Problem 80
Question
In Exercises 59–94, solve each absolute value inequality. $$ 5|2 x+1|-3 \geq 9 $$
Step-by-Step Solution
Verified Answer
The solution set for the given absolute value inequality is \(-\frac{17}{10} \leq x \leq \frac{7}{10}\).
1Step 1: Isolate the Absolute Value Expression
The first step is to isolate the absolute value expression. We'll start with the original inequality \(5|2x+1|-3 \geq 9\) and isolate the absolute value by adding 3 to both sides, and then divide everything by 5. That gives us: \(|2x+1| \geq \frac{12}{5}\). Now we have the absolute value expression alone on one side.
2Step 2: Express the Inequality Without the Absolute Value
The fact that the absolute value of a number is greater than or equal to another number means that the number is either greater than or equal to the positive value of that number, or is less than or equal to the negative value of that number. Therefore, we can rewrite the inequality without the absolute value as a compound inequality: \(2x+1 \geq \frac{12}{5}\) or \(2x+1 \leq - \frac{12}{5}\).
3Step 3: Solve the Compound Inequality
In this step, we will solve both inequalities. To do this, we subtract 1 from both sides and then divide by 2 to solve for x. For the first inequality, \(\frac{2x+1-1}{2} \geq \frac{12}{5}-1\), we get \(x \geq \frac{7}{10}\). For the second inequality, \(\frac{2x+1-1}{2} \leq -\frac{12}{5}-1\), we get \(x \leq -\frac{17}{10}\). The solution set for this inequality is \(-\frac{17}{10} \leq x \leq \frac{7}{10}\).
Key Concepts
Solving InequalitiesCompound InequalityIsolate Absolute Value Expression
Solving Inequalities
Understanding how to solve inequalities is a fundamental skill in algebra. An inequality, unlike an equation, indicates that one side is not necessarily equal to the other, but rather greater than, less than, or possibly equal when we're dealing with non-strict inequalities. When we solve inequalities, it’s about finding all the possible values that make the inequality true.
General Steps for Solving Inequalities
- Identify the Inequality: Determine which type of inequality you are dealing with (greater than, less than, greater than or equal to, or less than or equal to).
- Perform Operations: Apply operations to both sides of the inequality to isolate the variable just like you would with an equation, being careful to reverse the inequality sign when multiplying or dividing by a negative number.
- Check the Solution: Unlike equations, where you'd plug the solution back in to check, with inequalities, it's often more practical to test a range of values around your solution to ensure the inequality holds true.
- Express the Solution: When the solution is a range of numbers, it's commonly expressed with inequality notation, a graph, or interval notation.
Compound Inequality
A compound inequality is an inequality that combines two distinct inequalities into one statement by using the word 'and' or 'or'. When the word 'and' is used, it means that the solution must satisfy both inequalities at once. On the other hand, 'or' implies that either of the inequalities can be true for the solution to hold.
In the context of absolute value inequalities, creating a compound inequality is often necessary. For an expression like \(|2x+1| \geq \frac{12}{5}\), the absolute value creates two scenarios: when \(2x+1\) is positive and when it's negative. Therefore, we split it into two different inequalities (\(2x+1 \geq \frac{12}{5}\) or \(2x+1 \leq -\frac{12}{5}\)) and treat them as a compound inequality.
In the context of absolute value inequalities, creating a compound inequality is often necessary. For an expression like \(|2x+1| \geq \frac{12}{5}\), the absolute value creates two scenarios: when \(2x+1\) is positive and when it's negative. Therefore, we split it into two different inequalities (\(2x+1 \geq \frac{12}{5}\) or \(2x+1 \leq -\frac{12}{5}\)) and treat them as a compound inequality.
Visualizing Compound Inequalities
If you graph the solutions of these inequalities on a number line, 'and' would be where the solution sets intersect, whereas 'or' would be the union of both solutions sets, depicting all the numbers that make either of the inequalities true.Isolate Absolute Value Expression
When solving absolute value inequalities, a critical step is to isolate the absolute value expression on one side of the inequality. This technique is important because it allows us to treat the absolute value expression as a 'single entity', which we can then analyze and split into its positive and negative components.
To isolate the absolute value, similar to isolating a variable, we perform inverse operations to 'undo' anything around the absolute value. This often involves adding or subtracting terms on both sides and dividing or multiplying to get the absolute value by itself, as is done in the textbook example with the expression \(5|2x+1|-3 \geq 9\).
Once we have the absolute value expression isolated, such as \(|2x+1| \geq \frac{12}{5}\), it becomes clear to define the two scenarios under which the inequality will hold true. Isolating the absolute value is a key step that sets up the equation for the creation of a compound inequality, leading us towards finding the full range of the solution.
To isolate the absolute value, similar to isolating a variable, we perform inverse operations to 'undo' anything around the absolute value. This often involves adding or subtracting terms on both sides and dividing or multiplying to get the absolute value by itself, as is done in the textbook example with the expression \(5|2x+1|-3 \geq 9\).
Once we have the absolute value expression isolated, such as \(|2x+1| \geq \frac{12}{5}\), it becomes clear to define the two scenarios under which the inequality will hold true. Isolating the absolute value is a key step that sets up the equation for the creation of a compound inequality, leading us towards finding the full range of the solution.
Other exercises in this chapter
Problem 79
Exercises \(78-80\) will help you prepare for the material covered in the next section. Factor: \(x^{2}-6 x+9\)
View solution Problem 79
Combine the types of equations we have discussed in this section. Solve equation. Then state whether the equation is an identity, a conditional equation, or an
View solution Problem 80
Compute the discriminant. Then determine the number and type of solutions for the given equation. $$ 3 x^{2}=2 x-1 $$
View solution Problem 80
Exercises \(78-80\) will help you prepare for the material covered in the next section. Evaluate \(\frac{-b-\sqrt{b^{2}-4 a c}}{2 a}\) for \(a=2, b=9,\) and \(c
View solution