Problem 8
Question
Verify that each of the following is an identity. $$ \cot x=\frac{\sin 2 x}{1-\cos 2 x} $$
Step-by-Step Solution
Verified Answer
The identity \( \cot x = \frac{\sin 2x}{1 - \cos 2x} \) is verified.
1Step 1: Understand the Identity Form
We are given the identity \( \cot x = \frac{\sin 2x}{1 - \cos 2x} \). The goal is to verify that this expression is valid by showing that both sides of the equation are equal for all \(x\) where both sides are defined.
2Step 2: Express \( \cot x \) Using Trig Functions
Recall that \( \cot x = \frac{\cos x}{\sin x} \), which is the expression we will use for the left side of the identity.
3Step 3: Simplify \( \frac{\sin 2x}{1 - \cos 2x} \)
For the right side, start by expressing \( \sin 2x \) and \( \cos 2x \) using their double-angle formulas. We have \( \sin 2x = 2 \sin x \cos x \) and \( \cos 2x = \cos^2 x - \sin^2 x \).
4Step 4: Substitute Double Angle Formulas
Substitute \( \sin 2x = 2 \sin x \cos x \) into \( \frac{\sin 2x}{1 - \cos 2x} \): \[ \frac{2 \sin x \cos x}{1 - (\cos^2 x - \sin^2 x)} \] \[ = \frac{2 \sin x \cos x}{1 - \cos^2 x + \sin^2 x} \].
5Step 5: Simplify the Denominator
Since \( 1 - \cos^2 x = \sin^2 x \), substitute this in: \[ \frac{2 \sin x \cos x}{\sin^2 x + \sin^2 x} = \frac{2 \sin x \cos x}{2 \sin^2 x} \].
6Step 6: Divide Each Term
Simplify by dividing both the numerator and the denominator by 2 \(\sin x\):\[ \frac{\sin x \cos x}{\sin^2 x} = \frac{\cos x}{\sin x} \].
7Step 7: Conclude the Identity Verification
The right side \( \frac{\cos x}{\sin x} \) simplifies to \( \cot x \), which is the left side of the identity. Therefore, the initial equation is verified as an identity.
Key Concepts
CotangentDouble Angle FormulasTrigonometric Functions
Cotangent
The cotangent function, often denoted as \( \cot x \), is one of the primary trigonometric functions. It is defined as the reciprocal of the tangent function, which means it is equal to the ratio of the cosine of an angle to the sine of an angle. Mathematically, it can be expressed as:
Another interesting fact is that cotangent is closely related to tangent. You can express \( \cot x \) as \( \frac{1}{\tan x} \). This relationship highlights how trigonometric functions interconnect with one another, giving you different ways to handle problems requiring transformations or simplifications.
- \( \cot x = \frac{\cos x}{\sin x} \)
Another interesting fact is that cotangent is closely related to tangent. You can express \( \cot x \) as \( \frac{1}{\tan x} \). This relationship highlights how trigonometric functions interconnect with one another, giving you different ways to handle problems requiring transformations or simplifications.
Double Angle Formulas
Double angle formulas are key tools in trigonometry that simplify the expressions of trigonometric functions. They are trigonometric identities that involve the sine, cosine, and tangent of an angle that is twice another angle. These formulas are invaluable for solving many types of trigonometric problems.
- The formula for sine is: \( \sin 2x = 2 \sin x \cos x \).
- The formula for cosine is: \( \cos 2x = \cos^2 x - \sin^2 x \), which can also be written in other forms such as \( 2\cos^2 x - 1 \) or \( 1 - 2\sin^2 x \).
- The formula for tangent is: \( \tan 2x = \frac{2 \tan x}{1 - \tan^2 x} \).
Trigonometric Functions
Trigonometric functions are fundamental to trigonometry, a branch of mathematics that studies triangles and the relationships between their sides and angles. The six primary trigonometric functions are sine, cosine, tangent, cosecant, secant, and cotangent.Each function has a specific relationship with the angles and sides of a right triangle:
- Sine (\( \sin \theta \)): the ratio of the opposite side to the hypotenuse.
- Cosine (\( \cos \theta \)): the ratio of the adjacent side to the hypotenuse.
- Tangent (\( \tan \theta \)): the ratio of the opposite side to the adjacent side, or \( \frac{\sin \theta}{\cos \theta} \).
- Cotangent (\( \cot \theta \)): the reciprocal of the tangent, or \( \frac{\cos \theta}{\sin \theta} \).
- Secant (\( \sec \theta \)): the reciprocal of the cosine, or \( \frac{1}{\cos \theta} \).
- Cosecant (\( \csc \theta \)): the reciprocal of the sine, or \( \frac{1}{\sin \theta} \).
Other exercises in this chapter
Problem 7
Simplify each expression. $$ \frac{\tan \theta}{\sin \theta} $$
View solution Problem 8
Solve each equation for all values of \(\theta\) if \(\theta\) is measured in degrees. \(2 \cos ^{2} \theta+2=5 \cos \theta\)
View solution Problem 8
Simplify each expression. $$ \sin \theta\left(1+\cot ^{2} \theta\right) $$
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State the vertical shift, equation of the midline, amplitude, and period for each function. Then graph the function. $$ y=\sin \theta+0.25 $$
View solution