Problem 80
Question
Find the solution of the equation rounded to two decimals. \(2.14(x-4.06)=2.27-0.11 x\)
Step-by-Step Solution
Verified Answer
The solution to the equation is approximately 4.86.
1Step 1: Expand the Equation
First, expand the left side of the equation using the distributive property. Multiply 2.14 by both terms inside the parentheses: \[ 2.14(x - 4.06) = 2.14x - 8.6684 \] Now the equation becomes: \[ 2.14x - 8.6684 = 2.27 - 0.11x \]
2Step 2: Combine Like Terms
Next, move the term with \(x\) on the right side of the equation to the left side by adding \(0.11x\) to both sides. This results in: \[ 2.14x + 0.11x - 8.6684 = 2.27 \] Combine the \(x\) terms: \[ 2.25x - 8.6684 = 2.27 \]
3Step 3: Isolate the x Term
To isolate the term with \(x\), add 8.6684 to both sides of the equation: \[ 2.25x = 2.27 + 8.6684 \] Calculate the right side: \[ 2.25x = 10.9384 \]
4Step 4: Solve for x
Finally, divide both sides of the equation by 2.25 to solve for \(x\): \[ x = \frac{10.9384}{2.25} \] Calculate the result and round it to two decimal places: \[ x \approx 4.86 \]
Key Concepts
Distributive PropertyCombining Like TermsIsolating VariablesRounding Numbers
Distributive Property
The distributive property is a fundamental algebraic concept that allows us to multiply a single term across terms inside a bracket. By applying this property, expressions can be simplified, making complex equations easier to work with. In the context of the equation \(2.14(x-4.06) = 2.27 - 0.11x\), we used the distributive property to expand \(2.14(x-4.06)\). Here’s how it works:
- Multiply 2.14 by \(x\).
- Multiply 2.14 by -4.06.
Combining Like Terms
After using the distributive property, the next step is to combine like terms. This means simplifying the equation further by adding or subtracting terms that are similar.
In our equation, after expanding, we have \(2.14x - 8.6684 = 2.27 - 0.11x\). To simplify, we move terms containing \(x\) to one side. We do this by adding \(0.11x\) to both sides:
In our equation, after expanding, we have \(2.14x - 8.6684 = 2.27 - 0.11x\). To simplify, we move terms containing \(x\) to one side. We do this by adding \(0.11x\) to both sides:
- Adding \(0.11x\) to \(2.14x\) results in \(2.25x\).
- The constant term \(-8.6684\) stays with \(x\) terms.
Isolating Variables
Isolating the variable is a key step in solving equations. It involves manipulating the equation to get the variable alone on one side. This step allows us to determine its value. Once like terms are combined and our equation is \(2.25x - 8.6684 = 2.27\), we need to isolate \(x\).
To do that, simply add 8.6684 to both sides of the equation:
To do that, simply add 8.6684 to both sides of the equation:
- This moves all constants to the right side.
- We're left with \(2.25x = 10.9384\).
Rounding Numbers
Rounding numbers is often employed to communicate solutions with precision and clarity. In real-world applications, answers are frequently rounded to a set number of decimal places for consistency.
Once you’ve isolated the variable and performed final computations, as in \(x = \frac{10.9384}{2.25}\), the last step is to round \(x\) to two decimal places:
Once you’ve isolated the variable and performed final computations, as in \(x = \frac{10.9384}{2.25}\), the last step is to round \(x\) to two decimal places:
- First, compute \(x\) which is approximately 4.86026667.
- Look at the third decimal place to decide rounding.
- Since it's below 5, \(x\) rounds to 4.86.
Other exercises in this chapter
Problem 80
Number Problem The sum of the squares of two consecutive even integers is \(1252 .\) Find the integers.
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Radius of a Tank A spherical tank has a capacity of 750 gallons. Using the fact that 1 gallon is about 0.1337 \(\mathrm{ft}^{3}\) , find the radius of the tank
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Complex Conjugate Roots Suppose that the equation \(a x^{2}+b x+c=0\) has real coefficients and complex roots. Why must the roots be complex conjugates of each
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Dimensions of a Garden A rectangular garden is 10 \(\mathrm{ft}\) longer than it is wide. Its area is \(875 \mathrm{ft}^{2} .\) What are its dimensions?
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