Problem 8
Question
Write the first five terms of each geometric sequence. $$a_{n}=-6 a_{n-1}, \quad a_{1}=-2$$
Step-by-Step Solution
Verified Answer
The first five terms of the geometric sequence are -2, 12, -72, 432, -2592.
1Step 1: Identify the Initial Value and Ratio
First, let's note the key components of the formula given. The sequence starts with \(a_{1}=-2\), this is the first term. It also includes a common ratio indicated by the formula \(a_{n}=-6 a_{n-1}\), which implies each term is -6 times the term before it.
2Step 2: Calculate the Second Term
Using the formula, the second term of the sequence can be calculated as \(a_{2}= -6 a_{1} = -6 (-2) = 12\). Thus, our sequence now is -2, 12.
3Step 3: Calculate the Third Term
Continuing onto the next term, according to our formula this would be \(a_{3}= -6 a_{2}= -6 (12) = -72\). Thus, our sequence is -2, 12, -72.
4Step 4: Calculate the Fourth Term
Using the same formula, calculate the fourth term: \(a_{4}= -6 a_{3}= -6 (-72) = 432\). The sequence is now -2, 12, -72, 432.
5Step 5: Calculate the Fifth Term
Calculate the fifth term in the same way: \(a_{5}= -6 a_{4}= -6(432) = -2592\). Now, the five term sequence is -2, 12, -72, 432, -2592.
Key Concepts
Common RatioSequence TermsRecursive Formula
Common Ratio
The common ratio is a key component of any geometric sequence. It defines the factor by which we multiply a term to get the subsequent term. In the above exercise, the **common ratio** is expressed in the recursive formula as \( a_{n} = -6a_{n-1} \). This tells us that each term in the sequence is -6 times the previous term.
- If the common ratio is positive, the sequence's terms all maintain the same sign over consecutive terms.
- If it’s negative, as in our exercise, each term alternates in sign compared to its predecessor.
Sequence Terms
Sequence terms are the individual numbers that make up a sequence. In a geometric sequence, we start with an initial term, usually denoted as \( a_1 \), and generate subsequent terms through the multiplication of the common ratio. For the given problem, the initial term \( a_1 \) is -2. We then compute the following terms using the formula, repeatedly applying the common ratio:
- The second term: \( a_2 = -6 \, \times \,-2 = 12 \)
- The third term: \( a_3 = -6 \, \times \, 12 = -72 \)
- The fourth term: \( a_4 = -6 \, \times \, -72 = 432 \)
- The fifth term: \( a_5 = -6 \, \times \, 432 = -2592 \)
Recursive Formula
A recursive formula defines each term of a sequence using the preceding term(s). In geometric sequences, this often involves multiplying the previous term by the common ratio. In our exercise, the recursive formula given is \( a_{n} = -6 a_{n-1} \):
- \( a_{n} \) refers to the current term we are interested in.
- \( a_{n-1} \) is the term directly preceding it.
Other exercises in this chapter
Problem 8
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Write the first four terms of each sequence whose general term is given. $$a_{n}=(-1)^{n+1}(n+4)$$
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Write the first six terms of each arithmetic sequence. $$a_{n}=a_{n-1}+6, a_{1}=-9$$
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