Problem 80
Question
a. Find the center of mass of a thin plate of constant density covering the region between the curve \(y=1 / \sqrt{x}\) and the \(x-\) axis from \(x=1\) to \(x=16\) . b. Find the center of mass if, instead of being constant, the density function is \(\delta(x)=4 / \sqrt{x}\) .
Step-by-Step Solution
Verified Answer
a. (7, 0), b. \( \left( \frac{15}{\ln 16}, 0 \right) \).
1Step 1: Understand the Problem Requirements
We are asked to find the center of mass for a thin plate covering a region between a curve and the x-axis. This involves integrating over the region to find both mass and moments.
2Step 2: Set Up the Integral for Total Mass with Constant Density
For part (a) where density is constant, assume density \( \rho \) = 1 for simplicity. The mass \( M \) is the integral of the density over the area. Thus, \( M = \int_{1}^{16} (1/\sqrt{x}) dx \).
3Step 3: Calculate Total Mass for Constant Density
Evaluate the integral \( M = \int_{1}^{16} \frac{1}{\sqrt{x}} \, dx \). By substitution, \( \int \frac{1}{\sqrt{x}} \, dx = 2\sqrt{x} \), so \( M = [2\sqrt{x}]_{1}^{16} = 8 - 2 = 6 \).
4Step 4: Set Up Integrals for Moments with Constant Density
For the x-coordinate of the center of mass, calculate the moment about the y-axis: \( M_{x} = \int_{1}^{16} x \cdot \frac{1}{\sqrt{x}} \, dx \).
5Step 5: Calculate x-Moment for Constant Density
Evaluate \( M_{x} = \int_{1}^{16} x \cdot \frac{1}{\sqrt{x}} \, dx = \int_{1}^{16} \sqrt{x} \, dx = \frac{2}{3}x^{3/2} \) to get \( M_{x} = \left[\frac{2}{3}x^{3/2}\right]_{1}^{16} = \frac{2}{3}[64 - 1] = \frac{126}{3} = 42 \).
6Step 6: Calculate Center of Mass for Constant Density
The x-coordinate of the center of mass is \( \bar{x} = \frac{M_{x}}{M} = \frac{42}{6} = 7 \). For constant density, the y-coordinate doesn’t affect the integration here. The center of mass is (7, 0).
7Step 7: Modify Density Function and Set Up New Mass Integral
For part (b), change the density to \( \delta(x) = \frac{4}{\sqrt{x}} \). Find the new mass \( M = \int_{1}^{16} \frac{4}{\sqrt{x}} \frac{1}{\sqrt{x}} \, dx = \int_{1}^{16} \frac{4}{x} \, dx \).
8Step 8: Calculate Total Mass for Variable Density
Evaluate \( M = 4 \int_{1}^{16} \frac{1}{x} \, dx = 4[\ln x]_{1}^{16} = 4(\ln 16 - \ln 1) = 4 \ln 16 \).
9Step 9: Set Up Integrals for Moments with Variable Density
Find the x-moment \( M_{x} = \int_{1}^{16} x \cdot \frac{4}{\sqrt{x}} \frac{1}{\sqrt{x}} \, dx = \int_{1}^{16} 4 \, dx = 4[x]_{1}^{16} \).
10Step 10: Calculate x-Moment for Variable Density
Evaluate \( M_{x} = 4[16 - 1] = 4 \times 15 = 60 \).
11Step 11: Calculate Center of Mass for Variable Density
The x-coordinate of the center of mass is \( \bar{x} = \frac{M_{x}}{M} = \frac{60}{4 \ln 16} = \frac{15}{\ln 16} \). For the y-coordinate, it again does not affect the integration. The center of mass is \( \left( \frac{15}{\ln 16}, 0 \right) \).
Key Concepts
Calculus IntegrationVariable DensityMoments of Mass
Calculus Integration
In calculus, integration is a fundamental concept often used to find areas under curves or to calculate total values such as mass or moments of mass in physical systems. Specifically, an integral sums up infinitesimally small quantities over a given range to produce a cumulative outcome. Integration involves the calculation of definite integrals over specific intervals. In the context of the center of mass, it's used to aggregate the effects of density and shape across a region. For example, in the given exercise, we utilized the integral to determine the mass of a solid by integrating the density across the defined area of the plate. With integration,
- We established the total mass by integrating the density function.
- We computed moments by integrating weighted positions, which contribute to the understanding of the overall balance of the shape.
Variable Density
When dealing with physics problems involving objects like plates, density is not always constant. It may vary with position, which is what we refer to as variable density. This characteristic means that some parts of the object could be denser than others, affecting calculations of mass and other properties. In the given problem, the density function is altered from constant to a function \( \delta(x) = \frac{4}{\sqrt{x}} \) for part (b). This variable density means:
- The density increases or decreases along the region's span.
- The calculation of mass is not straightforward like in the constant density case and requires careful integration handling.
Moments of Mass
In the context of finding a center of mass, moments of mass are essential concepts. They represent the rotational analogs of mass that account for the distribution of mass at various points relative to a chosen axis. There are several key points to remember:
- The moment about an axis provides insight into the balance or rotational behavior of an object.
- In this exercise, the moment about the y-axis \( M_x \) was calculated to find the x-coordinate of the center of mass.
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