Problem 8
Question
Use identities to find the exact value of each expression. Do not use a calculator. $$\sin \left(-\frac{5 \pi}{12}\right)$$
Step-by-Step Solution
Verified Answer
\( \sin\left(-\frac{5\pi}{12}\right) = \frac{-\sqrt{6} + \sqrt{2}}{4} \).
1Step 1: Identify the Identity to Use
To find the exact value of \( \sin(-\frac{5\pi}{12}) \), we utilize the sine angle addition identity because the angle \( -\frac{5\pi}{12} \) can be expressed as a sum or difference of angles with known sine values. The sine addition identity is: \( \sin(a + b) = \sin a \cos b + \cos a \sin b \).
2Step 2: Express the Angle
The angle \( -\frac{5\pi}{12} \) can be rewritten using known angles like: \( -\frac{5\pi}{12} = -\frac{\pi}{4} - \frac{\pi}{6} \). Both angles \( -\frac{\pi}{4} \) and \( -\frac{\pi}{6} \) have known sine and cosine values, which makes them suitable for use in the identity.
3Step 3: Apply the Sine Angle Addition Identity
Applying the identity for sine, we get:\[sin\left(-\frac{5\pi}{12}\right) = \sin\left(-\frac{\pi}{4} - \frac{\pi}{6}\right) = \sin\left(-\frac{\pi}{4}\right)\cos\left(-\frac{\pi}{6}\right) - \cos\left(-\frac{\pi}{4}\right)\sin\left(-\frac{\pi}{6}\right).\]
4Step 4: Substitute Known Values
Substitute the known values:- \( \sin\left(-\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2} \)- \( \cos\left(-\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2} \)- \( \cos\left(-\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} \)- \( \sin\left(-\frac{\pi}{6}\right) = -\frac{1}{2} \).These values convert the expression to:\[-\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \left(-\frac{1}{2}\right)\]
5Step 5: Simplify the Expression
Calculate the product in each term:\[-\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} = \frac{-\sqrt{6} + \sqrt{2}}{4}.\]
6Step 6: Conclusion
Thus, the exact value of \( \sin\left(-\frac{5\pi}{12}\right) \) is \( \frac{-\sqrt{6} + \sqrt{2}}{4} \).
Key Concepts
Sine Angle Addition IdentityExact Trigonometric ValuesSimplifying Expressions
Sine Angle Addition Identity
The Sine Angle Addition Identity is a fundamental tool in trigonometry. It helps us find the sine of an angle that can be expressed as the sum or difference of two other known angles. The identity is written as:
In the exercise, we applied the Sine Angle Addition Identity to \( \sin\left(-\frac{5\pi}{12}\right) \). By breaking down \( -\frac{5\pi}{12} \) into simpler angles like \( -\frac{\pi}{4} \) and \( -\frac{\pi}{6} \), both of which have known sine and cosine values, we were able to plug them into the identity, making our calculations more straightforward.
- \( \sin(a + b) = \sin a \cos b + \cos a \sin b \).
In the exercise, we applied the Sine Angle Addition Identity to \( \sin\left(-\frac{5\pi}{12}\right) \). By breaking down \( -\frac{5\pi}{12} \) into simpler angles like \( -\frac{\pi}{4} \) and \( -\frac{\pi}{6} \), both of which have known sine and cosine values, we were able to plug them into the identity, making our calculations more straightforward.
Exact Trigonometric Values
Trigonometric values such as sine and cosine are often memorized for standard angles like \(0\), \(\frac{\pi}{6}\), \(\frac{\pi}{4}\), \(\frac{\pi}{3}\), and \(\frac{\pi}{2}\). Knowing these values by heart simplifies the process when solving trigonometry problems.
For instance:
For instance:
- \( \sin\left(-\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2} \)
- \( \cos\left(-\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2} \)
- \( \cos\left(-\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} \)
- \( \sin\left(-\frac{\pi}{6}\right) = -\frac{1}{2} \)
Simplifying Expressions
Simplifying trigonometric expressions is an essential skill. It involves reducing complex mathematical expressions into a simpler, more digestible form.
In our exercise, after substituting known trigonometric values, we were left with the expression:
In our exercise, after substituting known trigonometric values, we were left with the expression:
- \(-\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \left(-\frac{1}{2}\right)\)
- \(-\frac{\sqrt{6}}{4}\) from the first term, and \(+ \frac{\sqrt{2}}{4}\) from the second term.
- \( \frac{-\sqrt{6} + \sqrt{2}}{4} \).
Other exercises in this chapter
Problem 8
Solve each equation for solutions over the interval \([0,2 \pi)\) by first solving for the trigonometric finction. Do not use a calculator. $$2 \sin x+3=4$$
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Solve each equation over the interval \([0,2 \pi)\) $$\cos x-1=\cos 2 x$$
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Write short answers and fill in the blanks. Consider the inverse tangent function, \(y=\tan ^{-1} x\) or \(y=\arctan x\) (a) What is its domain? (b) What is its
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