Problem 80
Question
A cellphone company offers the following plans. Also given are the piecewise functions that model these plans. Use this information to solve. Plan \(A\) \(\cdot$$\$ 30\) per month buys 120 minutes. \(\cdot\) Additional time costs \(\$ 0.30\) per minute. $$C(t)=\left\\{\begin{array}{ll}30 & \text { if } 0 \leq t \leq 120 \\\30+0.30(t-120) & \text { if } t>120\end{array}\right.$$ Plan \(B\) \(\cdot \$ 40\) per month buys 200 minutes. \(\cdot\) Additional time costs \(\$ 0.30\) per minute. $$C(t)=\left\\{\begin{array}{ll}40 & \text { if } 0 \leq t \leq 200 \\\40+0.30(t-200) & \text { if } t>200\end{array}\right.$$ Simplify the algebraic expression in the second line of the piecewise function for plan \(\mathrm{B}\). Then use point-plotting to graph the function.
Step-by-Step Solution
VerifiedKey Concepts
Simplify Algebraic Expressions
Starting with the unsimplified expression, \( 40 + 0.30 \times (t-200) \), our first step is to distribute the \( 0.30 \) across the terms within the parentheses. This gives us two separate terms: \( 0.30 \times t \) and \( 0.30 \times -200 \). Multiplying these out, we get \( 0.30t \) and \( -60 \), respectively. Combining these with the constant \( 40 \), we end up with \( 40 + 0.30t - 60 \), which then simplifies to \( -20 + 0.30t \).
When simplifying, remember to:
- Apply the distributive property correctly.
- Combine like terms, both constants, and those with the same variable,
- Check your work for any possible additional simplifications.
Graphing Functions
The constant piece \( C(t) = 40 \) for \( 0 \leq t \leq 200 \) is straightforward because it represents a flat line where the cost remains the same, irrespective of the minutes used, up to 200 minutes. Plotting this on a graph, we get a horizontal line from (0, 40) to (200, 40).
For the second piece where \( t > 200 \), the function is \( C(t) = -20 + 0.30t \), representing a linear equation that starts at 200 minutes and increases at the rate of \$0.30 for every additional minute. Since \( C(200) = 40 \), the graph continues from the point (200, 40) upwards and rightwards, matching the slope of 0.30.
To render this graph accurately, start by plotting the y-intercept and other strategic points, then draw a line connecting these points. Always ensure any transitions between slices of the piecewise function are clear on the graph.
Linear Equations
For Plan B's second part, where \( t > 200 \), we have the linear equation \( -20 + 0.30t \). Here, 0.30 is the slope (\( m \)), showing the rate of change—how much the cost increases per additional minute. The constant term, -20, results from shifting the y-axis to match the context of the piecewise function.
Remember, in the context of linear equations:
- The slope (\( m \)) indicates the steepness and direction of a line.
- The y-intercept (\( b \)) provides the starting value on the vertical axis at \( t = 0 \).
- Since piecewise functions can change formulas at certain points, the concept of a 'piecewise' y-intercept might be applied, as is the case with the shift at \( t = 200 \) minutes.