Problem 8
Question
Which one of the following forms, with an excess of \(\mathrm{CN}^{-}\), a complex having coordination number two? (a) \(\mathrm{Ni}^{2+}\) (b) \(\mathrm{Cu}^{+}\) (c) \(\mathrm{Ag}^{+}\) (d) \(\mathrm{Fe}^{2+}\)
Step-by-Step Solution
Verified Answer
The complex having coordination number two is formed by c '\mathrm{Ag}^{+}\', which forms c '\mathrm{[Ag(CN)_2]^{-}\'.
1Step 1: Understand coordination number
The coordination number refers to the number of ligand donor atoms to which the central atom is directly bonded. In this question, we seek a complex with coordination number two.
2Step 2: Ligand characteristics
The ligand \(\mathrm{CN}^{-}\) is a strong field ligand, which tends to form complexes with transition metal ions. We need to identify which metal ion, when combined with \(\mathrm{CN}^{-}\), can result in coordination number two.
3Step 3: Analyze metal ions
Each metal ion option provided can form complexes with cyanide ions, because \(\mathrm{CN}^{-}\) is a strong and small ligand able to cause certain metals to exhibit lower coordination numbers.
4Step 4: Specific analysis of Ag^{+}
The silver ion \(\mathrm{Ag}^{+}\) is known to readily form a linear complex with \(\mathrm{CN}^{-}\) due to its preference for a two-coordinated structure, forming \(\mathrm{[Ag(CN)_2]^{-}\) with coordination number two.
5Step 5: Conclusion
From the analysis, \(\mathrm{Ag}^{+}\) forms a complex \(\mathrm{[Ag(CN)_2]^{-}\) which has a coordination number of two, confirming it as the correct answer.
Key Concepts
Coordination NumberStrong Field LigandTransition Metal ComplexesCyanide Ion Ligand
Coordination Number
In coordination chemistry, the coordination number of a complex refers to the number of ligand donor atoms bonded directly to the central metal atom or ion. Understanding this concept is crucial when studying complexes, as it influences the geometry and stability of the formed complex.
- A coordination number of two often results in a linear geometry.
- Common coordination numbers range from two to twelve, with most compounds having a coordination number between four and six.
Strong Field Ligand
A strong field ligand greatly affects the properties and behavior of transition metal complexes. By causing significant splitting of the d-orbitals in the metal center, these ligands play a crucial role in the determination of the coordination number and magnetic properties.
- Strong field ligands can cause low-spin complexes by pairing electrons in lower energy orbitals.
- They can alter the oxidation state and electronic configuration of a metal, influencing the coordination number and geometry.
Transition Metal Complexes
Transition metal complexes are fascinating because they display a wide range of colors, magnetic properties, and reactivities. These complexes are formed by the combination of transition metals with ligands, where the metal is typically located in the center.
- The variety of possible ligands allows for diverse coordination environments.
- The properties of these complexes are largely dictated by the nature of the metal and the ligands.
Cyanide Ion Ligand
The cyanide ion (\( ext{CN}^{-} \) ) is a highly significant ligand in coordination chemistry. Due to its ability to act as a strong field ligand, it dramatically influences the bonding and properties of the resulting complexes.
- It often forms stable, linear complexes with coordination number two.
- CYanide behaves as a monodentate ligand, meaning it bonds through a single donor atom.
Other exercises in this chapter
Problem 6
In which of the following metal complex, does the central metal atom have zero Oxidation state? (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \
View solution Problem 7
Misch metal is (a) an alloy of copper (b) an alloy of lanthanoid metal (c) an alloy of aluminium (d) a mixture of chromium and lead chromate
View solution Problem 9
Which of the following order is correct for the size of \(\mathrm{Fe}^{3+}, \mathrm{Fe}\) and \(\mathrm{Fe}^{2+} ?\) (a) \(\mathrm{Fe}^{3+}
View solution Problem 10
Which of the following pairs of ions is colourless? (a) \(\mathrm{Ti}^{-3+}, \mathrm{Cu}^{2+}\) (b) \(\mathrm{Sc}^{3+}, \mathrm{Zn}^{2+}\) (c) \(\mathrm{Co}^{2+
View solution