Problem 8
Question
The labels have fallen off two bottles, one containing \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) and the other containing \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\). You have a bottle of dilute \(\mathrm{H}_{2} \mathrm{SO}_{4}\). How could you use it to test a portion of each solution to identify which solution is which? [Section 4.2]
Step-by-Step Solution
Verified Answer
To identify which solution is Mg(NO3)2 and which is Pb(NO3)2 using dilute H2SO4, take small samples from each unknown solution and add H2SO4 to each. Observe the reactions:
- If a white precipitate forms, the solution is Pb(NO3)2 (due to the formation of PbSO4).
- If the solution remains clear, the solution is Mg(NO3)2 (due to the formation of soluble MgSO4).
1Step 1: Write down the chemical reactions
When Mg(NO3)2 or Pb(NO3)2 reacts with H2SO4, the following reactions take place:
\[Mg(NO_3)_2 + H_2SO_4 \rightarrow MgSO_4 + 2HNO_3\]
and
\[Pb(NO_3)_2 + H_2SO_4 \rightarrow PbSO_4 + 2HNO_3\]
2Step 2: Determine the difference in the reaction products
The products of the reactions are MgSO4 and PbSO4. The key difference between MgSO4 and PbSO4 is their solubility in water. MgSO4 is soluble in water and forms a clear solution, while PbSO4 is not very soluble and forms a white precipitate.
3Step 3: Perform the test with dilute H2SO4
To identify which solution is which, follow these steps:
1. Take two small samples, one from each of the two unknown solutions.
2. Add a small amount of dilute H2SO4 to each sample.
3. Observe the reactions for any formation of precipitate.
4Step 4: Analyze the results
After adding dilute H2SO4:
- If a white precipitate is formed, the solution is Pb(NO3)2 (due to the formation of PbSO4).
- If the solution remains clear, the solution is Mg(NO3)2 (due to the formation of soluble MgSO4).
This way, you can identify which solution contains Mg(NO3)2 and which contains Pb(NO3)2.
Key Concepts
SolubilityPrecipitate FormationSolution Identification
Solubility
Solubility is a critical property of substances, especially when discussing chemical reactions involving solutions. It refers to a substance's ability to dissolve in a solvent, like water. Solubility is influenced by factors such as temperature, pressure, and the nature of both the solute and solvent.
In the context of the given exercise, understanding solubility helps differentiate between the two products formed during the reactions.
In the context of the given exercise, understanding solubility helps differentiate between the two products formed during the reactions.
- Magnesium sulfate ( MgSO_4 ) is highly soluble in water. As a result, when it forms during the reaction, it readily dissolves, leaving the solution clear.
- Lead sulfate ( PbSO_4 ), on the other hand, has low solubility in water. This means it does not dissolve easily, leading to the formation of a precipitate.
Precipitate Formation
Precipitation occurs when a solution reacts to form a solid, known as a precipitate. This is a crucial phenomenon in chemistry because it often indicates the formation of a new compound.
In this exercise, Pb(NO_3)_2 reacts with H_2SO_4 to form PbSO_4 , which is insoluble in water. As a result:
In this exercise, Pb(NO_3)_2 reacts with H_2SO_4 to form PbSO_4 , which is insoluble in water. As a result:
- PbSO_4 appears as a white solid precipitate in the reaction mixture.
- This solid formation suggests that the reaction mixture contains lead.
Solution Identification
Identifying solutions based on their chemical properties, such as solubility and precipitate formation, is a practical application of chemistry.
In the scenario given, using H_2SO_4 to distinguish between Mg(NO_3)_2 and Pb(NO_3)_2 depends on observing the reaction's outcome:
In the scenario given, using H_2SO_4 to distinguish between Mg(NO_3)_2 and Pb(NO_3)_2 depends on observing the reaction's outcome:
- If a white precipitate forms, the solution was Pb(NO_3)_2 , due to the creation of PbSO_4 , which is insoluble.
- If no precipitate forms and the solution remains clear, the solution was Mg(NO_3)_2 because MgSO_4 is soluble.
Other exercises in this chapter
Problem 6
We have seen that ions in aqueous solution are stabilized by the attractions between the ions and the water molecules. Why then do some pairs of ions in solutio
View solution Problem 7
Which of the following ions will always be a spectator ion in a precipitation reaction? (a) Cl", (b) \(\mathrm{NO}_{3}^{-}\), (c) \(\mathrm{NH}_{4}^{+},(\mathrm
View solution Problem 9
Explain how a redox reaction involves electrons in the same way that an acid- base reaction involves protons. [Sections \(4.3\) and \(4.4]\)
View solution Problem 12
When methanol, \(\mathrm{CH}_{3} \mathrm{OH}\), is dissolved in water, a nonconducting solution results. When acetic acid, \(\mathrm{CH}_{3} \mathrm{COOH}\), di
View solution