Problem 80
Question
A function \(f\) and a point \(c\) are given. Graph the function $$ \phi(x)=\frac{f(x)-f(c)}{x-c} $$ in an appropriate viewing window centered about the line \(x=c .\) Use the graph of \(\phi\) to decide whether or not \(f^{\prime}(c)\) exists. Explain the reason for your answer, and, if your answer is that \(f^{\prime}(c)\) exists, use the graph of \(\phi\) to approximate the value of \(f^{\prime}(c)\). $$ f(x)=\sqrt{x^{4}-2 x^{3}+2 x-1}, c=1 $$
Step-by-Step Solution
Verified Answer
The graph of \(\phi(x)\) does not exhibit a finite limit as \(x\) approaches 1, so \(f'(1)\) does not exist.
1Step 1: Substitute the Function and Point
Firstly, substitute the given function \(f(x) = \sqrt{x^4 - 2x^3 + 2x - 1}\) and point \(c = 1\) into the expression for \(\phi(x)\). This yields the function \(\phi(x) = \frac{\sqrt{x^4 - 2x^3 + 2x - 1} - \sqrt{0}}{x - 1}\), simplifying to \(\phi(x) = \frac{\sqrt{x^4 - 2x^3 + 2x - 1}}{x - 1}\).
2Step 2: Determine the Appropriate Viewing Window
To analyze the behavior of \(\phi(x)\) as \(x\) approaches 1, choose a viewing window centered around \(x = 1\) such as \(x \in [0.8, 1.2]\) and \(y \) range based on trial, for example, \(y \in [-5, 5]\).
3Step 3: Graph the Function \(\phi(x)\)
Use graphing software or a graphing calculator to plot \(\phi(x)\) over the chosen viewing window. Examine the graph around \(x = 1\) to observe the behavior of \(\phi(x)\).
4Step 4: Analyze the Graph to Determine Existence of \(f'(c)\)
Look at the graph of \(\phi(x)\) near \(x = 1\). If the graph approaches a finite limit as \(x\) approaches 1, then \(f'(1)\) exists. If the graph does not approach a finite limit, then \(f'(1)\) does not exist.
5Step 5: Approximate \(f'(c)\) if It Exists
If the graph indicates that \(f'(1)\) exists, estimate the value of \(f'(1)\) by observing the value that \(\phi(x)\) approaches as \(x\) approaches 1 on the graph.
Key Concepts
LimitsContinuityDifferentiabilityGraphing Functions
Limits
Understanding limits is essential to exploring the behavior of functions as we approach a certain point, such as the point where a derivative is calculated. In the given exercise, analyzing the limit of the function \( \phi(x) = \frac{\sqrt{x^4 - 2x^3 + 2x - 1}}{x - 1} \) as \( x \) approaches 1 is crucial.
Limits help us comprehend what value a function approaches, even if it doesn't actually reach that value. This is particularly useful in calculus, where we often need to know the behavior of a function as it gets close to a specific point.
In simpler terms:
Limits help us comprehend what value a function approaches, even if it doesn't actually reach that value. This is particularly useful in calculus, where we often need to know the behavior of a function as it gets close to a specific point.
In simpler terms:
- Limits allow for understanding near-behavior without direct substitution.
- They're foundational for calculus concepts like derivatives and integrals.
Continuity
Continuity is the property of a function to be unbroken or uninterrupted; in other words, no gaps or holes in the graph. A function is continuous at a point \( c \) if the following three conditions are met:
If any of the above conditions are not met, the function is not continuous at that point. Continuity plays an important role because, for a function to have a derivative at a point, it must be continuous there. If \( \phi(x) \) has no abrupt changes or breaks at \( x = 1 \), it suggests continuity.
- The function \( f(x) \) is defined at \( x = c \).
- The limit of \( f(x) \) as \( x \) approaches \( c \) exists.
- The limit of \( f(x) \) as \( x \) approaches \( c \) is equal to \( f(c) \).
If any of the above conditions are not met, the function is not continuous at that point. Continuity plays an important role because, for a function to have a derivative at a point, it must be continuous there. If \( \phi(x) \) has no abrupt changes or breaks at \( x = 1 \), it suggests continuity.
Differentiability
Differentiability is the ability of a function to have a derivative at a particular point. If a function is differentiable at a point, it means the slope of the tangent line to the function at that point can be determined. For a function to be differentiable at a point \( c \), it must be continuous there. However, a function can be continuous but not differentiable at some points (e.g., corners or cusps).
Differentiability in this exercise refers to determining if \( f'(1) \) exists. This involves:
Differentiability in this exercise refers to determining if \( f'(1) \) exists. This involves:
- Checking if \( \phi(x) \) settles into a specific path approaching a finite number as \( x \to 1 \).
- Ensuring the absence of jumps, infinite slopes, or vertical tangents in the plotted graph of \( \phi(x) \).
Graphing Functions
Graphing functions is a powerful tool for visualizing and understanding the mathematical behavior of expressions. In our exercise, graphing \( \phi(x) \) helps in observing how the function behaves near \( x = 1 \). A clear graph enables us to see if \( \phi(x) \) approaches a finite value, implying the existence of the derivative at that point.
Key elements of graphing:
Key elements of graphing:
- Choose an appropriate window that captures behavior around points of interest.
- Look for trends that indicate limits and ensure no abrupt irregularities are present.
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