Problem 8
Question
Use properties of logarithms to expand logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \(\log _{9}\left(\frac{9}{x}\right)\)
Step-by-Step Solution
Verified Answer
The expanded logarithmic expression is: \(1 - \log_{9}(x)\)
1Step 1: Apply the Quotient Rule of Logarithms
The quotient rule states that \(\log _{b}(\frac{M}{N}) = \log _{b}M - \log _{b}N\). Use this rule to break down the given expression into: \(\log _{9}(9) - \log _{9}(x)\).
2Step 2: Evaluate Logarithm of Base to the Base
The logarithm base \(b\) of any number to the base \(b\) is 1, because \(b^1 = b\). Thus, \(\log _{9}(9) = 1\). Substitute this result into the expression from Step 1, yielding: \(1 - \log_{9}(x)\).
3Step 3: Finish
There are no further evaluation or expansions that can be made without more information on \(x\). With information about \(x\)'s value, one might potentially simplify further, but the final answer for our purposes is: \(1 - \log_{9}(x)\).
Key Concepts
Properties of LogarithmsQuotient RuleBase EvaluationLogarithmic Simplification
Properties of Logarithms
Logarithms have a set of rules that make it easier to work with them, especially when you're expanding or simplifying expressions. Understanding these properties is key to addressing logarithmic problems effectively. Here are the most commonly used:
- Product Rule: This rule states that the logarithm of a product, \(\log_b(M \times N) = \log_b(M) + \log_b(N)\), allows us to split products into separate terms added together.
- Quotient Rule: This is the opposite of the product rule, used when you're dealing with division. The logarithm of a quotient is \(\log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N)\), allowing the division to be expressed as a difference.
- Power Rule: If you have a power, this rule helps break it down: \(\log_b(M^n) = n \cdot \log_b(M)\).
Quotient Rule
The quotient rule is a fundamental property that is extremely useful for simplifying logarithmic expressions. It helps translate a division inside the log into a simple subtraction outside. In the exercise we examined,
- We began with the expression \(\log_{9}\left(\frac{9}{x}\right)\).
- By applying the quotient rule, we rewrote it as \(\log_{9}(9) - \log_{9}(x)\).
Base Evaluation
Evaluating a logarithm's base is about simplifying the expression using properties inherent to logarithms. A classic result in log base evaluation is that the log of a base itself is 1. This is because any number raised to the power of 1 is itself, a crucial fact in our example.
- In the given task, \(\log_{9}(9) = 1\) because when you raise 9 to the power of 1, you get 9.
- This fact is universally true for any base, simplifying expressions where a logarithm equals its base.
Logarithmic Simplification
Simplifying logarithmic expressions involves making them as concise as possible, often using known values and properties of logarithms. In our exercise, the last step yielded a final expression that was already as simplified as it could be without additional data about \(x\).
- We started with \(\log_{9}\left(\frac{9}{x}\right)\) and, through steps involving the quotient rule and base evaluation, reached the simplified form \(1 - \log_{9}(x)\).
- This transformation reduced the expression to the basics, substituting in known values like \(\log_{9}(9) = 1\).
- Further simplification depends on more information, such as the specific value of \(x\), which wasn't provided.
Other exercises in this chapter
Problem 7
Approximate each number using a calculator. Round your answer to three decimal places. $$e^{2.3}$$
View solution Problem 8
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$5^{3 x-1}=125$$
View solution Problem 8
Write each equation in its equivalent exponential form. $$\log _{5} 125=y$$
View solution Problem 8
Approximate each number using a calculator. Round your answer to three decimal places. $$e^{3.4}$$
View solution