Problem 80
Question
If \({ }^{n} C_{r}\) denotes the number of combination of \(n\) things taken \(\mathrm{r}\) at a time, then the expression \({ }^{n} C_{r+1}+{ }^{n} C_{r-1}^{\prime}+2 \times{ }^{n} C_{r}\) equals \(\quad[2003]\) (a) \({ }^{n+1} C_{r+1}\) (b) \({ }^{n+2} C_{r}\) (c) \({ }^{n+2} C_{r+1}\) (d) \({ }^{n+1} C_{r}\)
Step-by-Step Solution
Verified Answer
(c) \( { }^{n+2}C_{r+1} \).
1Step 1: Understanding Combinations
The notation \( ^{n}C_{r} \) represents the number of combinations of \( n \) items taken \( r \) at a time, calculated using the formula \( ^{n}C_{r} = \frac{n!}{r!(n-r)!}\). We need to work with combinations in this problem.
2Step 2: Identify the Problem Expression
The expression given is: \( { }^{n}C_{r+1} + { }^{n}C_{r-1} + 2 \times { }^{n}C_{r} \). We need to simplify this expression in terms of combinations.
3Step 3: Applying Combination Identities
Use the known identity for combinations: \( ^{n}C_{r} + ^{n}C_{r-1} = ^{n+1}C_{r}\). Apply this identity to each part of the expression:- Start with \( { }^{n}C_{r+1} + { }^{n}C_{r} \). By identity, this equals \( { }^{n+1}C_{r+1} \).- Similarly, \( { }^{n}C_{r} + { }^{n}C_{r-1} = { }^{n+1}C_{r} \).
4Step 4: Substituting into the Expression
Insert these simplified expressions into the original problem statement:- Start with \( { }^{n+1}C_{r+1} \) from the identity \( { }^{n}C_{r+1} + { }^{n}C_{r} \).- Add \( { }^{n+1}C_{r} \) for the combination \( { }^{n}C_{r} + { }^{n}C_{r-1} \).- The expression becomes \( { }^{n+1}C_{r+1} + { }^{n+1}C_{r} \).
5Step 5: Final Combination Identity
Using another identity \( { }^{n+1}C_{r+1} + { }^{n+1}C_{r} = { }^{n+2}C_{r+1} \) (since adding combinations shifts \( n \) upward), we simplify the expression to match one of the answer choices.
6Step 6: Select the Correct Answer
The simplified expression matches the identity \( { }^{n+2}C_{r+1} \). Therefore, the correct answer is (c) \( { }^{n+2}C_{r+1} \).
Key Concepts
Binomial CoefficientCombination IdentitiesCombinatorial Mathematics
Binomial Coefficient
The binomial coefficient is a fundamental concept in combinatorics. It represents the number of ways to select a certain number of items from a larger set, without regard to order. Typically denoted as \( { }^{n}C_{r} \) or sometimes \( \binom{n}{r} \), the binomial coefficient is calculated using the formula:
This formula allows us to calculate how many ways we can choose \( r \) objects from \( n \) objects. It's widely used in probability and statistics, and in combinatorial problems where the order of selection does not matter.
- \( { }^{n}C_{r} = \frac{n!}{r!(n-r)!} \)
This formula allows us to calculate how many ways we can choose \( r \) objects from \( n \) objects. It's widely used in probability and statistics, and in combinatorial problems where the order of selection does not matter.
Combination Identities
Combination identities are equations that relate different binomial coefficients in combinatorics. These identities help simplify complex expressions involving multiple combinations.
One of the basic identities is:
One of the basic identities is:
- \( { }^{n}C_{r} + { }^{n}C_{r-1} = { }^{n+1}C_{r} \)
- \( { }^{n+1}C_{r+1} + { }^{n+1}C_{r} = { }^{n+2}C_{r+1} \)
Combinatorial Mathematics
Combinatorial mathematics is an area of mathematics focused on counting, arrangement, and combination of elements within a set according to specified rules. It has diverse applications in fields such as computer science, statistical physics, and network theory, to name just a few.
At its core, combinatorics uses principles like:
At its core, combinatorics uses principles like:
- Counting Principle: Techniques for counting the number of ways to perform a task.
- Pigeonhole Principle: A simple yet powerful concept for proving that something exists based on counting.
- Inclusion-Exclusion Principle: This helps find the number of elements in the union of sets by subtracting overcounts from sum of individual counts.
Other exercises in this chapter
Problem 78
The number of ways of distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is (a) \({ }^{8} C_{3}\) (b) 21 (c) \(3^{8}\) (d) 5
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A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices availab
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Five digit number divisible by 3 is formed using \(0,1,2,3,4\), 6 and 7 without repetition. Total number of such numbers are [2002] (a) 312 (b) 3125 (c) 120 (d)
View solution Problem 77
The value of \({ }^{50} C_{4}+\sum_{r=1}^{6}{\underline{\phantom{xx}}}^{56-r} C_{3}\) is (a) \({ }^{55} \mathrm{C}_{4}\) (b) \({ }^{55} C_{3}\) (c) \({ }^{56} \mathrm{C}_{3}\) (d) \({
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