Problem 80
Question
If you are given an equation of the form \(A x+B y=C\) explain how to find the \(x\)-intercept.
Step-by-Step Solution
Verified Answer
To find the x-intercept of the equation \(Ax + By = C\), set y to 0 and solve for x. The solution is \(x = C / A\), which is the x-coordinate of the x-intercept.
1Step 1: Identify the equation
You're given an equation of the form \(A x + B y = C\). This is a standard form for a linear equation.
2Step 2: Set y to zero
Since we want to find the x-intercept (the x value when the line crosses the x-axis), you have to set y=0 in the equation. So, the equation becomes \(A x + B * 0 = C\), which simplifies to \(A x = C\).
3Step 3: Solve for x
Next, solve for x by dividing both sides of the equation by A. So, the solution is \(x = C / A\). This is the x-coordinate of the x-intercept.
Key Concepts
Linear EquationsStandard Form of a Linear EquationSolving for X-InterceptAlgebraic Manipulation
Linear Equations
Linear equations are mathematical expressions that illustrate a straight-line relationship between two variables. In their simplest form, these equations can be written as \(y = mx + b\), where:
- \(y\) is the dependent variable.
- \(x\) is the independent variable.
- \(m\) represents the slope of the line.
- \(b\) is the y-intercept, where the line crosses the y-axis.
Standard Form of a Linear Equation
The standard form of a linear equation is expressed as \(Ax + By = C\). This form has certain characteristics that make it useful for solving different types of problems:
- \(A\), \(B\), and \(C\) are integers, and \(A\) should not be negative.
- It is straightforward to find both x- and y-intercepts from this form.
Solving for X-Intercept
Finding the x-intercept of an equation means determining the point where the line crosses the x-axis. At this point, the value of \(y\) is always zero. Let's follow the basic steps required to find the x-intercept for the standard form equation \(Ax + By = C\):
- Step 1: Replace \(y\) with zero in the equation, turning it into \(Ax + B(0) = C\).
- Step 2: Simplify the equation to \(Ax = C\).
- Step 3: Solve for \(x\) by dividing both sides by \(A\), resulting in \(x = \frac{C}{A}\).
Algebraic Manipulation
Algebraic manipulation involves applying various algebraic techniques to transform and solve equations. In the context of finding intercepts, one key technique is isolating the desired variable:
- Start by substituting known values, such as zero for \(y\) when finding the x-intercept.
- Simplify the equation by performing arithmetic operations like multiplication or division.
Other exercises in this chapter
Problem 79
graph each linear equation in two variables. Find at least five solutions in your table of values for each equation. $$y=4, \text { or } y=0 x+4$$
View solution Problem 79
\( \quad \frac{x}{2}+7=13-\frac{x}{4}\)
View solution Problem 80
write each sentence as a linear equation in two variables. Then graph the equation. $$y=3, \text { or } y=0 x+3$$
View solution Problem 80
$$\text { Simplify: } \quad 3\left(12 \div 2^{2}-3\right)^{2}$$.
View solution