Problem 8
Question
Use a pattern to factor. Check. Identify any prime polynomials. $$ c^{2}-14 c+49 $$
Step-by-Step Solution
Verified Answer
\[ (c - 7)^2 \]
1Step 1 - Identify the quadratic form
Notice that the given polynomial is in the standard quadratic form: \[ c^2 - 14c + 49 \]
2Step 2 - Recognize the perfect square trinomial
To factor the polynomial, recognize it as a perfect square trinomial. A perfect square trinomial has the form \[ (a - b)^2 = a^2 - 2ab + b^2 \]. In this case, compare it with our expression \[ c^2 - 14c + 49 \].
3Step 3 - Identify 'a' and 'b'
Here, \[ a = c \] and \[ b = 7 \], so the polynomial can be written as: \[ c^2 - 2(7)(c) + 7^2 \]
4Step 4 - Factor the polynomial
Rewrite the polynomial as: \[ (c - 7)^2 \]
5Step 5 - Check the factorization
Expand \[ (c - 7)^2 \] to verify it matches the original polynomial: \[ (c - 7)(c - 7) = c^2 - 7c - 7c + 49 = c^2 - 14c + 49 \]
6Step 6 - Identify prime polynomials
Since we were able to factor the polynomial, it is not prime. Therefore, \[ c^2 - 14 c + 49 \] is not a prime polynomial.
Key Concepts
Perfect Square TrinomialQuadratic FormFactorization ProcessPrime Polynomials
Perfect Square Trinomial
A perfect square trinomial is a specific type of polynomial. It's created by squaring a binomial. This means it takes the form \((a - b)^2 = a^2 - 2ab + b^2\).
In our example, \(c^2 - 14c + 49\), we need to see if it fits this form.
Comparing it, we notice that:
In our example, \(c^2 - 14c + 49\), we need to see if it fits this form.
Comparing it, we notice that:
- \(a^2 = c^2\) means \(a = c\)
- \(-2ab = -14c\) leads us to find \(b = 7\)
- \(b^2 = 49\)
Quadratic Form
The quadratic form is a type of polynomial with three parts: \(ax^2 + bx + c\). It's called 'quadratic' because the highest degree of the variable (in this case, c) is squared.
In our example \(c^2 - 14c + 49\), it matches the standard quadratic form where:
In our example \(c^2 - 14c + 49\), it matches the standard quadratic form where:
- \(a = 1\)
- \(b = -14\)
- \(c = 49\)
Factorization Process
Factoring polynomials involves breaking them down into simpler pieces called 'factors'. If we recognize a pattern like a perfect square trinomial, factorization becomes easier.
Follow these basic steps to factor a polynomial like \(c^2 - 14c + 49\):
Follow these basic steps to factor a polynomial like \(c^2 - 14c + 49\):
- Identify the quadratic form.
- Recognize the perfect square trinomial by comparing it with \( (a - b)^2 \).
- Determine values for \(a\) and \(b\).
- Rewrite the polynomial as \((c - 7)^2 \).
Prime Polynomials
A prime polynomial cannot be factored into simpler polynomials with integer coefficients.
To determine if a polynomial is prime:
To determine if a polynomial is prime:
- Attempt to factor it.
- If it can be factored (like our example \(c^2 - 14c + 49 = (c - 7)^2\)), it is not prime.
- If no factorization is possible, it is a prime polynomial.
Other exercises in this chapter
Problem 8
Solve. $$ (h+2)(h-10)=0 $$
View solution Problem 8
Factor completely. Identify any prime polynomials. $$ 7 c^{2}+7 d^{2} $$
View solution Problem 8
Use the guess and check method to factor. Identify any prime polynomials. $$ a^{2}-4 a-21 $$
View solution Problem 9
Factor completely. Identify any prime polynomials. $$ 4 x^{2}+24 x+36 $$
View solution