b)^2 = a^2 + 2ab + b^2\). This formula tells us exactly how to expand the binomial by squaring each term and then doubling the product of the two distinct terms
When we have an expression such as \((c + \frac{1}{c})^2\), we recognize that \(c\) and \(\frac{1}{c}\) play the roles of \(a\) and \(b\), respectively. By applying our identity, we can break down the binomial into three terms by:
When we have an expression such as \((c + \frac{1}{c})^2\), we recognize that \(c\) and \(\frac{1}{c}\) play the roles of \(a\) and \(b\), respectively. By applying our identity, we can break down the binomial into three terms by:
- Squaring the first term: \(c^2\)
- Multiplying the terms together and doubling it: \(2 \, (c \cdot \frac{1}{c}) = 2\)
- Squaring the second term: \((\frac{1}{c})^2 = \frac{1}{c^2}\)
Squaring a Binomial
Squaring a binomial is a specific operation where you raise an expression made up of two terms to the power of two. This operation is fundamental in algebra, allowing us to transform and manipulate polynomial expressions. When we square a binomial, we use the formula \((a+b)^2 = a^2 + 2ab + b^2\).
In our exercise, we square the whole binomial \(\left(c + \frac{1}{c}\right)^2\). This involves three main operations:
In our exercise, we square the whole binomial \(\left(c + \frac{1}{c}\right)^2\). This involves three main operations:
- Compute \(c^2\)
- Calculate the middle term \(2ab\), which simplifies to \(2\) because \(c \cdot \frac{1}{c} = 1\)
- Finish with \((\frac{1}{c})^2\), leading to \(\frac{1}{c^2}\)
Simplifying Expressions
Simplifying expressions involves combining and condensing terms to make the expression easier to understand or work with. The goal is to make expressions as simple as possible while keeping them equivalent to the original form. For algebraic expressions, this often means performing operations like addition, subtraction, multiplication, or division on coefficients or like terms.
In the context of the expanded binomial \(c^2 + 2 + \frac{1}{c^2}\), we simplify it down to its most compact form by ensuring all terms are gathered without any further reduction possible. Simplification reveals underlying patterns or values that might not be immediately visible in expanded form.
For our example:
In the context of the expanded binomial \(c^2 + 2 + \frac{1}{c^2}\), we simplify it down to its most compact form by ensuring all terms are gathered without any further reduction possible. Simplification reveals underlying patterns or values that might not be immediately visible in expanded form.
For our example:
- Combine constants or similar terms when applicable.
- Ensure fractions are properly managed to keep the expression neat.
- Always check results against the original expression to confirm equivalence.
Algebraic Expressions
Algebraic expressions are mathematical phrases involving numbers, variables, and operations. They serve as the foundation of algebra, representing a wide range of mathematical scenarios. Understanding how to manipulate these expressions is key to solving algebraic equations and problems.
An algebraic expression might be as simple as a single term, like \(x\), or more complex, involving several variables and operations as seen with \(c^2 + 2 + \frac{1}{c^2}\). These expressions are versatile, allowing for various manipulations:
An algebraic expression might be as simple as a single term, like \(x\), or more complex, involving several variables and operations as seen with \(c^2 + 2 + \frac{1}{c^2}\). These expressions are versatile, allowing for various manipulations:
- Adding or subtracting expressions
- Multiplying or dividing terms
- Factoring or expanding components
Other exercises in this chapter
Problem 80
Factor the expression completely. $$ n(x-y)+(n-1)(y-x) $$
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\(69-82\) . Simplify the expression and express the answer using rational exponents. Assume that all letters denote positive numbers. $$ \sqrt[3]{\frac{54 x^{2}
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Simplify the fractional expression. (Expressions like these arise in calculus.) $$ \sqrt{1+\left(\frac{x}{\sqrt{1-x^{2}}}\right)^{2}} $$
View solution Problem 81
\(81-88\) Write each number in decimal notation. $$ 3.19 \times 10^{5} $$
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